I try upload a file to an FTP-server with C#. The file is uploaded but with zero bytes.
private void button2_Click(object sender, EventArgs e)
{
var dirPath = #"C:/Documents and Settings/sander.GD/Bureaublad/test/";
ftp ftpClient = new ftp("ftp://example.com/", "username", "password");
string[] files = Directory.GetFiles(dirPath,"*.*");
var uploadPath = "/httpdocs/album";
foreach (string file in files)
{
ftpClient.createDirectory("/test");
ftpClient.upload(uploadPath + "/" + Path.GetFileName(file), file);
}
if (string.IsNullOrEmpty(txtnaam.Text))
{
MessageBox.Show("Gelieve uw naam in te geven !");
}
}
The existing answers are valid, but why re-invent the wheel and bother with lower level WebRequest types while WebClient already implements FTP uploading neatly:
using (var client = new WebClient())
{
client.Credentials = new NetworkCredential(ftpUsername, ftpPassword);
client.UploadFile("ftp://host/path.zip", WebRequestMethods.Ftp.UploadFile, localFile);
}
Easiest way
The most trivial way to upload a file to an FTP server using .NET framework is using WebClient.UploadFile method:
WebClient client = new WebClient();
client.Credentials = new NetworkCredential("username", "password");
var url = "ftp://ftp.example.com/remote/path/file.zip";
client.UploadFile(url, #"C:\local\path\file.zip");
Advanced options
If you need a greater control, that WebClient does not offer (like TLS/SSL encryption, ascii/text transfer mode, active mode, transfer resuming, progress monitoring, etc), use FtpWebRequest. Easy way is to just copy a FileStream to an FTP stream using Stream.CopyTo:
var url = "ftp://ftp.example.com/remote/path/file.zip";
FtpWebRequest request = (FtpWebRequest)WebRequest.Create(url);
request.Credentials = new NetworkCredential("username", "password");
request.Method = WebRequestMethods.Ftp.UploadFile;
using (Stream fileStream = File.OpenRead(#"C:\local\path\file.zip"))
using (Stream ftpStream = request.GetRequestStream())
{
fileStream.CopyTo(ftpStream);
}
Progress monitoring
If you need to monitor an upload progress, you have to copy the contents by chunks yourself:
var url = "ftp://ftp.example.com/remote/path/file.zip";
FtpWebRequest request = (FtpWebRequest)WebRequest.Create(url);
request.Credentials = new NetworkCredential("username", "password");
request.Method = WebRequestMethods.Ftp.UploadFile;
using (Stream fileStream = File.OpenRead(#"C:\local\path\file.zip"))
using (Stream ftpStream = request.GetRequestStream())
{
byte[] buffer = new byte[10240];
int read;
while ((read = fileStream.Read(buffer, 0, buffer.Length)) > 0)
{
ftpStream.Write(buffer, 0, read);
Console.WriteLine("Uploaded {0} bytes", fileStream.Position);
}
}
For GUI progress (WinForms ProgressBar), see C# example at:
How can we show progress bar for upload with FtpWebRequest
Uploading folder
If you want to upload all files from a folder, see
Upload directory of files to FTP server using WebClient.
For a recursive upload, see
Recursive upload to FTP server in C#
.NET 5 Guide
async Task<FtpStatusCode> FtpFileUploadAsync(string ftpUrl, string userName, string password, string filePath)
{
FtpWebRequest request = (FtpWebRequest)WebRequest.Create(ftpUrl);
request.Method = WebRequestMethods.Ftp.UploadFile;
request.Credentials = new NetworkCredential(userName, password);
using (FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read))
using (Stream requestStream = request.GetRequestStream())
{
await fileStream.CopyToAsync(requestStream);
}
using (FtpWebResponse response = (FtpWebResponse)await request.GetResponseAsync())
{
return response.StatusCode;
}
}
.NET Framework
public void UploadFtpFile(string folderName, string fileName)
{
FtpWebRequest request;
string folderName;
string fileName;
string absoluteFileName = Path.GetFileName(fileName);
request = WebRequest.Create(new Uri(string.Format(#"ftp://{0}/{1}/{2}", "127.0.0.1", folderName, absoluteFileName))) as FtpWebRequest;
request.Method = WebRequestMethods.Ftp.UploadFile;
request.UseBinary = 1;
request.UsePassive = 1;
request.KeepAlive = 1;
request.Credentials = new NetworkCredential(user, pass);
request.ConnectionGroupName = "group";
using (FileStream fs = File.OpenRead(fileName))
{
byte[] buffer = new byte[fs.Length];
fs.Read(buffer, 0, buffer.Length);
fs.Close();
Stream requestStream = request.GetRequestStream();
requestStream.Write(buffer, 0, buffer.Length);
requestStream.Flush();
requestStream.Close();
}
}
How to use
UploadFtpFile("testFolder", "E:\\filesToUpload\\test.img");
use this in your foreach
and you only need to create folder one time
to create a folder
request = WebRequest.Create(new Uri(string.Format(#"ftp://{0}/{1}/", "127.0.0.1", "testFolder"))) as FtpWebRequest;
request.Method = WebRequestMethods.Ftp.MakeDirectory;
FtpWebResponse ftpResponse = (FtpWebResponse)request.GetResponse();
The following works for me:
public virtual void Send(string fileName, byte[] file)
{
ByteArrayToFile(fileName, file);
var request = (FtpWebRequest) WebRequest.Create(new Uri(ServerUrl + fileName));
request.Method = WebRequestMethods.Ftp.UploadFile;
request.UsePassive = false;
request.Credentials = new NetworkCredential(UserName, Password);
request.ContentLength = file.Length;
var requestStream = request.GetRequestStream();
requestStream.Write(file, 0, file.Length);
requestStream.Close();
var response = (FtpWebResponse) request.GetResponse();
if (response != null)
response.Close();
}
You can't read send the file parameter in your code as it is only the filename.
Use the following:
byte[] bytes = File.ReadAllBytes(dir + file);
To get the file so you can pass it to the Send method.
public static void UploadFileToFtp(string url, string filePath, string username, string password)
{
var fileName = Path.GetFileName(filePath);
var request = (FtpWebRequest)WebRequest.Create(url + fileName);
request.Method = WebRequestMethods.Ftp.UploadFile;
request.Credentials = new NetworkCredential(username, password);
request.UsePassive = true;
request.UseBinary = true;
request.KeepAlive = false;
using (var fileStream = File.OpenRead(filePath))
{
using (var requestStream = request.GetRequestStream())
{
fileStream.CopyTo(requestStream);
requestStream.Close();
}
}
var response = (FtpWebResponse)request.GetResponse();
Console.WriteLine("Upload done: {0}", response.StatusDescription);
response.Close();
}
In the first example must change those to:
requestStream.Flush();
requestStream.Close();
First flush and after that close.
This works for me,this method will SFTP a file to a location within your network.
It uses SSH.NET.2013.4.7 library.One can just download it for free.
//Secure FTP
public void SecureFTPUploadFile(string destinationHost,int port,string username,string password,string source,string destination)
{
ConnectionInfo ConnNfo = new ConnectionInfo(destinationHost, port, username, new PasswordAuthenticationMethod(username, password));
var temp = destination.Split('/');
string destinationFileName = temp[temp.Count() - 1];
string parentDirectory = destination.Remove(destination.Length - (destinationFileName.Length + 1), destinationFileName.Length + 1);
using (var sshclient = new SshClient(ConnNfo))
{
sshclient.Connect();
using (var cmd = sshclient.CreateCommand("mkdir -p " + parentDirectory + " && chmod +rw " + parentDirectory))
{
cmd.Execute();
}
sshclient.Disconnect();
}
using (var sftp = new SftpClient(ConnNfo))
{
sftp.Connect();
sftp.ChangeDirectory(parentDirectory);
using (var uplfileStream = System.IO.File.OpenRead(source))
{
sftp.UploadFile(uplfileStream, destinationFileName, true);
}
sftp.Disconnect();
}
}
publish date: 06/26/2018
https://learn.microsoft.com/en-us/dotnet/framework/network-programming/how-to-upload-files-with-ftp
using System;
using System.IO;
using System.Net;
using System.Text;
namespace Examples.System.Net
{
public class WebRequestGetExample
{
public static void Main ()
{
// Get the object used to communicate with the server.
FtpWebRequest request =
(FtpWebRequest)WebRequest.Create("ftp://www.contoso.com/test.htm");
request.Method = WebRequestMethods.Ftp.UploadFile;
// This example assumes the FTP site uses anonymous logon.
request.Credentials = new NetworkCredential("anonymous",
"janeDoe#contoso.com");
// Copy the contents of the file to the request stream.
byte[] fileContents;
using (StreamReader sourceStream = new StreamReader("testfile.txt"))
{
fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd());
}
request.ContentLength = fileContents.Length;
using (Stream requestStream = request.GetRequestStream())
{
requestStream.Write(fileContents, 0, fileContents.Length);
}
using (FtpWebResponse response = (FtpWebResponse)request.GetResponse())
{
Console.WriteLine($"Upload File Complete, status
{response.StatusDescription}");
}
}
}
}
Best way I've found is FluentFtp
You can find the repo here:
https://github.com/robinrodricks/FluentFTP
and the quickstart example here:
https://github.com/robinrodricks/FluentFTP/wiki/Quick-Start-Example.
And actually the WebRequest class recommended by a few people here, is not recommended by Microsoft anymore, check out this page:
https://learn.microsoft.com/en-us/dotnet/api/system.net.webrequest?view=net-5.0
// create an FTP client and specify the host, username and password
// (delete the credentials to use the "anonymous" account)
FtpClient client = new FtpClient("123.123.123.123", "david", "pass123");
// connect to the server and automatically detect working FTP settings
client.AutoConnect();
// upload a file and retry 3 times before giving up
client.RetryAttempts = 3;
client.UploadFile(#"C:\MyVideo.mp4", "/htdocs/big.txt",
FtpRemoteExists.Overwrite, false, FtpVerify.Retry);
// disconnect! good bye!
client.Disconnect();
I have observed that -
FtpwebRequest is missing.
As the target is FTP, so the NetworkCredential required.
I have prepared a method that works like this, you can replace the value of the variable ftpurl with the parameter TargetDestinationPath. I had tested this method on winforms application :
private void UploadProfileImage(string TargetFileName, string TargetDestinationPath, string FiletoUpload)
{
//Get the Image Destination path
string imageName = TargetFileName; //you can comment this
string imgPath = TargetDestinationPath;
string ftpurl = "ftp://downloads.abc.com/downloads.abc.com/MobileApps/SystemImages/ProfileImages/" + imgPath;
string ftpusername = krayknot_DAL.clsGlobal.FTPUsername;
string ftppassword = krayknot_DAL.clsGlobal.FTPPassword;
string fileurl = FiletoUpload;
FtpWebRequest ftpClient = (FtpWebRequest)FtpWebRequest.Create(ftpurl);
ftpClient.Credentials = new System.Net.NetworkCredential(ftpusername, ftppassword);
ftpClient.Method = System.Net.WebRequestMethods.Ftp.UploadFile;
ftpClient.UseBinary = true;
ftpClient.KeepAlive = true;
System.IO.FileInfo fi = new System.IO.FileInfo(fileurl);
ftpClient.ContentLength = fi.Length;
byte[] buffer = new byte[4097];
int bytes = 0;
int total_bytes = (int)fi.Length;
System.IO.FileStream fs = fi.OpenRead();
System.IO.Stream rs = ftpClient.GetRequestStream();
while (total_bytes > 0)
{
bytes = fs.Read(buffer, 0, buffer.Length);
rs.Write(buffer, 0, bytes);
total_bytes = total_bytes - bytes;
}
//fs.Flush();
fs.Close();
rs.Close();
FtpWebResponse uploadResponse = (FtpWebResponse)ftpClient.GetResponse();
string value = uploadResponse.StatusDescription;
uploadResponse.Close();
}
Let me know in case of any issue, or here is one more link that can help you:
https://msdn.microsoft.com/en-us/library/ms229715(v=vs.110).aspx
I have an http POST being actioned via a .NET System.Net.WebRequest as follows:
...
XXXUtilities.Log.WriteLog(string.Format("XXXHTTPPost PostToUri has uri={0}, body={1}", uri, messageBodyAsString));
System.Net.WebRequest req = System.Net.WebRequest.Create(uri);
req.ContentType = "application/x-www-form-urlencoded";
req.Method = "POST";
byte[] bytes = System.Text.Encoding.ASCII.GetBytes(messageBodyAsString);
req.ContentLength = bytes.Length;
System.IO.Stream os = req.GetRequestStream();
os.Write(bytes, 0, bytes.Length);
os.Close();
try
{
using (System.Net.WebResponse resp = req.GetResponse())
{
if (resp == null) return null;
System.IO.StreamReader sr =
new System.IO.StreamReader(resp.GetResponseStream());
string rs = sr.ReadToEnd().Trim();
sr.Close();
resp.Close();
XXXUtilities.Log.WriteLog(string.Format("XXXHTTPPost PostToUri has string response = {0}", rs));
MongoDB.Bson.BsonDocument doc2 = new BsonDocument();
doc2.Add("Response", rs);
return doc2;
}
}
catch (System.Net.WebException e)
{...
This all works fine most of the time. However, looking at the log files that this creates I spotted something strange. The suspect log entries look like this:
18:59:17.0608 HPSHTTPPost PostToUri has uri=https://salesforce.ringlead.com/cgi-bin/2848/3/dedup.pl, body=LastName=Doe&FirstName=Jon
18:59:17.5608 HPSHTTPPost PostToUri has string response = Success
18:59:18.0295 HPSHTTPPost PostToUri has string response = Success
It seems that the Http Response is being received twice. Is this even technically possible? i.e. is it possible for an Http POST to receive two Responses, one after the other? If so, is my code below then liable to be called twice, thus resulting in the observed log file entries? Many thanks.
Edit:
In response to the comment that the logging code may be broken, here is the logging code:
public class Log
{
public static void WriteLog(string commandText)
{
string clientDBName = "test";
string username = "test";
try
{
string filePath = "c:\\Data\\XXXLogs\\" + clientDBName + "logs\\";
string filename = System.DateTime.Now.ToString("yyyyMMdd_") + username + ".log";
DirectoryInfo dir = new DirectoryInfo(filePath);
if (!dir.Exists)
{
dir.Create();
}
System.IO.FileStream stream = new System.IO.FileStream(
filePath + filename
, System.IO.FileMode.Append); // Will create if not already exists
StreamWriter writer = new StreamWriter(stream);
writer.WriteLine(); // Writes a line terminator, thus separating entries by 1 blank line
writer.WriteLine(System.DateTime.Now.ToString("HH:mm:ss.ffff") + " " + commandText);
writer.Flush();
stream.Close();
}
catch { }
}
}
This is my jsp we are calling an java method
<%
PDFFileUploader.generatePDcFile(); //Calls the PDF method;
%>
This is my PDFFileUploader code
public class PDFFileUploader {
static final String UPLOAD_URL = "http://localhost:7080/pdf/GetPDFFile";
static final int BUFFER_SIZE = 4096;
public static void generatePDcFile() throws IOException
{
System.out.println("Inside generatePDC File");
// takes file path from first program's argument
String filePath = "H:/report1.pdf";
File uploadFile = new File("H:/report1.pdf");
System.out.println("File to upload: " + filePath);
// creates a HTTP connection
URL url = new URL(UPLOAD_URL);
HttpURLConnection httpConn = (HttpURLConnection) url.openConnection();
httpConn.setUseCaches(false);
httpConn.setDoOutput(true);
httpConn.setRequestMethod("POST");
// sets file name as a HTTP header
httpConn.setRequestProperty("fileName", uploadFile.getName());
// opens output stream of the HTTP connection for writing data
OutputStream outputStream = httpConn.getOutputStream();
// Opens input stream of the file for reading data
FileInputStream inputStream = new FileInputStream(uploadFile);
byte[] buffer = new byte[BUFFER_SIZE];
int bytesRead = -1;
System.out.println("Start writing data...");
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
System.out.println("Data was written.");
outputStream.close();
inputStream.close();
//Read pdc file
//FileOutputStream test = new FileOutputStream("test");
// always check HTTP response code from server
InputStream test = null;
File pdcFile = new File("H:/report123.pdf");
FileOutputStream outputStreamTest = new FileOutputStream(pdcFile);
//byte[] bufferTest = new byte[BUFFER_SIZE];
//int bytesReadTest = -1;
//final OutputStream ostream = new FileOutputStream("/tmp/data.pdc");
int responseCode = httpConn.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
// reads server's response
/* BufferedReader reader = new BufferedReader(new InputStreamReader(
httpConn.getInputStream()));*/
test = httpConn.getInputStream();
String message= httpConn.getResponseMessage();
System.out.println("Message is///"+message);
System.out.println("Header :: "+httpConn.getHeaderField(0));
final byte[] bufferTest = new byte[1024*14];
while (true) {
int len = test.read(bufferTest);
if (len <= 0) {
break;
}
outputStreamTest.write(bufferTest, 0, len);
}
outputStreamTest.close();
test.close();
String fileName = "";
String disposition = httpConn.getHeaderField("Content-Disposition");
// extracts file name from header field
int index = disposition.indexOf("filename=");
if (index > 0) {
fileName = disposition.substring(index + 10,
disposition.length() - 1);
}
System.out.println("Get File Name"+fileName);
/* Map<String, List<String>> map = httpConn.getHeaderFields();
for (Map.Entry<String, List<String>> entry : map.entrySet()) {
System.out.println("Key : " + entry.getKey() +
" ,Value : " + entry.getValue());
}*/
// String response = reader.readLine();
//System.out.println("Server's response: " + response);
} else {
System.out.println("Server returned non-OK code: " + responseCode);
}
}
from here a servlet is called through the URL provided above the code for doPost method for the getPDFFile Servlet is
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
// Gets file name for HTTP header
String fileName = request.getHeader("fileName");
File saveFile = new File(SAVE_DIR + fileName);
// prints out all header values
System.out.println("===== Begin headers =====");
Enumeration<String> names = request.getHeaderNames();
while (names.hasMoreElements()) {
String headerName = names.nextElement();
System.out.println(headerName + " = " + request.getHeader(headerName));
}
System.out.println("===== End headers =====\n");
// opens input stream of the request for reading data
InputStream inputStream = request.getInputStream();
// opens an output stream for writing file
/*FileOutputStream outputStream = new FileOutputStream(saveFile);*/
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
byte[] buffer = new byte[BUFFER_SIZE];
int bytesRead = -1;
System.out.println("Receiving data...");
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
System.out.println("Data received.");
outputStream.close();
inputStream.close();
System.out.println("File written to: " + saveFile.getAbsolutePath());
int processStatus = 0;
//temp file (used for conversion)
/* boolean success = (new File
(saveFile.getAbsolutePath())).delete();
System.out.println("File deleted :: "+success);
//delete pdc file too
boolean successtemp = (new File
(recentlyConvertedFile.getAbsolutePath())).delete();
System.out.println("File deleted :: "+successtemp);*/
response.setContentType("application/octet-stream" );
response.setHeader("Content-Disposition","inline;filename=\"" + saveFile.getName() + "\"");
response.setContentLength((int) saveFile.length());
OutputStream os = response.getOutputStream();
FileInputStream fis = new FileInputStream(saveFile);
//op.write(response.toString().getBytes(Charset.forName("utf-8")));
//op.flush();
try {
int byteRead = 0;
while ((byteRead = fis.read()) != -1) {
os.write(buffer, 0, byteRead);
}
os.flush();
} catch (Exception excp) {
excp.printStackTrace();
} finally {
os.close();
fis.close();
}
// sends response to client
//response.getWriter().print("UPLOAD DONE");
}
The file is getting downloaded but not opening the generated pdf have the same size of the original and I have taken a text file and printed the content to another file it seems to read only first line of the text file taken as input
Your final loop returning a file from the servlet to the client looks like this:
while ((byteRead = fis.read()) != -1) {
os.write(buffer, 0, byteRead);
}
You seem to have forgotten to use buffer in the fis.read() which should look like this:
while ((byteRead = fis.read(buffer)) != -1) {
os.write(buffer, 0, byteRead);
}
Thus, you send back as many copies of the buffer contents as fis returns numbers != -1.
BTW: Your servlet puts the data it receives into the ByteArrayOutputStream outputStream and drops that, but it claims to have written them into the file it eventually attempts to return to the caller.
I'm trying to set up a web api service that searches for a .pdf file in a directory and returns the file if it's found.
The controller
public class ProductsController : ApiController
{
[HttpPost]
public HttpResponseMessage Post([FromBody]string certificateId)
{
string fileName = certificateId + ".pdf";
var path = #"C:\Certificates\20487A" + fileName;
//check the directory for pdf matching the certid
if (File.Exists(path))
{
//if there is a match then return the file
HttpResponseMessage result = new HttpResponseMessage(HttpStatusCode.OK);
var stream = new FileStream(path, FileMode.Open);
stream.Position = 0;
result.Content = new StreamContent(stream);
result.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment") { FileName = fileName };
result.Content.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("application/pdf");
result.Content.Headers.ContentDisposition.FileName = fileName;
return result;
}
else
{
HttpResponseMessage result = new HttpResponseMessage(HttpStatusCode.Gone);
return result;
}
}
}
I'm calling the service with the following code
private void GetCertQueryResponse(string url, string serial)
{
string encodedParameters = "certificateId=" + serial.Replace(" ", "");
HttpWebRequest httpRequest = (HttpWebRequest)WebRequest.Create(url);
httpRequest.Method = "POST";
httpRequest.ContentType = "application/x-www-form-urlencoded";
httpRequest.AllowAutoRedirect = false;
byte[] bytedata = Encoding.UTF8.GetBytes(encodedParameters);
httpRequest.ContentLength = bytedata.Length;
Stream requestStream = httpRequest.GetRequestStream();
requestStream.Write(bytedata, 0, bytedata.Length);
requestStream.Close();
HttpWebResponse response = (HttpWebResponse)httpRequest.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
byte[] bytes = null;
using (Stream stream = response.GetResponseStream())
using (MemoryStream ms = new MemoryStream())
{
int count = 0;
do
{
byte[] buf = new byte[1024];
count = stream.Read(buf, 0, 1024);
ms.Write(buf, 0, count);
} while (stream.CanRead && count > 0);
ms.Position = 0;
bytes = ms.ToArray();
}
var filename = serial + ".pdf";
Response.ContentType = "application/pdf";
Response.Headers.Add("Content-Disposition", "attachment; filename=\"" + filename + "\"");
Response.BinaryWrite(bytes);
}
}
This appears to be working in the sense that the download file dialogue is shown with the correct file name and size etc, but the download takes only a couple of seconds (when the file sizes are >30mb) and the files are corrupt when I try to open them.
Any ideas what I'm doing wrong?
Your code looks similar to what Ive used in the past, but below is what I typically use:
Response.AddHeader("content-length", myfile.Length.ToString())
Response.AddHeader("content-disposition", "inline; filename=MyFilename")
Response.AddHeader("Expires", "0")
Response.AddHeader("Pragma", "Cache")
Response.AddHeader("Cache-Control", "private")
Response.ContentType = "application/pdf"
Response.BinaryWrite(finalForm)
I post this for 2 reasons. One, add the content-length header, you may have to indicate how large the file is so the application waits for the whole response.
If that doesn't fix it. Set a breakpoint, does the byte array content the appropriate length (aka, 30 million bytes for a 30 MB file)? Have you used fiddler to see how much content is coming back over the HTTP call?
private byte[] BytesFromString(string str)
{
return Encoding.ASCII.GetBytes(str);
}
private int GetResponseCode(string ResponseString)
{
return int.Parse(ResponseString.Substring(0, 3));
}
protected void Button1_Click(object sender, EventArgs e)
{
TcpClient tClient = new TcpClient("plus.smtp.mail.yahoo.com", 465);
string CRLF = "\r\n";
byte[] dataBuffer;
string ResponseString;
NetworkStream netStream = tClient.GetStream();
StreamReader reader = new StreamReader(netStream);
ResponseString = reader.ReadLine();
dataBuffer = BytesFromString("HELO " + CRLF);
netStream.Write(dataBuffer, 0, dataBuffer.Length);
ResponseString = reader.ReadLine();
dataBuffer = BytesFromString("MAIL FROM:<myemail#yahoo.com>" + CRLF);
netStream.Write(dataBuffer, 0, dataBuffer.Length);
ResponseString = reader.ReadLine();
dataBuffer = BytesFromString("RCPT TO:<" + TextBox1.Text.Trim() + ">" + CRLF);
netStream.Write(dataBuffer, 0, dataBuffer.Length);
ResponseString = reader.ReadLine();
if (GetResponseCode(ResponseString) == 550)
{
Response.Write("Mai Address Does not Exist !");
}
dataBuffer = BytesFromString("QUITE" + CRLF);
netStream.Write(dataBuffer, 0, dataBuffer.Length);
tClient.Close();
}
Hi, this code does not work with smtp yahoo server but code work with gmail smtp server TcpClient tClient = new TcpClient("gmail-smtp-in.l.google.com", 25)
error:An established connection was aborted by the software in your host machine in line Response String = reader.ReadLine();
and change port server to 25 not happen!
Whether smtp server and port server is valid?
Is there a way to make sure of is email valid?
someone could help me?
Some Server machine used to algorithm for responsing to fetch data from it's particular server than that machine can't responding.....
but as you say gmail provide data therefore that machine can't use any restriction for responding data......