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I am trying to do some dynamic programming based on the number of characters in a sentence. Which letter of the English alphabet takes up the most pixels on the screen?
Hmm, let's see:
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
cccccccccccccccccccccccccccccccccccccccc
dddddddddddddddddddddddddddddddddddddddd
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
ffffffffffffffffffffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggggggg
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
llllllllllllllllllllllllllllllllllllllll
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
oooooooooooooooooooooooooooooooooooooooo
pppppppppppppppppppppppppppppppppppppppp
qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq
rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
ssssssssssssssssssssssssssssssssssssssss
tttttttttttttttttttttttttttttttttttttttt
uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
GGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG
HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
IIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL
MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
QQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQ
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
TTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU
VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
WWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
W wins.
Of course, this is a silly empirical experiment. There is no single answer to which letter is widest. It depends on the font. So you'll have to do a similar empirical experiment to figure out the answer for your environment. But the fact is, most fonts follow the same conventions, and capital W will be the widest.
Gist with these character widths in a ratio form (W = 100) captured here using this particular example font:
https://gist.github.com/imaurer/d330e68e70180c985b380f25e195b90c
Further to Ned Batchelder's awesomely practical answer, because I came here wondering about digits:
0000000000000000000000000000000000000000
1111111111111111111111111111111111111111
2222222222222222222222222222222222222222
3333333333333333333333333333333333333333
4444444444444444444444444444444444444444
5555555555555555555555555555555555555555
6666666666666666666666666666666666666666
7777777777777777777777777777777777777777
8888888888888888888888888888888888888888
9999999999999999999999999999999999999999
How about a programmatic solution?
var capsIndex = 65;
var smallIndex = 97
var div = document.createElement('div');
div.style.float = 'left';
document.body.appendChild(div);
var highestWidth = 0;
var elem;
for(var i = capsIndex; i < capsIndex + 26; i++) {
div.innerText = String.fromCharCode(i);
var computedWidth = window.getComputedStyle(div, null).getPropertyValue("width");
if(highestWidth < parseFloat(computedWidth)) {
highestWidth = parseFloat(computedWidth);
elem = String.fromCharCode(i);
}
}
for(var i = smallIndex; i < smallIndex + 26; i++) {
div.innerText = String.fromCharCode(i);
var computedWidth = window.getComputedStyle(div, null).getPropertyValue("width");
if(highestWidth < parseFloat(computedWidth)) {
highestWidth = parseFloat(computedWidth);
elem = String.fromCharCode(i);
}
}
div.innerHTML = '<b>' + elem + '</b>' + ' won';
Capital "M" is conventionally the widest.
I believe the letter W is the widest.
It also depends on the font. I did this 1 or 2 years ago with Processing and Helvetica and it is ILJTYFVCPAXUZKHSEDORGNBQMW in order of increasing pixels. The idea is to draw the text on a canvas with the font you are looking at, count the pixels, then sort with a HashMap or Dictionary.
Of course, this might not be directly relavant to your use as this calculates pixel area rather than just width. Might be a little overkill too.
void setup() {
size(30,30);
HashMap hm = new HashMap();
fill(255);
PFont font = loadFont("Helvetica-20.vlw");
textFont(font,20);
textAlign(CENTER);
for (int i=65; i<91; i++) {
background(0);
text(char(i),width/2,height-(textDescent()+textAscent())/2);
loadPixels();
int white=0;
for (int k=0; k<pixels.length; k++) {
white+=red(pixels[k]);
}
hm.put(char(i),white);
}
HashMap sorted = getSortedMap(hm);
String asciiString = new String();
for (Iterator<Map.Entry> i = sorted.entrySet().iterator(); i.hasNext();) {
Map.Entry me = (Map.Entry)i.next();
asciiString += me.getKey();
}
println(asciiString); //the string in ascending pixel order
}
public HashMap getSortedMap(HashMap hmap) {
HashMap map = new LinkedHashMap();
List mapKeys = new ArrayList(hmap.keySet());
List mapValues = new ArrayList(hmap.values());
TreeSet sortedSet = new TreeSet(mapValues);
Object[] sortedArray = sortedSet.toArray();
int size = sortedArray.length;
// a) Ascending sort
for (int i=0; i<size; i++) {
map.put(mapKeys.get(mapValues.indexOf(sortedArray[i])), sortedArray[i]);
}
return map;
}
Depending on your platform, there might be a way to "getWidth" from a string or DrawText() function somehow with a width property.
I would make a simple algortime that utilized the needed font and then ran through the alfabet and stored it in a small config or just calculated it at initialization as a loop from A to Z isnt that hard.
Arial 30px in Chrome - W wins.
A solution to calculate the widths of fonts a bit like the solution posted by xxx was posted by Alex Michael on his blog (which funnily enough linked me here).
Summary:
For Helvetica, the top three letters are: M (2493 pixels), W (2414) and B (1909).
For a set of fonts that shipped with his Mac, the results are more or less the same: M (2217.51 ± 945.19), W (2139.06 ± 945.29) and B (1841.38 ± 685.26).
Original Post: http://alexmic.net/letter-pixel-count/
Code:
# -*- coding: utf-8 -*-
from __future__ import division
import os
from collections import defaultdict
from math import sqrt
from PIL import Image, ImageDraw, ImageFont
# Make a lowercase + uppercase alphabet.
alphabet = 'abcdefghijklmnopqrstuvwxyz'
alphabet += ''.join(map(str.upper, alphabet))
def draw_letter(letter, font, save=True):
img = Image.new('RGB', (100, 100), 'white')
draw = ImageDraw.Draw(img)
draw.text((0,0), letter, font=font, fill='#000000')
if save:
img.save("imgs/{}.png".format(letter), 'PNG')
return img
def count_black_pixels(img):
pixels = list(img.getdata())
return len(filter(lambda rgb: sum(rgb) == 0, pixels))
def available_fonts():
fontdir = '/Users/alex/Desktop/English'
for root, dirs, filenames in os.walk(fontdir):
for name in filenames:
path = os.path.join(root, name)
try:
yield ImageFont.truetype(path, 100)
except IOError:
pass
def letter_statistics(counts):
for letter, counts in sorted(counts.iteritems()):
n = len(counts)
mean = sum(counts) / n
sd = sqrt(sum((x - mean) ** 2 for x in counts) / n)
yield letter, mean, sd
def main():
counts = defaultdict(list)
for letter in alphabet:
for font in available_fonts():
img = draw_letter(letter, font, save=False)
count = count_black_pixels(img)
counts[letter].append(count)
for letter, mean, sd in letter_statistics(counts):
print u"{0}: {1:.2f} ± {2:.2f}".format(letter, mean, sd)
if __name__ == '__main__':
main()
I know the accepted answer here is W, W is for WIN.
However, in this case, W is also for Width. The case study used employed a simple width test to examine pixels, but it was only the width, not the total pixel count. As an easy counter example, the accepted answer assumes that O and Q take up the same amount of pixels, yet they only take up the same amount of space.
Thus, W takes up the most space. But, is it all the pixels it's cracked up to be?
Let's get some empirical data. I created imgur images from the following B, M and W. I then analyzed their pixel count (see below), here are the results:
B : 114 pixels
M : 150 pixels
W : 157 pixels
Here is how I fed them into canvas and analyzed the raw pixel data from the images.
var imgs = {
B : "//i.imgur.com/YOuEPOn.png",
M : "//i.imgur.com/Aev3ZKQ.png",
W : "//i.imgur.com/xSUwE7w.png"
};
window.onload = function(){
for(var key in imgs){(function(img,key){
var Out = document.querySelector("#"+key+"Out");
img.crossOrigin = "Anonymous";
img.src=imgs[key];
img.onload = function() {
var canvas = document.querySelector('#'+key);
(canvas.width = img.width,canvas.height = img.height);
var context = canvas.getContext('2d');
context.drawImage(img, 0, 0);
var data = context.getImageData(0, 0, img.width, img.height).data;
Out.innerHTML = "Total Pixels: " + data.length/4 + "<br>";
var pixelObject = {};
for(var i = 0; i < data.length; i += 4){
var rgba = "rgba("+data[i]+","+data[i+1]+","+data[i+2]+","+data[i+3]+")";
pixelObject[rgba] = pixelObject[rgba] ? pixelObject[rgba]+1 : 1;
}
Out.innerHTML += "Total Whitespace: " + pixelObject["rgba(255,255,255,255)"] + "<br>";
Out.innerHTML += "Total Pixels In "+ key +": " + ((data.length/4)-pixelObject["rgba(255,255,255,255)"]) + "<br>";
};
})(new Image(),key)}
};
<table>
<tr>
<td>
<canvas id="B" width="100%" height="100%"></canvas>
</td>
<td id="BOut">
</td>
</tr>
<tr>
<td>
<canvas id="M" width="100%" height="100%"></canvas>
</td>
<td id="MOut">
</td>
</tr>
<tr>
<td>
<canvas id="W" width="100%" height="100%"></canvas>
</td>
<td id="WOut">
</td>
</tr>
</table>
Want to know the real longest glyph, not just guessing?
And I'm not just talking about the letters, digits and common symbols (!, # and so on). I mean the longest glyph in all the 32,834 characters of UTF-16.
So I started with answer by #NK that had a programmatic solution to it, and made a modification:
var capsIndex = 65;
var smallIndex = 97;
var div = document.createElement('div');
div.style.float = 'left';
document.body.appendChild(div);
var highestWidth = 0;
var elem;
for(var i = capsIndex; i < 32834; i++) {
div.innerText = String.fromCharCode(i);
var computedWidth = window.getComputedStyle(div, null).getPropertyValue("width");
if(highestWidth < parseFloat(computedWidth)) {
highestWidth = parseFloat(computedWidth);
elem = String.fromCharCode(i);
}
}
div.innerHTML = '<b>' + elem + '</b>' + ' won';
After running this and waiting (and waiting), it gives the output ௌ won.
And there you have it, the longest character in UTF-32!
Note that on most fonts the longest glyph is ﷽, but some fonts (especially monospace ones) overlap the characters, as with the font that the program was run with.
It will depend on the font. I would create a small program in a programming language you're most comfortable with, where you draw each letter of the alphabet into a n times m sized bitmap. Initialize each pixel with white. Then count the number of white pixels after you've drawn each letter and save that number. The highest number you find is the one you're looking for.
EDIT: If you're in fact just interested in which one takes up the largest rectangle (but it looks like you're really after that, not the pixels), you can use various API calls to find the size, but that depends on your programming language. In Java, for example, you would use the FontMetrics class.
Or if you want to have a map of widths, containing more than just alpha(numeric) characters like described above (like I needed in a non-browser environment)
const chars = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "!", "\"", "#", "$", "%", "'", "(", ")", "*", "+", ",", "-", ".", "/", ":", ";", "=", "?", "#", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "[", "\\", "]", "^", "_", "`", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "{", "|", "}", "~", " ", "&", ">", "<"]
const test = document.createElement('div')
test.id = "Test"
document.body.appendChild(test)
test.style.fontSize = 12
const result = {}
chars.forEach(char => {
let newStr = ""
for (let i = 0; i < 10; i++) {
if (char === " ") {
newStr += " "
} else {
newStr += char
}
}
test.innerHTML = newStr
const width = (test.clientWidth)
result[char] = width / 10
})
console.log('RESULT:', result)
#Test
{
position: absolute;
/* visibility: hidden; */
height: auto;
width: auto;
white-space: nowrap; /* Thanks to Herb Caudill comment */
}
This code will get widths for all characters as array:
const alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
var widths = [];
var div = document.createElement('div');
div.style.float = 'left';
document.body.appendChild(div);
var highestObservedWidth = 0;
// widest characters (not just one)
var answer = '';
for (var i = 0; i < alphabet.length; i++) {
div.innerText = alphabet[i];
var computedWidthString = window.getComputedStyle(div, null).getPropertyValue("width");
var computedWidth = parseFloat(computedWidthString.slice(0, -2));
// console.log(typeof(computedWidth));
widths[i] = computedWidth;
if(highestObservedWidth == computedWidth) {
answer = answer + ', ' + div.innerText;
}
if(highestObservedWidth < computedWidth) {
highestObservedWidth = computedWidth;
answer = div.innerText;
}
}
if (answer.length == 1) {
div.innerHTML = ' Winner: ' + answer + '.';
} else {
div.innerHTML = ' Winners: ' + answer + '.';
}
div.innerHTML = div.innerHTML ;
// console.log(widths);
// console.log(widths.sort((a, b) => a - b));
It depends on the font. Crossed zero for example takes up considerably more than a regular one.
But if one could put up a guess, I'd go with X or B.
Related
I'm trying to add items from a csv into a vector. Some of the items have 2 elements, some 3, some 4. The code is working fine for the first 3 elements, but when I try to add the fourth I get an out of range error.
int i = 1;
while (i < temp.size()) {
Course course;
course.courseId = temp[i][0];
course.name = temp[i][1];
if (!temp[i][2].empty()) {
course.prereq = temp[i][2];
/*if (!temp[i][3].empty()) {
course.prereq2 = temp[i][3];
}*/
}
courses.push_back(course);
i++;
cout << i;
}
Thank you.
I am writing a report in R Markdown, it contains multiple animated highcharts.
The animations work fine, however they all run when the html page loads (after knitting), instead of when the user scrolls to it, so essentially the animation is pointless as the user never sees it.
An example of an animated chart is at the bottom of this question.
Is there a way to make it animate when it appears? All the examples I have found use jsfiddle and I am using R Markdown.
Many thanks
library(dplyr)
library(stringr)
library(purrr)
n <- 5
set.seed(123)
df <- data.frame(x = seq_len(n) - 1) %>%
mutate(
y = 10 + x + 10 * sin(x),
y = round(y, 1),
z = (x*y) - median(x*y),
e = 10 * abs(rnorm(length(x))) + 2,
e = round(e, 1),
low = y - e,
high = y + e,
value = y,
name = sample(fruit[str_length(fruit) <= 5], size = n),
color = rep(colors, length.out = n),
segmentColor = rep(colors2, length.out = n)
)
hcs <- c("line") %>%
map(create_hc)
hcs
Ok, I worked out how to do it myself, going to post the answer here in case someone stumbles across this post in the future.
First of all, I found NOTHING on how to do this in R.
So, I decided to do this in JS, AFTER I had knitted the R Markdown document to HTML, as it wouldn't work in R Markdown.
Once it is a HTML file, open it in TextEdit or Notepad, and add the following code just before one of the charts:
<script>
(function (H) {
var pendingRenders = [];
// https://stackoverflow.com/questions/123999/how-to-tell-if-a-dom-element-is-visible-in-the-current-viewport/7557433#7557433
function isElementInViewport(el) {
var rect = el.getBoundingClientRect();
return (
rect.top >= 0 &&
rect.left >= 0 &&
rect.bottom <= (
window.innerHeight ||
document.documentElement.clientHeight
) &&
rect.right <= (
window.innerWidth ||
document.documentElement.clientWidth
)
);
}
H.wrap(H.Series.prototype, 'render', function deferRender(proceed) {
var series = this,
renderTo = this.chart.container.parentNode;
// It is appeared, render it
if (isElementInViewport(renderTo) || !series.options.animation) {
proceed.call(series);
// It is not appeared, halt renering until appear
} else {
pendingRenders.push({
element: renderTo,
appear: function () {
proceed.call(series);
}
});
}
});
function recalculate() {
pendingRenders.forEach(function (item) {
if (isElementInViewport(item.element)) {
item.appear();
H.erase(pendingRenders, item);
}
});
}
if (window.addEventListener) {
['DOMContentLoaded', 'load', 'scroll', 'resize']
.forEach(function (eventType) {
addEventListener(eventType, recalculate, false);
});
}
}(Highcharts));
</script>
The charts then animate when you scroll to them, rather than when you open the HTML file.
Note: The JSFIDDLE I got the code from was from here:
https://jsfiddle.net/gh/get/library/pure/highcharts/highcharts/tree/master/samples/highcharts/studies/appear/
I am using Open Flash Charts v2. I have been trying to make Conditional line graph. But I couldn't find any straight forward way, example or any class for producing Conditional charts.
Example of Conditional Graph
So I thought to use some techniques to emulate conditional graph ,I made separate Line object for values above limit range and then this line is used to overlap the plotted line.
This techniques works some what ok ,but there are problems with it,
How to color or place the conditional colored line exactly above the limit.
Remove tooltip and dot from limit line.
Tooltip of conditional line(red) and plotted line(green) are both shown ,I only need tooltip of green line.
Conditional Line Graph Problem illustrated
Source Code: // C#
var chart = new OpenFlashChart.OpenFlashChart();
var data1 = new List<double?> { 1, 3, 4, 5, 2, 1, 6, 7 };//>4=
var overlap = new List<double?> { null, null, 4, 5, null, null, null, null };
var overlap2 = new List<double?> { null, null, null, null, null, null, 6, 7 };
var limitData = new List<double?> { 4, 4, 4, 4, 4, 4, 4, 4 };
var line1 = new Line();
line1.Values = data1;
//line1.HaloSize = 0;
line1.Width = 2;
line1.DotSize = 5;
line1.DotStyleType.Tip = "#x_label#<br>#val#";
line1.Colour = "#37c855";
line1.Tooltip = "#val#";
var overLine = new Line();
overLine.Values = overlap;
//overLine.HaloSize = 0;
overLine.Width = 2;
overLine.DotSize = 5;
overLine.DotStyleType.Tip = "#x_label#<br>#val#";
overLine.Colour = "#d81417";
overLine.Tooltip = "#val#";
var overLine2 = new Line();
overLine2.Values = overlap2;
//overLine2.HaloSize = 0;
overLine2.Width = 2;
overLine2.DotSize = 5;
//overLine2.DotStyleType.Tip = "#x_label#<br>#val#";
//overLine2.DotStyleType.Type = DotType.DOT;
overLine2.Colour = "#d81417";
overLine2.Tooltip = "#val#";
var limit = new Line();
limit.Values = limitData;
limit.Width = 2;
limit.Colour = "#ff0000";
limit.HaloSize = -1;
limit.DotSize = -1;
// limit.DotStyleType.Tip = "";
limit.DotStyleType.Type = null;
//limit.Tooltip = "";
chart.AddElement(line1);
chart.AddElement(overLine);
chart.AddElement(overLine2);
chart.AddElement(limit);
chart.Y_Legend = new Legend("Experiment");
chart.Title = new Title("Conditional Line Graph");
chart.Y_Axis.SetRange(0, 10);
chart.X_Axis.Labels.Color = "#e43456";
chart.X_Axis.Steps = 4;
chart.Tooltip = new ToolTip("#val#");
chart.Tooltip.Shadow = true;
chart.Tooltip.Colour = "#e43456";
chart.Tooltip.MouseStyle = ToolTipStyle.CLOSEST;
Response.Clear();
Response.CacheControl = "no-cache";
Response.Write(chart.ToPrettyString());
Response.End();
Note:
I have already downloaded the OFC (Open Flash Charts) source ,If I modify the OFC Line.as source than how would I be able to generate json for the changed graph ? ,b/c I'm currently using .Net library for the json generation for OFC charts,please do let me know this also.
Update:
I have modified the source code on the advice of David Mears I'm using FlashDevelop for ActionScript.
P.S: I'm open for ideas if another library can do this job.
If you don't mind a little rebuilding, you can get the source of OFC here and modify the Line.solid_line() method in open-flash-chart/charts/Line.as to do this fairly easily.
In order to set the extra chart details through JSON using the .NET library, you'll also have to modify OpenFlashChart/LineBase.cs to add alternative colour and boundary properties. I'm not hugely familiar with .NET, but based on the existing properties you might add something like this:
private double boundary;
private string altcolour;
[JsonProperty("boundary")]
public virtual double Boundary
{
set { this.boundary = value; }
get { return this.boundary; }
}
[JsonProperty("alt-colour")]
public virtual string AltColour
{
set { this.altcolour = value; }
get { return this.altcolour; }
}
Then I believe the following should work in Line.as:
public function solid_line(): void {
var first:Boolean = true;
var i:Number;
var tmp:Sprite;
var x:Number;
var y:Number;
var last_e:Element;
var ratio:Number;
for ( i=0; i < this.numChildren; i++ ) {
// Step through every child object.
tmp = this.getChildAt(i) as Sprite;
// Only include data Elements, ignoring extra children such as line masks.
if( tmp is Element )
{
var e:Element = tmp as Element;
if( first )
{
if (this.props.get('alt-colour') != Number.NEGATIVE_INFINITY) {
if (e._y >= this.props.get_colour('boundary'))
{
// Line starts below boundary, set alt line colour.
this.graphics.lineStyle( this.props.get_colour('width'), this.props.get_colour('alt-colour') );
}
else
{
// Line starts above boundary, set normal line colour.
this.graphics.lineStyle( this.props.get_colour('width'), this.props.get_colour('colour') );
}
}
// Move to the first point.
this.graphics.moveTo(e.x, e.y);
x = e.x;
y = e.y;
first = false;
}
else
{
if (this.props.get('alt-colour') != Number.NEGATIVE_INFINITY) {
if (last_e._y < this.props.get_colour('boundary') && e._y >= this.props.get_colour('boundary'))
{
// Line passes below boundary. Draw first section and switch to alt colour.
ratio = (this.props.get_colour('boundary') - last_e._y) / (e._y - last_e._y);
this.graphics.lineTo(last_e.x + (e.x - last_e.x) * ratio, last_e.y + (e.y - last_e.y) * ratio);
this.graphics.lineStyle( this.props.get_colour('width'), this.props.get_colour('alt-colour') );
}
else if (last_e._y >= this.props.get_colour('boundary') && e._y < this.props.get_colour('boundary'))
{
// Line passes above boundary. Draw first section and switch to normal colour.
ratio = (this.props.get_colour('boundary') - last_e._y) / (e._y - last_e._y);
this.graphics.lineTo(last_e.x + (e.x - last_e.x) * ratio, last_e.y + (e.y - last_e.y) * ratio);
this.graphics.lineStyle( this.props.get_colour('width'), this.props.get_colour('colour') );
}
}
// Draw a line to the next point.
this.graphics.lineTo(e.x, e.y);
}
last_e = e;
}
}
if ( this.props.get('loop') ) {
// close the line loop (radar charts)
this.graphics.lineTo(x, y);
}
}
With the new open-flash-chart.swf, you should be able to just set your new properties on line1:
line1.Boundary = 4;
line1.AltColour = "#d81417";
I need to create an asp.net page that auto generate a brackets tournament tennis style.
Regarding the managing of match in database, it's not a problem.
The problem is the dynamic graphics creation of brackets.
The user will be able to create tournament by 2-4...32 players.
And i don't know ho to create the graphics bracket in html or gdi...
Using Silverlight, and a Grid, You can produce something like this:
To do it, define a regular UserControl containing a Grid. (This is the default when you build a silverlight app in VS2008 with the Silverlight 3.0 SDK).
Then, add a call to the following in the constructor for the user control:
private void SetupBracket(int n)
{
var black = new SolidColorBrush(Colors.Gray);
// number of levels, or rounds, in the single-elim tourney
int levels = (int)Math.Log(n, 2) + 1;
// number of columns in the Grid. There's a "connector"
// column between round n and round n+1.
int nColumns = levels * 2 - 1;
// add the necessary columns to the grid
var cdc = LayoutRoot.ColumnDefinitions;
for (int i = 0; i < nColumns; i++)
{
var cd = new ColumnDefinition();
// the width of the connector is half that of the regular columns
int width = ((i % 2) == 1) ? 1 : 2;
cd.Width = new GridLength(width, GridUnitType.Star);
cdc.Add(cd);
}
var rdc = LayoutRoot.RowDefinitions;
// in the grid, there is one row for each player, and
// an interleaving row between each pair of players.
int totalSlots = 2 * n - 1;
for (int i = 0; i < totalSlots; i++)
{
rdc.Add(new RowDefinition());
}
// Now we have a grid of the proper geometry.
// Next: fill it.
List<int> slots = new List<int>();
ImageBrush brush = new ImageBrush();
brush.ImageSource = new BitmapImage(new Uri("Bridge.png", UriKind.Relative));
// one loop for each level, or "round" in the tourney.
for (int j = 0; j < levels; j++)
{
// Figure the number of players in the current round.
// Since we insert the rounds in the reverse order,
// think of j as the "number of rounds remaining."
// Therefore, when j==0, playersThisRound=1.
// When j == 1, playersThisRound = 2. etc.
int playersThisRound = (int)Math.Pow(2, j);
int x = levels - j;
int f = (int)Math.Pow(2, x - 1);
for (int i = 0; i < playersThisRound; i++)
{
// do this in reverse order. The innermost round is
// inserted first.
var r = new TextBox();
r.Background = black;
if (j == levels - 1)
r.Text = "player " + (i + 1).ToString();
else
r.Text = "player ??";
// for j == 0, this is the last column in the grid.
// for j == levels-1, this is the first column.
// The grid column is not the same as the current
// round, because of the columns used for the
// interleaved connectors.
int k = 2 * (x - 1);
r.SetValue(Grid.ColumnProperty, k);
int m = (i * 2 + 1) * f - 1;
r.SetValue(Grid.RowProperty, m);
LayoutRoot.Children.Add(r);
// are we not on the last round?
if (j > 0)
{
slots.Add(m);
// Have we just inserted two rows? Then we need
// a connector between these two and the next
// round (the round previously added).
if (slots.Count == 2)
{
string xamlTriangle = "<Path xmlns='http://schemas.microsoft.com/winfx/2006/xaml/presentation' "+
"xmlns:x='http://schemas.microsoft.com/winfx/2006/xaml' " +
"Data='M0,0 L 100 50 0 100 Z' Fill='LightBlue' Stretch='Fill'/>";
Path path = (Path)System.Windows.Markup.XamlReader.Load(xamlTriangle);
path.SetValue(Grid.ColumnProperty, 2 * (x - 1) + 1);
path.SetValue(Grid.RowProperty, slots[0]);
path.SetValue(Grid.RowSpanProperty, slots[1] - slots[0] + 1);
this.LayoutRoot.Children.Add(path);
slots.Clear();
}
}
}
}
}
In the above, the connector is just an isosceles triangle, with the apex pointing to the right. It is generated by XamlReader.Load() on a string.
You would also want to pretty it up, style it with different colors and fonts, I guess.
You can insert this silverlight "user control" into any HTML web page, something like embedding a flash app into a page. There are silverlight plugins for IE, Firefox, Opera, Safari, and Chrome.
If you don't want to use Silverlight, you could use a similar approach to construct an HTML table.
I'm using microsoft Chart control in my web form. I want points(0, 0) should be bold on the chart. My code is as follows:
DataTable dt = collection.ToDataTable();
// Chart1.Series[0].Points.DataBind(collection, "Price", "OverallQuality", "Label=HotelName");
for (int i = 0; i < dt.Rows.Count; i++)
{
Chart1.Series.Add("series" + i);
Chart1.Series["series" + i].ChartType = SeriesChartType.Point;
// Chart1.Series["series" + i].Points.AddXY(double.Parse(dt.Rows[i]["Price"].ToString()), double.Parse(dt.Rows[i]["OverallQuality"].ToString()));
Chart1.Series["series" + i].Points.AddXY(double.Parse(dt.Rows[i]["OverallQuality"].ToString()), double.Parse(dt.Rows[i]["Price"].ToString()));
Chart1.Series["series" + i].MarkerSize = 10;
Chart1.Series["series" + i].LegendText = dt.Rows[i]["HotelName"].ToString();
}
// Chart1.ChartAreas[0].AxisX.Title = "Price";
// Chart1.ChartAreas[0].AxisY.Title = "Quality";
Chart1.ChartAreas[0].AxisX.Title = "Quality";
Chart1.ChartAreas[0].AxisY.Title = "Price";
Chart1.ChartAreas[0].AxisX.Maximum = 10;
Chart1.ChartAreas[0].AxisX.Minimum = -10;
Chart1.ChartAreas[0].AxisX.Interval = 1;
Chart1.ChartAreas[0].AxisY.Maximum = 10;
Chart1.ChartAreas[0].AxisY.Minimum = -10;
Chart1.ChartAreas[0].AxisY.Interval = 1;
Chart1.ChartAreas[0].AxisX.MajorGrid.LineColor = System.Drawing.Color.LightGray;
Chart1.ChartAreas[0].AxisY.MajorGrid.LineColor = System.Drawing.Color.LightGray;
}
Have you tried changing the PointWidth of the series?
Chart1.Series["series"]["PointWidth"] = "0.2";
You can find a bunch of examples of manipulating this property, such as this. But the trick, for your situation, is dealing with the fact that you can only manipulate this property for the entire series. This post leads me to believe you will have problems setting it for just this particular point, unless you can separate is into it's own somehow. Here's an exmample from stack somewhat similar that might help, depending on how your information is formatted.