I've just started using Drupal and I must admit its brilliant. Im still finding my way around it, so this might be a stupdi question, but Id like to know what the best and least perofrmance impacting way to achieve the below.
I have created a view with the "Node: Nid" argument to bascially list certain information about additioanl information about an artist, his events, albums etc..... The path has been set using the %. The idea being that when a particular artist node is in the node URL it will display all of the other info.
What I would like to do is add a link to the artist page called more info. So when clicked it takes you to that particular view and display all the other information.
I have realised that you cannot create menu items, using % argument.
How you would you guys do this ?
thanks :)
Charles
You are correct that you can't use wildcards in menus.
However, you can create a fake menu block outside the normal Drupal menu system that contains the menu items you want: just create a view and use the HTML list style. Each row in the view will correspond to one of your fake menu's items. When you're finished creating the view, create a block display for that view.
Add the block to a region using Site Building -> Blocks, and style it to look like your other menus.
Related
I need to create a list of nodes(with links) that shows nodes of a couple specific content type, but also filters out nodes that are more than 1 level of menu depth lower than a specific node.
I've tried creating a menu block, but I see no options to filter by content type.
I've tried creating a view, but I see no options to filter by menu depth.
Anyone know the best way to do this?
Thanks.
Follow up: I just ended up using Taxonomy and setting a default node that it refers to. Not my ideal solution, but it gets the job done.
I have created a page view using field style to display a list of teasers as I want. fields configuration in views allows us to link the field to it's node. but what if we have created view for node detail page and want field to link to it's relevant view.
I had the same question, and after a bit of research this is what I've concluded:
The views module isn't intended to replace a default node view. I say this because of the level of difficulty involved in doing this and the lack of information on how to accomplish this. Ryan Weal has posted a way to accomplish this by editing your node template that doesn't look too difficult to accomplish, and here is the link.
However, it seems that a more popular solution, especially if you are like me and don't like to get into editing theme files. You can use the Display Suite module to effectively reformat the default node content as you would like.
I'm not sure if I understand you properly, but it sounds like you are wanting to display a view in a page view of a node?
In order to do this, you could:
create a small module, using hook_nodeapi() or one of the D7 replacements for this function in order to insert the output of the embedded view into this page's content, by conditionally adding a $content element when the node is of the appropriate id
or (easier, but requires allowing input type PHP) embed the view right on the page.
http://thedrupalblog.com/embedding-view-drupal-6-using-views-embed-view for information on embedding views
I've encountered a Drupal problem: I'm using the Views module for rendering nodes of a kind, based on the user id of it's author (it is a Content Profile actually). I want the view to show the comments for the node, just like in node/%. I could not find any option in views or any relevant module. Am I in the wrong direction and should reorganize stuff for this...?
Any ideas, how can it be done?
Regards,
Laci
Using views is really not the best plan of action. You should instead create a node template in your theme and customize it. If needed you can put some logic in a preprocess function. It requires more coding but will get you where you want.
If you use view node display type
Check in it's settings show comments
if you use view fields display type
Use relationship to comments and select fields you need and theme them
I know this is old request, but I was just struggling with the same issue and came across this post. I thought it'd be helpful to share my solution.
I'm using Drupal 7, with Views 3 and Display Suite.
In your view, choose the display in question.
Under Format, click the first link to the right of 'Show'.
Choose 'Content' (or 'Display Suite' in my case).
Click 'Apply'.
On the next screen, you'll have the option to 'Display comments'. Check this box and save your view.
You should now see the comments displayed under each item in the view.
You could create a second view (with URL e.g. /comments/% where the placeholder will be the node ID, and not the comment ID) that lists comments for a given node, with a contextual filter to only show them based on the NID in the URL.
Then, add that view to the footer (as a 'view area') of the single-node view you've already got.
There's some tweaking required for layout (inline fields etc.) but the basic structure should work.
After only a few weeks of working with Drupal I've come up with a recurring problem, which I don't really have an optimal solution to, so I'm hoping that someone here might be able to give some best practice pointers.
What I have is a region inside my node.tpl.php, which is populated with blocks that display content from two different CCK fields of the type node_reference. This works fine when displaying a single node. The problem appears when I need to use a view.
For example, lets say I have a news listing, and a single news item view. When I display the single news item I can use the news node node_reference field to reference whatever material I would like to have in my sidebar, but when on the news listing view I would like to reference nodes separately. What would be the best practice to solve this?
I'm having a few ideas, but none seem like the logical choice, how would you do?
My understanding of your problem is that you don't want the blocks to display on the view page and you want the block information displayed inline with the node.
The first part is easy, you can modify the block visibility settings to not show up on the path where you have the view.
The second part will depend on how you set up your view. If you are using fields you can simply add fields for the node_reference and they should display. If you are using a node view, you will have to override the template and create a template which displays the node reference field.
If you want further explanation please comment and I can clarify
After reading my question I realize that it was explained pretty badly, so I'll try again, and also tell how I solved it.
The Problem
On normal "pages" (when displaying only a single node), I have a sidebar that shows something similar to banners, which are either random, or I can select one or many that should always be displayed on the sidebar. This is solved easily when displaying a single node, using a CCK node_reference field. The problem is when using a View that displays multiple nodes, for example a news listing-
The Solution
In my case I could solve this by creating additional fields on my default Page content-type. These fields were called view, display and arguments. In my tpl.php I then embedded the news listing view inside a page, lets call it News. This way I gained great flexibility, and also helps the News page to know where it is located in menu structure.
Final comments
I have yet to discover if there are any drawbacks or dangers in doing this way, but if there are, feel free to share them with me :)
I tend to want to create my own modules, which create blocks and reference the database directly. Then I put the blocks inside of panels, this seems to be more flexible for me than using views and cck fields etc ...
Let's suppose I have created a view that shows some kind of stories.
But I want to show this view in a left-hand bar — not a link to the view, but the view itself.
How can I connect my new view with a fixed block position?
I want to be able to show real view data in various places on my page.
Is it possible or I am limited only to central area and links to views from menu?
Using Views 2.x for Drupal 6.x it's simple to create a block from a view. Every view has a set of 'default' settings and some number of display settings. A display can be a page, a block, a feed or anything else that creative module authors.
To make a block from your view, you just "Add Display" of type "block", override any settings that you want changed in the block (IE - display less items, just a node title, whatever). You then have a block that you can place like any other Drupal block.
edit: Answer to "Can you limit stories to ones that are tagged"? Sure thing. You just add a filter for Taxonomy terms.
Getting a view to display in a block is easy. Once you have created a view and assigned the view as a block position you simply head to blocks in your admin and you'll see the view.
Just select the block and save it. Simple.
If your view doesn't show, check your filters and that the view fields are correct. Usually if they are not showing it is something simple like selecting content published = yes.
You can create views as pages or blocks. As you're not telling exactly which Drupal/Views version you're working with, all I can tell so far is that, after you create the view, you can tell it to display as a block or as a page.
Then go to the blocks settings and set that to the position you want.