I have a jsp page which holds a form, it is supposed to send off the form data to a remote servlet, which calculates it, and then returns it as XML. It works, but at the moment I'm creating an instance and dispatcher which only works with local servlets whereas I want it to work with a remote servlet.
I was previously told that HTTPClient would do this, but this thing has become such a headache and it seems like a complete overkill for what I want to do. There must be some simple method as opposed to faffing around with all these jar components and dependencies?
Please give sample code if possible, I'm really a complete novice to Java, much more of a PHP guy :P
Figured it out with the help of some online resources. Had to first collect the submitted values (request.getParamater("bla")), build the data string (URLEnconder), start up a URLConnection and tell it to open a connection with the designated URL, startup an OutputStreamWriter and then tell it to add the string of data (URLEncoder), then finally read the data and print it...
Below is the gist of the code:
String postedVariable1 = request.getParameter("postedVariable1");
String postedVariable2 = request.getParameter("postedVariable2");
//Construct data here... build the string like you would with a GET URL
String data = URLEncoder.encode("postedVariable1", "UTF-8") + "=" + URLEncoder.encode(postedVariable1, "UTF-8");
data += "&" + URLEncoder.encode("postedVariable2", "UTF-8") + "=" + URLEncoder.encode(submitMethod, "UTF-8");
try {
URL calculator = new URL("http://remoteserver/Servlet");
URLConnection calcConnection = calculator.openConnection();
calcConnection.setDoOutput(true);
OutputStreamWriter outputLine = new OutputStreamWriter(calcConnection.getOutputStream());
outputLine.write(data);
outputLine.flush();
// Get the response
BufferedReader streamReader = new BufferedReader(new InputStreamReader(calcConnection.getInputStream()));
String line;
//streamReader = holding the data... can put it through a DOM loader?
while ((line = streamReader.readLine()) != null) {
PrintWriter writer = response.getWriter();
writer.print(line);
}
outputLine.close();
streamReader.close();
} catch (MalformedURLException me) {
System.out.println("MalformedURLException: " + me);
} catch (IOException ioe) {
System.out.println("IOException: " + ioe);
}
Related
I've got a problem while resolving one task. The task was: Create an opportunity for users to download a .docx document with pasted data. But I'm stuck at the moment at sending the file as a byte array (taken from a MemoryStream) to the context's response. Here's a sample:
using (MemoryStream stream = new MemoryStream(FileBytes))
{
using (WordprocessingDocument myDoc = WordprocessingDocument.Open(stream, true))
{
MainDocumentPart mainPart = myDoc.MainDocumentPart;
foreach (SdtElement obj in mainPart.Document.Body.Descendants<SdtElement>().ToList())
{
foreach (Text t in obj.Descendants<Text>().ToList())
{
switch (t.Text)
{
//.... here is code that fiiling content control's
}
}
}
myDoc.MainDocumentPart.Document.Save();
myDoc.Close();
}
context.Response.Clear();
context.Response.ClearHeaders();
context.Response.ClearContent();
context.Response.AddHeader("content-disposition", "attachment; filename=\"" + DocName + ".docx\"");
context.Response.ContentType = "application/vnd.openxmlformats-officedocument.wordprocessingml.document";
context.Response.ContentEncoding = Encoding.GetEncoding("ISO-8859-1");
stream.Seek(0, SeekOrigin.Begin);
context.Response.BinaryWrite(stream.ToArray());
}
context.Response.Flush();
The HTTP handler doesn't return any errors - page refresh and download don't start. The handler is calling from JS. Here is the sample of the JS function:
function save_word_doc(id_btn) {
// ... here is code that gets params from default page data
jQuery.post("DataHandler.ashx?CN=" + vCN + "&CommandName=SaveWord&auctionID=" + oFormRecord.auctionID
+ "&user_login=" + user_login
+ ....
+ "&amount=" + oFormRecord.value.amount
+ "&percent=" + percent);
}
By the way, this sample code is working well in an ASP.Net MVC project, where the handler is calling from a link button. But this must work in a Web Forms project.
Update to pretend questions and incorrect answers: the file is generated and saved correctly to the local machine.
I see a few issues in your code. Firstly, new MemoryStream(FileBytes) creates a non-resizable MemoryStream, which is not what you want in case you are changing the WordprocessingDocument. You would should use new MemoryStream() to create a resizable MemoryStream and copy your FileBytes to that MemoryStream.
Secondly, since you are in a using statement, you don't need the following two lines of code. This is done automatically for you.
myDoc.MainDocumentPart.Document.Save();
myDoc.Close();
Lastly, I am not sure about your ContentEncoding value for the binary data you are sending. You might want to use a tool like Fiddler or Postman to verify what happens.
I'm trying to download a file using HTTP, and here is the code.
With this, I have a directory made with a correct name, and a file within the directory made with a correct name, but there is NOTHING WRITTEN in the file.
PostMethod post = new PostMethod(serverUrl);
post.setRequestEntity(entity);
httpclient.executeMethod(post);
File contentDirectory = new File(fileFullPath);
if(contentDirectory.exists() == false){
contentDirectory.mkdir();
}
File localFile = new File(fileFullPath + File.separator + filename);
int readBuf = 0;
byte[] buf = new byte[Utils.getBufferSize()]; (BufferSize Checked)
InputStream is = null;
is = post.getResponseBodyAsStream();
FileOutputStream fos = new FileOutputStream(localFile);
while((readBuf = is.read(buf))!= -1){
fos.write(buf, 0, readBuf);
logger.info("readBuf : "+readBuf);
}
is.close();
fos.close();enter code here
if(localFile.exists()) Transfer_Success = true;
Being a noob I am, turns out all this time I was sending post method to a wrong servlet. A mistake only novices make.
So I have the bytes transferred correctly, but this time the image files can't be open due to wrong encoding type or something. I'm on to resolving this.
As the title suggests, WLP won't run the process- it won't return anything to the process input stream nor to error stream.
If anyone knows about a configuration that needs to take place I would love to know..
(note the process Can run by running the command manually - in addition, the whole thing runs smooth on tomcat8 so..)
EDIT 1:
The problem was not the command execution under WLP as you guys stated, so I accepted the answer.
The problem is different : I sent a media file to a multipart servlet and stored it in a file on disk using the following code:
InputStream is = request.getInputStream();
String currentTime = new Long(System.currentTimeMillis()).toString();
String fileName = PATH + currentTime + "." + fileType;
File file = new File(fileName);
// write the image to a temporary location
FileOutputStream os = new FileOutputStream(file);
byte[] buffer = new byte[BUFFER_SIZE];
while(true) {
int numRead = is.read(buffer);
if(numRead == -1) {
break;
}
os.write(buffer, 0, numRead);
os.flush();
}
is.close();
os.close();
and the file gets saved along with the following prefix:
While this does not happen on tomcat8 (using the same client)..
something is not trivial in the received input stream. (Note its a multipart servlet that set up via #MultipartConfig only)
Hope this post will help others..
guys,thanks for your help!
This will work in Liberty. I was able to test out the following code in a servlet and it printed the path of my current directory just fine:
String line;
Process p = Runtime.getRuntime().exec("cmd /c cd");
BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream()));
while ((line = input.readLine()) != null) {
System.out.println(line);
}
input.close();
Start with a simple command like this, and when you move up to more complex commands or scripts, make sure you are not burying exceptions that may come back. Always at least print the stack trace!
I have a servlet that receives an uploaded file. We've been having issues with a certain client's request not having a file attached or so the servlet thinks. The upload servlet is a replacement for an old one and we're using the Apache Commons FileUpload library to parse the file from the request. The old code uses the JavaZoom library. The requests client we're having issues with work perfectly fine in the old code.
In order to troubleshoot the problem, I added a bunch of logging to look at the request headers and parts to compare requests from a client that works with the one that doesn't. This is a snippet of how I'm looking at the parts:
Collection<Part> parts = request.getParts();
for(Part part : parts)
{
String partName = part.getName();
log.debug("Part=" + partName);
Collection<String> headerNames = part.getHeaderNames();
for(String headerName : headerNames)
{
String headerValue = part.getHeader(headerName);
log.debug(headerName + "=" + headerValue);
InputStream inputStream = part.getInputStream();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"));
StringBuilder builder = new StringBuilder();
try
{
for(String line=bufferedReader.readLine(); line!=null; line=bufferedReader.readLine())
{
builder.append(line);
builder.append('\n');
}
}
catch (IOException ignore)
{
// empty
}
finally
{
inputStream.reset();
}
log.debug("InputStream=" + builder.toString());
}
}
All this code works fine and I get the logging I'm expecting. However, this next bit of code doesn't act as expected:
if (isMultipart)
{
// Create a factory for disk-based file items
FileItemFactory factory = new DiskFileItemFactory();
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
#SuppressWarnings("rawtypes")
List items = null;
// Parse the request
try
{
items = upload.parseRequest(request);
log.debug("items=" + items);
}
catch (FileUploadException ex)
{
log.warn("Error parsing request", ex);
response.sendError(HttpServletResponse.SC_BAD_REQUEST, ex.getMessage());
}
the items variable is empty when it's logged. If I comment out the code for logging the request parts, this bit of code works and the items variable contains the uploaded file.
I can only assume that the act of getting/reading the parts from the request somehow removes them from it and are no longer available for further processing. Is there some way to read them for logging purposes and still retain them in the request for further processing?
The Collection<Part> parts = request.getParts(); is an Sevlet 3.0 API which is replacement for Commons Apache File Upload API.
You should be using only one of the two methods. Both have the support for processing uploaded files and parameters along with it.
Here is the Example for File Upload Using Servlet 3.0
The problem you are facing is because you are invoking this Collection<Part> parts = request.getParts(); request will consume the request input stream. And then you are using Apache Commons API to read the parts again. Because the stream is already read you are seeing no parts are available.
References for Servlet 3.0 File Upload:
Posting Data along with File
Servlet 3.0 Multipart Example
Servlet 3.0 MultipartConfig
I'm trying to create an MJPEG stream, I have a series of jpegs that I want to put together into a stream so that a user can just hit a URL and get an mjpeg stream.
I've been trying for the last few days to get this to work, and it may just not be possible. I've brought up ethereal and listened to the packets coming from an axis camera on the net somewhere, and tried to mimmick it. I originally tried using WCF, and returning a "stream" but then later found out that I would need to set the content type on that stream, so I then tried the WCF REST api, but that suffers from the same problem. so I am now just using a bare bones HTTPListener, and handling the event. I would greatly prefer to use WCF, but I'm not sure that it will allow me to return a stream with the right content type.
so here's what I have for the httpListener .
in the handler of the listener call back I put the following.
HttpListenerResponse response = context.Response;
response.ProtocolVersion = new System.Version(1, 0);
response.StatusCode = 200;
response.StatusDescription = "OK";
response.ContentType = "multipart/x-mixed-replace;boundary=" + BOUNDARY + "\r\n";
System.IO.Stream output = response.OutputStream;
Render(output);
the Render method looks like this
var writer = new StreamWriter(st);
writer.Write("--" + BOUNDARY + "\r\n");
while (true)
{
for (int i = 0; i < imageset.Length; i++)
{
var resource = Properties.Resources.ResourceManager.GetObject(imageset[i]) as Bitmap;
var memStream = new MemoryStream();
resource.Save(memStream,ImageFormat.Jpeg);
byte[] imgBinaryData = memStream.ToArray();
string s = Convert.ToBase64String(imgBinaryData);
writer.Write("Content-type: image/jpeg\r\n");
foreach (var s1 in imgBinaryData)
{
writer.Write((char)s1);
}
writer.Write("\n--" + BOUNDARY + "\n");
writer.Flush();
Thread.Sleep(500);
}
}
At this point I've just added a few jpeg images as properties on the dll, and am iterating over them, eventually these will be dynamic images, but for now I just want to get the thing to work.
From what I understand about the MJPEG (spec) is that the content must be set to multipart/x-mixed-replace and a boundary set. and then you just deliminate the jpegs within the stream by the boundary.
This seems like it should be simpler then I'm making it, but I'm wondering where I'm going wrong. if I load this URL up in IE or Firefox, it just hangs. if I try to make a stub html page with an img tag, whose source is the URL then I get a broken image.
Any ideas, thanks
Josh
Well, as far as I can tell, here are your issues:
The StreamWriter is not a correct choice. Use a regular stream write function is fine. Meaning, you should write data in Byte array instead of string.
You convert the Binary data of the image to String64, the browser does not known that, still thinking it is 32bit data.
Your jpeg frame format is not correct. You should also add Content-Length to the frame header so that the application that receive the stream know when to stop reading rather than having to check for the next boundary string every read. This will result in about 4-5 times faster in reading data. And there are also inconsistency in your new line character, some are "\r\n" while some others are "\n".
While loop is a infinite loop.
So, here is the solution.
Note: There might be some syntax errors but you probably get the general idea.
private byte[] CreateHeader(int length)
{
string header =
"--" + BOUDARY + "\r\n" +
"Content-Type:image/jpeg\r\n" +
"Content-Length:" + length + "\r\n" +
+ "\r\n"; // there are always 2 new line character before the actual data
// using ascii encoder is fine since there is no international character used in this string.
return ASCIIEncoding.ASCII.GetBytes(header);
}
public byte[] CreateFooter()
{
return ASCIIEncoding.ASCII.GetBytes("\r\n");
}
private void WriteFrame(Stream st, Bitmap image)
{
// prepare image data
byte[] imageData = null;
// this is to make sure memory stream is disposed after using
using (MemoryStream ms = new MemoryStream())
{
image.Save(ms, ImageFormat.Jpeg);
imageData = ms.ToArray();
}
// prepare header
byte[] header = CreateHeader(imageData.Length);
// prepare footer
byte[] footer = CreateFooter();
// Start writing data
st.Write(header, 0, header.Length);
st.Write(imageData, 0, imageData.Length);
st.Write(footer, 0, footer.Length);
}
private void Render(Stream st)
{
for (int i = 0; i < imageset.Length; i++)
{
var resource = Properties.Resources.ResourceManager.GetObject(imageset[i]) as Bitmap;
WriteFrame(st, resource);
Thread.Sleep(500);
}
}
There is also an implementation # https://net7mma.codeplex.com/SourceControl/latest the library there can transcode the Http to Rtp compatible on the fly!