Flex Cairngorm Spring Blazeds - Remoting Error - help me please - apache-flex

I seem to be getting the following error when I try to access a Remote Java class (on Spring/BlazeDS) from the Flex/Cairngorm application. I am going crazy at the moment trying to see what is wrong - any help would be greatly appreciated - thanks Mike.
**Error: C0007E: RemoteObject not found for mycomponentsService
at RemoteObjects/getService()
at com.adobe.cairngorm.business::ServiceLocator/getRemoteObject()
at com.nomura.dashboard.client.business::DashBoardDelegate()**
All my config files are below:
Cairngorm - BusinessDelegate.as
this.service = ServiceLocator.getInstance().getRemoteObject("**mycomponentsService**");
Cairngorm - Services.mxml
mx:RemoteObject id="mycomponentsService"
destination="remotecomponentService"
showBusyCursor="true">
Spring/BlazeDS - application-config.xml
flex:remote-service ref="remotecomponentService"
bean id="remotecomponentService"
class="com.mycompany.dashboard.server.dao.ComponentsDAO"
Spring/BlazeDS - services-config.xml
channel-definition id="myamf" class="mx.messaging.channels.AMFChannel"
endpoint url="http://localhost:8080/dashboard-server/spring/messagebroker/amf"
class="flex.messaging.endpoints.AMFEndpoint"
The web.xml also contains Spring references - see below
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4">
<!-- The front controller of this Spring Web application, responsible for handling all application requests -->
<display-name>dashboard-server</display-name>
<servlet>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/*-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map /spring/* requests to the DispatcherServlet -->
<servlet-mapping>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<url-pattern>/spring/*</url-pattern>
</servlet-mapping>
</web-app>

Can we see your web.xml also please? I am surprised to see the word "spring" in the endpoint URL. My endpoints have always looked like
url="http://{server.name}:{server.port}/{context.root}/messagebroker/amf"
E.g.: I think your services-config.xml should look more like this.
<channel-definition id="my-amf" class="mx.messaging.channels.AMFChannel">
<endpoint url="http://{server.name}/dashboard-server/messagebroker/amf"
class="flex.messaging.endpoints.AMFEndpoint"/>
</channel-definition>
I would also suggest not hardcoding the end-point URL so much. Just go with
<channel-definition id="my-amf" class="mx.messaging.channels.AMFChannel">
<endpoint class="flex.messaging.endpoints.AMFEndpoint"
url="http://{server.name}:{server.port}/{context.root}/messagebroker/amf" />
</channel-definition>
Update:
OK, so your web.xml looks OK, as does having the spring in your URL. What I don's see in your Spring configuration file (application-config.xml) is the Spring URL mapping. For example, in my Spring config files, in addition to the the bean definitions, there is a mapping. E.g.:
<bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<value>
/histogram/**=bean.HistogramController
/counter/**=bean.CounterController
</value>
</property>
</bean>
<bean id="bean.HistogramController" class="ch.comp.app.HistogramXportController" />
<bean id="bean.CounterController" class="ch.comp.app.CounterXportController" />
(I have one app that is Spring-based, and another that uses BlazeDS, but not both...so I might be missing something. That said, what I'm asking still should be valid. In theory. But take it with a grain of salt.)
Maybe some some super basic debugging is in order. Can you check to see if the calls to your server are returning HTTP 404 or not on theses problem endpoints? A couple ways to do this:
Check the access logs for GET /dashboard-server/spring/messagebroker/amf. What is the HTTP status code for these requests? (Free, easy, no new tools.)
If you are using FireFox as a browser, add the Tamper Data plug in. You don't have to tamper with the data, but it shows you what is being called, what is returned, and all the HTTP headers.
Use a full on Flash/Flex oriented protocol sniffer tool, like Charles Web Debugging Proxy.
It will very helpful to narrow down the problem to know if where these requests are failing on the communications stack.

I have attached web.xml below. In terms of the word "Spring" - I am using the standard BlazrDS/Spring integration WAR file which requires "spring" to be there. The bean id="remotecomponentService" is acutally a Spring bean.
Are you saying even with the BlazeDS/Spring WAR I can use your solution above?
The web.xml also contains Spring references - see below
<web-app version="2.4">
<display-name>dashboard-server</display-name>
<servlet>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/*-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map /spring/* requests to the DispatcherServlet -->
<servlet-mapping>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<url-pattern>/spring/*</url-pattern>
</servlet-mapping>
</web-app>

Related

Spring MVC 3 - Need help in resolving the url-pattern issue

I am developing an app with spring mvc and here is my web.xml
<servlet>
<servlet-name>admin</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>admin</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
For serving static content, I added the following line in my admin-servlet.xml
<context:component-scan base-package="com.prasanna.blog.Server" />
<mvc:resources mapping="/resources/**" location="/"/>
I have 5 controllers each mapped to particular url for example adminRequests.java is mapped to /admin/*
#Controller
#RequestMapping("/admin/*")
public class AdminRequests
Then I have methods inside the class mapped to particular urls.
The problem is, I am getting 404 error when the url-pattern in web.xml is mapped as / .But when I change the url pattern in web.xml to /app or any other , my index.html is served without any issues.
I am not sure where the problem is. Please advice
When you map Url pattern / to Spring's Dispatcher Servlet, all the request to your application is forwarded to Dispatcher Servlet. Although in this case you defined the static resources using <mvc:resources> tag, but your index.html is not resolved properly because it is not rendered as /resources/index.html but /index.html.
I would suggest you to add one more <servlet-mapping> in your web.xml before spring's <servlet-mapping>. For example:
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/index.html</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>admin</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Hope that will work for you.
No that did not resolve the issue. But I saw another thread discussing the same issue and one of the answer there worked. I removed <mvc:resources> line from spring xml and added the below lines in the web.xml
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.js</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.css</url-pattern>
</servlet-mapping>
Now my static content is served without any issues but I don't like this method. It feels like a very dirty hack. Now if I have to serve images, I have to add mapping for each image type. I am not sure whether the spring version is a problem because I use mongodb in the backend with spring data. It took a hell of a time to set up my pom.xml because there were some issues with the spring data version and mongodb driver.

spring MVC servlet mapping

I am trying a sample spring MVC application. My web.xml has
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/test</url-pattern>
</servlet-mapping>
so my question is how I can call my test controller if I just type in the url
http://localhost:8080/MySpringProject/test
Where do i need to make change to call exactly this type of URL so that my test controller called. I don't know what I am asking is correct or not but my requirement is that I don't want to end my UrL with "/" or "test.htm".
Please help and thanks in advance
You usually map your dispatcher servlet to /, and then you have controllers with #RequestMapping("/foo/bar"). But if you define a servlet with a more specific url, it will get picked up.

How to use wildcards in Spring MVC servlet mapping URLs?

I've got a controller set up in my web.xml:
<servlet>
<servlet-name>controller</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>controller</servlet-name>
<url-pattern>/console/index</url-pattern>
</servlet-mapping>
And a matching bean defined in controller-servlet.xml:
<bean name="/console/index" class="com.package.OverviewController"/>
Which works correctly - when I get "/appName/console/index" it behaves as I expect. But when I change web.xml to this:
<servlet>
<servlet-name>controller</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>controller</servlet-name>
<url-pattern>/console/*</url-pattern>
</servlet-mapping>
It no longer functions, giving me the following exception:
WARN (org.springframework.web.servlet.PageNotFound) - No mapping for [/appName/console/index] in DispatcherServlet with name 'controller'
So my question is how do I use wildcards in the servlet mappings, so that different URLs all go through the single DispatcherServlet but may go to one of several controller beans?
FYI: I'm stuck on Spring 2.0, as it's an established application used in government.
When you use wildcards in <url-pattern>, controller names by default correspond to wildcard part of the pattern.
So, you can either rename your controller to /index, or set the alwaysUseFullPath property of your HandlerMapping to true.

Servlet mapping url mapping issue with spring and BIRT

In my application I'm using spring MVC(3.0.5) architecture along with BIRT reporting framework.
I'm trying to serve all requests including the static resources like css, js, html and image files using the spring DispatcherServlet.
For this purpose I added the following entries to my web.xml
<servlet>
<servlet-name>springapp</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
...............
...............
<servlet-mapping>
<servlet-name>springapp</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
This will direct all request to the DispatcherServlet and in my context file I added
<mvc:resources mapping="/css/**" location="/css/" />
<mvc:resources mapping="/docs/**" location="/docs/" />
<mvc:resources mapping="/images/**" location="/images/" />
<mvc:resources mapping="/js/**" location="/js/" />
<mvc:resources mapping="/themes/**" location="/themes/" />
so that these resources will be loaded from the file system.
These configurations are working fine. But I'm facing issues with my BIRT reporting engine now.
The BIRT reporting engine uses some jsp files located in a folder called webcontent which is located at the root of the application. Since we are directing all request to DispatcherServlet even the request for these jsp pages are going to the spring servlet. As I understand from some posts the jsp files are normally handled by org.apache.jasper.servlet.JspServlet which is registered in the Apache Tomcat's web.xml file and it has a servlet mapping as follows
<!-- The mapping for the JSP servlet -->
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>*.jsp</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>*.jspx</url-pattern>
</servlet-mapping>
What are the changes that I should make in my servlet mapping to work in this environment? I need the jsp files to be handled by the default jsp servlet not by the spring servlet. How can I achieve this?
For this post I understood that the second priority in servlet matching is for the url prefix, so my url pattern / for spring servelt is overriding the default jsp servlet mapping, Is this assumption correct? If it is correct then how to overcome this?
Thank you.
The typical mapping of DispatcherServlet is <url-pattern>/</url-pattern>. In this case it still handles all requests except for requests handled by other servlets (in particular, requests to *.jsp), so that it should solve the problem.

Calling servlet results in HTTP Status 404 "The requested resource is not available" [duplicate]

This question already has answers here:
Servlet returns "HTTP Status 404 The requested resource (/servlet) is not available"
(19 answers)
Closed 6 years ago.
I have a servlet register in class p1. I have a JSP jsp1.jsp. I run JSP file and see it, but when I try to apply to the servlet, Tomcat shows an error:
HTTP Status 404
The requested resource (/omgtuk/Register) is not available.
Servlet:
#WebServlet("/register")
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>omgtuk</display-name>
<servlet>
<description></description>
<display-name>register</display-name>
<servlet-name>register</servlet-name>
<servlet-class>p1.register</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>register</servlet-name>
<url-pattern>/register</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>jsp1.jsp</welcome-file>
</welcome-file-list>
</web-app>
I'm using Eclipse.
The requested resource (/omgtuk/Register) is not available.
This simply means that the servlet isn't listening on an URL pattern of /Register. In other words, you don't have a #WebServlet("/Register").
In your particular case, you made a case mistake in the URL. URLs are case sensitive. You're calling /Register, but your servlet is listening on /register. Fix your form action accordingly.
So, it should not look like this:
<form action="Register">
But it should look like this:
<form action="register">
Or this, which is more robust in case you happen to move around JSPs when you're bored:
<form action="${pageContext.request.contextPath}/register">
Unrelated to the concrete problem, please note that you registered the servlet via both a #WebServlet annotation on the class and a <servlet> entry in web.xml. This is not right. You should use the one or the other. The #WebServlet is the new way of registering servlets since Servlet 3.0 (Java EE 6) and the <servlet> is the old way of registering servlets.
Just get rid of the whole <servlet> and <servlet-mapping> in web.xml. You don't need to specify both. Make sure that you're reading up to date books/tutorials. Servlet 3.0 exist since December 2009 already.
Another detail is that p1 is not a class, it's a package. I'd warmly recommend to invest a bit more time in learning basic Java before diving into Java EE.
See also:
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