I'm looking for a way to use DateTime to parse two dates, to show the difference.
I want to have it on the format: "X years, Y months, Z days".
For JS, we have momentjs library and following code::
var a = moment([2015, 11, 29]);
var b = moment([2007, 06, 27]);
var years = a.diff(b, 'year');
b.add(years, 'years');
var months = a.diff(b, 'months');
b.add(months, 'months');
var days = a.diff(b, 'days');
console.log(years + ' years ' + months + ' months ' + days + ' days');
// 8 years 5 months 2 days
Is there similar library available for dart that can help achieve this usecase?
I think it is not possible to do exactly what you want easily with DateTime. Therefore you can use https://pub.dev/packages/time_machine package that is quite powerful with date time handling:
import 'package:time_machine/time_machine.dart';
void main() {
LocalDate a = LocalDate.today();
LocalDate b = LocalDate.dateTime(DateTime(2022, 1, 2));
Period diff = b.periodSince(a);
print("years: ${diff.years}; months: ${diff.months}; days: ${diff.days}");
}
for hours/minutes/seconds precision:
import 'package:time_machine/time_machine.dart';
void main() {
LocalDateTime a = LocalDateTime.now();
LocalDateTime b = LocalDateTime.dateTime(DateTime(2022, 1, 2, 10, 15, 47));
Period diff = b.periodSince(a);
print("years: ${diff.years}; months: ${diff.months}; days: ${diff.days}; hours: ${diff.hours}; minutes: ${diff.minutes}; seconds: ${diff.seconds}");
}
What you are looking for is the Dart DateTime class
You can get close to what you want in moment.js with
main() {
var a = DateTime.utc(2015, 11, 29);
var b = DateTime.utc(2007, 06, 27);
var years = a.difference(b);
print(years.inDays ~/365);
}
There is no inYears or inMonths option for DateTime though that's why the year is divided in the print.
the difference function returns the difference in seconds so you have to process it yourself to days.
You could write an extension on duration class to format it:
extension DurationExtensions on Duration {
String toYearsMonthsDaysString() {
final years = this.inDays ~/ 365
// You will need a custom logic for the months part, since not every month has 30 days
final months = (this.inDays ~% 365) ~/ 30
final days = (this.inDays ~% 365) ~% 30
return "$years years $months months $days days";
}
}
The usage will be:
final date1 = DateTime()
final date2 = DateTime()
date1.difference(date2).toYearsMonthsDaysString()
You can use Jiffy Package for this like this
var jiffy1 = Jiffy("2008-10", "yyyy-MM");
var jiffy2 = Jiffy("2007-1", "yyyy-MM");
jiff1.diff(jiffy2, Units.YEAR); // 1
jiff1.diff(jiffy2, Units.YEAR, true);
You can calculate from the total number of days:
void main() {
DateTime a = DateTime(2015, 11, 29);
DateTime b = DateTime(2007, 06, 27);
int totalDays = a.difference(b).inDays;
int years = totalDays ~/ 365;
int months = (totalDays-years*365) ~/ 30;
int days = totalDays-years*365-months*30;
print("$years $months $days $totalDays");
}
Result is: 8 5 7 3077
I created my own class for Gregorian Dates, and I created a method which handle this issue, it calculates "logically" the difference between two dates in years, months, and days...
i actually created the class from scratch without using any other packages (including DateTime package) but here I used DateTime package to illustrate how this method works.. until now it works fine for me...
method to determine if it's a leap year or no:
static bool leapYear(DateTime date) {
if(date.year%4 == 0) {
if(date.year%100 == 0){
return date.year%400 == 0;
}
return true;
}
return false;
}
this is the method which calculates the difference between two dates in years, months, and days. it puts the result in a list of integers:
static List<int> differenceInYearsMonthsDays(DateTime dt1, DateTime dt2) {
List<int> simpleYear = [31,28,31,30,31,30,31,31,30,31,30,31];
if(dt1.isAfter(dt2)) {
DateTime temp = dt1;
dt1 = dt2;
dt2 = temp;
}
int totalMonthsDifference = ((dt2.year*12) + (dt2.month - 1)) - ((dt1.year*12) + (dt1.month - 1));
int years = (totalMonthsDifference/12).floor();
int months = totalMonthsDifference%12;
late int days;
if(dt2.day >= dt1.day) {days = dt2.day - dt1.day;}
else {
int monthDays = dt2.month == 3
? (leapYear(dt2)? 29: 28)
: (dt2.month - 2 == -1? simpleYear[11]: simpleYear[dt2.month - 2]);
int day = dt1.day;
if(day > monthDays) day = monthDays;
days = monthDays - (day - dt2.day);
months--;
}
if(months < 0) {
months = 11;
years--;
}
return [years, months, days];
}
the method which calculates the difference between two dates in months, and days:
static List<int> differenceInMonths(DateTime dt1, DateTime dt2){
List<int> inYears = differenceInYearsMonthsDays(dt1, dt2);
int difMonths = (inYears[0]*12) + inYears[1];
return [difMonths, inYears[2]];
}
the method which calculates the difference between two dates in days:
static int differenceInDays(DateTime dt1, DateTime dt2) {
if(dt1.isAfter(dt2)) {
DateTime temp = dt1;
dt1 = dt2;
dt2 = temp;
}
return dt2.difference(dt1).inDays;
}
usage example:
void main() {
DateTime date1 = DateTime(2005, 10, 3);
DateTime date2 = DateTime(2022, 1, 12);
List<int> diffYMD = GregorianDate.differenceInYearsMonthsDays(date1, date2);
List<int> diffMD = GregorianDate.differenceInMonths(date1, date2);
int diffD = GregorianDate.differenceInDays(date1, date2);
print("The difference in years, months and days: ${diffYMD[0]} years, ${diffYMD[1]} months, and ${diffYMD[2]} days.");
print("The difference in months and days: ${diffMD[0]} months, and ${diffMD[1]} days.");
print("The difference in days: $diffD days.");
}
output:
The difference in years, months and days: 16 years, 3 months, and 9 days.
The difference in months and days: 195 months, and 9 days.
The difference in days: 5945 days.
the answer is yes, you can easilly achieve it with DateTime class in Dart. See: https://api.dart.dev/stable/2.8.3/dart-core/DateTime-class.html
Example
void main() {
var moonLanding = DateTime(1969,07,20)
var marsLanding = DateTime(2024,06,10);
var diff = moonLanding.difference(marsLanding);
print(diff.inDays.abs());
print(diff.inMinutes.abs());
print(diff.inHours.abs());
}
outputs:
20049
28870560
481176
final firstDate = DateTime.now();
final secondDate = DateTime(firstDate.year, firstDate.month - 20);
final yearsDifference = firstDate.year - secondDate.year;
final monthsDifference = (firstDate.year - secondDate.year) * 12 +
firstDate.month - secondDate.month;
final totalDays = firstDate.difference(secondDate).inDays;
Simple approach, no packages needed.
try intl package with the following code:
import 'package:intl/intl.dart';
String startDate = '01/01/2021';
String endDate = '01/01/2022';
final start = DateFormat('dd/MM/yyyy').parse(startDate);
final end = DateFormat('dd/MM/yyyy').parse(endDate);
Then, you can calculate the duration between the two dates with the following code:
final duration = end.difference(start);
To obtain the number of years, months and days, you can do the following:
final years = duration.inDays / 365;
final months = duration.inDays % 365 / 30;
final days = duration.inDays % 365 % 30;
Finally, you can use these variables to display the result in the desired format:
final result = '${years.toInt()} years ${months.toInt()} months y ${days.toInt()} days';
DateTime difference in years is a specific function, like this:
static int getDateDiffInYear(DateTime dateFrom, DateTime dateTo) {
int sign = 1;
if (dateFrom.isAfter(dateTo)) {
DateTime temp = dateFrom;
dateFrom = dateTo;
dateTo = temp;
sign = -1;
}
int years = dateTo.year - dateFrom.year;
int months = dateTo.month - dateFrom.month;
if (months < 0) {
years--;
} else {
int days = dateTo.day - dateFrom.day;
if (days < 0) {
years--;
}
}
return years * sign;
}
difHour = someDateTime.difference(DateTime.now()).inHours;
difMin = (someDateTime.difference(DateTime.now()).inMinutes)-(difHour*60);
and same for years and days
I want to add offset GMT +05:30 to Time but I don't know how to do that
String offset = data ['utc_offset'].substring(1,);
ntime =ntime.add(Duration(hours:int.parse(offset)));
Since there is " : " in the middle of 05:30 I can't add the exact value..
PS: I'm using http://worldtimeapi.org JSON API
You can parse the offset time by using a RegExp. I have used named groups in my example since I finds it more simple to understand what each part of the regexp are extracting:
import 'dart:io';
void main() {
const offset = '+01:00';
final regexp =
RegExp(r'^(?<plusMinus>[+-]?)(?<hours>[\d]+):(?<minutes>[\d]+)');
final match = regexp.firstMatch(offset);
print(match.namedGroup('plusMinus'));
print(match.namedGroup('hours'));
print(match.namedGroup('minutes'));
final offsetDuration = Duration(
hours: int.parse(match.namedGroup('hours')),
minutes: int.parse(match.namedGroup('minutes')));
DateTime time;
if (match.namedGroup('plusMinus') == '+') {
time = DateTime.now().add(offsetDuration);
} else if (match.namedGroup('plusMinus') == '-') {
time = DateTime.now().subtract(offsetDuration);
} else {
time = DateTime.now();
}
print(time);
}
Is it possible to parse a date and extract the week of month using Joda-Time. I know it is possible to do it for the week of year but I cannot find how/if it is possible to extract the week of month.
Example: 2014-06_03 where 03 is the third week of this month
DateTime dt = new DateTime();
String yearMonthWeekOfMonth = dt.toString("<PATTERN for the week of month>");
I have tried the pattern "yyyyMMW" but it is not accepted.
Current joda-time version doesn't support week of month, so you should use some workaround.
1) For example, you can use next method:
static DateTimeFormatter FORMATTER = DateTimeFormat.forPattern("yyyy-MM_'%d'");
static String printDate(DateTime date)
{
final String baseFormat = FORMATTER.print(date); // 2014-06_%d
final int weekOfMonth = date.getDayOfMonth() % 7;
return String.format(baseFormat, weekOfMonth);
}
Usage:
DateTime dt = new DateTime();
String dateAsString = printDate(dt);
2) You can use Java 8, because Java's API supports week of month field.
java.time.LocalDateTime date = LocalDateTime.now();
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM_W");
System.out.println(formatter.format(date));
This option in Joda is probably nicer:
Weeks.weeksBetween(date, date.withDayOfMonth(1)).getWeeks() + 1
For the case you don't like calculations so much:
DateTime date = new DateTime();
Calendar calendar = Calendar.getInstance();
calendar.setTime(date.toDate());
int weekOfMonth = calendar.get(Calendar.WEEK_OF_MONTH);
If the start day of week is Monday then you can use it:
public int getWeekOfMonth(DateTime date){
DateTime.Property dayOfWeeks = date.dayOfWeek();
return (int) (Math.ceil((date.dayOfMonth().get() - dayOfWeeks.get()) / 7.0)) + 1;
}
Please can anyone provide a method to calculate the difference between 2 hijri dates thanks in advance
i tried this code
HijriCalendar hijriCal=new HijriCalendar();
DateTimeFormatInfo DTFormat = new System.Globalization.CultureInfo("ar-sa", false).DateTimeFormat;
DTFormat.Calendar = new System.Globalization.HijriCalendar();
DTFormat.ShortDatePattern = "dd/MM/yyyy";
string HijriDate = FromDate.Date.ToString("d", DTFormat);
string[] fromDateParams=HijriDate.Split('/');
HijriDate = ToDate.Date.ToString("d", DTFormat);
string[] toDateParams = HijriDate.Split('/');
DateTime fromDateHijri = new DateTime(hijriCal.GetYear(FromDate), hijriCal.GetMonth(FromDate), int.Parse(fromDateParams[0]), hijriCal);
DateTime toDateHijri = new DateTime(hijriCal.GetYear(ToDate), hijriCal.GetMonth(ToDate), int.Parse(toDateParams[0]), hijriCal);
TimeSpan ts = ToDate.Subtract(FromDate);
As long as you just store the dates in normal datetimes, just treat them as any other date.
public TimeSpan GetDifference(this DateTime date1, DateTime date2) {
if (date1 < date2) {
return date2 - date1;
}
else if (date1 > date2) {
return date1 - date2;
}
return new TimeSpan(0);
}
I have to select date from date field in flex and store that date into SqlLite database. I
am inserting date by using this code :
dbInsertDate = datechooser.selectedDate.getFullYear().toString()+'0'+(datechooser.selectedDate.getMonth()+1).toString()+"-0"+datechooser.selectedDate.getDate().toString();
where dbInsertDate is string type variable and datechooser is date field id. It stores the date in database in a format like 2455361.5. I want to store date in either dd-mm-yyyy format or yyyy-mm-dd format in the database. How can i store date in yyyy-mm-dd format in SqlLite using flex ?
Thanks
You can use a DateFormatter:
var formatter:DateFormatter = new DateFormatter();
formatter.formatString = "DD-MM-YYYY";
var result:String = formatter.format(datechooser.selectedDate);
If you use localization you can "translate" the format string to the needed format.
solution: Convert date to string and in yyyy mm dd format
code:
here date will be like this string 2011-02-15
enter code heredateChooser is datefield.
public var dbInsertDate:String;
private var selectedDateByUser:int;
if(dateChooser.selectedDate.getMonth() < 9)
{
if(dateChooser.selectedDate.getDate() < 10)
{
dbInsertDate =
dateChooser.selectedDate.getFullYear().toString()+'-0'+(dateChooser.selectedDate.getMonth()+1).toString()+"-0"+dateChooser.selectedDate.getDate().toString();
}
else
{
dbInsertDate =
dateChooser.selectedDate.getFullYear().toString()+'-0'+(dateChooser.selectedDate.getMonth()+1).toString()+"-"+dateChooser.selectedDate.getDate().toString();
}
else
{
if(dateChooser.selectedDate.getDate() < 10)
{
dbInsertDate =
dateChooser.selectedDate.getFullYear().toString()+'-'+(dateChooser.selectedDate.getMonth()+1).toString()+"-0"+dateChooser.selectedDate.getDate().toString();
}
else
{
dbInsertDate =
dateChooser.selectedDate.getFullYear().toString()+'-'+(dateChooser.selectedDate.getMonth()+1).toString()+"-"+dateChooser.selectedDate.getDate().toString();
}
}
here date will be like this string 20110215. so you can store date in this format at varchar column type in sqqlite.
enter code here
var dateArray:Array = new Array();
dateArray = dbInsertDate.split('-');
selectedDateByUser = dateArray[0]+dateArray[1]+dateArray[2];