How to assert on a number which is comma separated in cypress - automated-tests

While writing tests on an application I have came across a problem.
I need to fetch a number inside a span from the DOM and then assert if the number is between a specific range.
I can do it by using
cy.get('#my_selector').invoke('text').should('be.gt',lower_bound).and('be.lt',upper_bound)
But the issue is the number is comma separated like 5,000. and I'm getting an error as "expected '5,000' to be a number or a date"
Is there any simple short way to convert it into pure numeric

You can use the javascript replace method to remove the comma and then add a + to convert it into a number, like:
cy.get('#my_selector')
.invoke('text')
.then((num) => {
cy.wrap(+num.replace(/,/g, ''))
.should('be.gt', lower_bound)
.and('be.lt', upper_bound)
})

You can use string.replaceAll() to remove the "," then parseInt()
cy.get('#my_selector')
.invoke('text')
.then(str => parseInt(str.replaceAll(',', '')))
.should('be.within', lower_bound, upper_bound)

Related

filter paths that have only one "/" in R using regular expression

I have a vector of different paths such as
levs<-c( "20200507-30g_25d" , "20200507-30g_25d/ggg" , "20200507-30g_25d/grn", "20200507-30g_25d/ylw", "ggg" , "grn", "tre_livelli", "tre_livelli/20200507-30g_25d", "tre_livelli/20200507-30g_25d/ggg", "tre_livelli/20200507-30g_25d/grn", "tre_livelli/20200507-30g_25d/ylw" , "ylw" )
which is actually the output of a list.dirs with recursive set to TRUE.
I want to identify only the paths which have just one subfolder (that is "20200507-30g_25d/ggg" , "20200507-30g_25d/grn", "20200507-30g_25d/ylw").
I thought to filter the vector to find only those paths that have only one "/" and then compare the this with the ones that have more than one "/" to get rid of the partial paths.
I tried with regular expression such as:
rep(levs,pattern='/{1}', value=T)
but I get this:
"20200507-30g_25d/ggg" "20200507-30g_25d/grn" "20200507-30g_25d/ylw" "tre_livelli/20200507-30g_25d" "tre_livelli/20200507-30g_25d/ggg" "tre_livelli/20200507-30g_25d/grn" "tre_livelli/20200507-30g_25d/ylw"
Any idea on how to proceed?
/{1} is a regex that is equal to / and just matches a / anywhere in a string, and there can be more than one / inside it. Please have a look at the regex tag page:
Using {1} as a single-repetition quantifier is harmless but never useful. It is basically an indication of inexperience and/or confusion.
h{1}t{1}t{1}p{1} matches the same string as the simpler expression http (or ht{2}p for that matter) but as you can see, the redundant {1} repetitions only make it harder to read.
You can use
grep(levs, pattern="^[^/]+/[^/]+$", value=TRUE)
# => [1] "20200507-30g_25d/ggg" "20200507-30g_25d/grn" "20200507-30g_25d/ylw" "tre_livelli/20200507-30g_25d"
See the regex demo:
^ - matches the start of string
[^/]+- one or more chars other than /
/ - a / char
[^/]+- one or more chars other than /
$ - end of string.
NOTE: if the parts before or after the only / in the string can be empty, replace + with *: ^[^/]*/[^/]*$.
An option with str_count to count the number of instances of /
library(stringr)
levs[str_count(levs, "/") == 1 ]
-ouptut
[1] "20200507-30g_25d/ggg" "20200507-30g_25d/grn"
[3] "20200507-30g_25d/ylw" "tre_livelli/20200507-30g_25d"

Remove Leading Zero(s) For Each Section Separated by '.' Except When '.0.'

In TSQL I need to create a script to remove all leading zero's between '.', starting with the first 0 in the string EXCEPT when there is a '.0.' anywhere in the middle of the task number. What I have so far does fine when the task number does not have EX: 111.0.123.234, but I cannot seem to figure out the combination of SUBSTRING/CHARINDEX/PATINDEX, etc. to remove all leading zeros except when the zero is the only number between '.' See attached screenshot and script/partial results as an example.
Here is my script:
SELECT TASKPRODUCTID, (CASE WHEN TASKPRODUCTID NOT LIKE '%.0.%' THEN
REPLACE(LTRIM(REPLACE(TASKPRODUCTID,'0','')),' ','0') ELSE
SUBSTRING(TASKPRODUCTID, PATINDEX('%[^0 ]%', TASKPRODUCTID + ' '), LEN(TASKPRODUCTID))
END) AS NewTaskProductID
FROM TASK
Here is a partial resultset:
TASKPRODUCTID NewTaskProductID
003.007.002.001 3.7.2.1
003.007.002.003 3.7.2.3
004.003.003.008.0.2017275.132925 4.003.003.008.0.2017275.132925
004.005.001.003 4.5.1.3
004.005.004.004.0.2017275.135139 4.005.004.004.0.2017275.135139
004.005.007.005.0.2017275.140304 4.005.007.005.0.2017275.140304
002.001.002 2.1.2
002.004 2.4
016.010 16.1
Screenshot Example of leading zero in highlighted rows still have leading zeros in next decimal section(s)
Thank you!!
You could try using the STUFF() to get the .0. in the else case scenario
declare #s AS varchar(100) = '0010.0.005.006025'
print stuff(REPLACE(LTRIM(REPLACE(#s,'0','0')),'0','*'),
patindex('%.*.%',REPLACE(LTRIM(REPLACE(#s,'0','0')),'0','*')), 3,'.-.')
OUTPUT
**1*.-.**5.**6*25
Now treat this as first scenario ; only difference is that we have got '*' instead of '0'

Split a string by a plus sign (+) character

I have a string in a data frame as: "(1)+(2)"
I want to split with delimiter "+" such that I get one element as (1) and other as (2), hence preserving the parentheses. I used strsplit but it does not preserve the parenthesis.
Use
strsplit("(1)+(2)", "\\+")
or
strsplit("(1)+(2)", "+", fixed = TRUE)
The idea of using strsplit("(1)+(2)", "+") doesn't work since unless specified otherwise, the split argument is a regular expression, and the + character is special in regex. Other characters that also need extra care are
?
*
.
^
$
\
|
{ }
[ ]
( )
Below Worked for me:
import re
re.split('\\+', 'ABC+CDE')
Output:
['ABC', 'CDE']

Find word (not containing substrings) in comma separated string

I'm using a linq query where i do something liike this:
viewModel.REGISTRATIONGRPS = (From a In db.TABLEA
Select New SubViewModel With {
.SOMEVALUE1 = a.SOMEVALUE1,
...
...
.SOMEVALUE2 = If(commaseparatedstring.Contains(a.SOMEVALUE1), True, False)
}).ToList()
Now my Problem is that this does'n search for words but for substrings so for example:
commaseparatedstring = "EWM,KI,KP"
SOMEVALUE1 = "EW"
It returns true because it's contained in EWM?
What i would need is to find words (not containing substrings) in the comma separated string!
Option 1: Regular Expressions
Regex.IsMatch(commaseparatedstring, #"\b" + Regex.Escape(a.SOMEVALUE1) + #"\b")
The \b parts are called "word boundaries" and tell the regex engine that you are looking for a "full word". The Regex.Escape(...) ensures that the regex engine will not try to interpret "special characters" in the text you are trying to match. For example, if you are trying to match "one+two", the Regex.Escape method will return "one\+two".
Also, be sure to include the System.Text.RegularExpressions at the top of your code file.
See Regex.IsMatch Method (String, String) on MSDN for more information.
Option 2: Split the String
You could also try splitting the string which would be a bit simpler, though probably less efficient.
commaseparatedstring.Split(new Char[] { ',' }).Contains( a.SOMEVALUE1 )
what about:
- separating the commaseparatedstring by comma
- calling equals() on each substring instead of contains() on whole thing?
.SOMEVALUE2 = If(commaseparatedstring.Split(',').Contains(a.SOMEVALUE1), True, False)

xQuery substring problem

I now have a full path for a file as a string like:
"/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/TRN_282C_HYD_MOD_1_Drive_Shaft_Rev000.xml"
However, now I need to take out only the folder path, so it will be the above string without the last back slash content like:
"/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/"
But it seems that the substring() function in xQuery only has substring(string,start,len) or substring(string,start), I am trying to figure out a way to specify the last occurence of the backslash, but no luck.
Could experts help? Thanks!
Try out the tokenize() function (for splitting a string into its component parts) and then re-assembling it, using everything but the last part.
let $full-path := "/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/TRN_282C_HYD_MOD_1_Drive_Shaft_Rev000.xml",
$segments := tokenize($full-path,"/")[position() ne last()]
return
concat(string-join($segments,'/'),'/')
For more details on these functions, check out their reference pages:
fn:tokenize()
fn:string-join()
fn:replace can do the job with a regular expression:
replace("/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/TRN_282C_HYD_MOD_1_Drive_Shaft_Rev000.xml",
"[^/]+$",
"")
This can be done even with a single XPath 2.0 (subset of XQuery) expression:
substring($fullPath,
1,
string-length($fullPath) - string-length(tokenize($fullPath, '/')[last()])
)
where $fullPath should be substituted with the actual string, such as:
"/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/TRN_282C_HYD_MOD_1_Drive_Shaft_Rev000.xml"
The following code tokenizes, removes the last token, replaces it with an empty string, and joins back.
string-join(
(
tokenize(
"/db/Liebherr/Content_Repository/Techpubs/Topics/HyraulicPowerDistribution/Released/TRN_282C_HYD_MOD_1_Drive_Shaft_Rev000.xml",
"/"
)[position() ne last()],
""
),
"/"
)
It seems to return the desired result on try.zorba-xquery.com. Does this help?

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