I have a XML source schema and an Flat file output schema.
Flat File Destination Schema:
Employee
FName
LName
I want the filename of output file as {LName}_{DateAndTime}. DateAndTime can be added by macros in BizTalk management console.
But can the value of {LNmae} be accessed somwhow?
I got an article to dynamically change the out filename in orchestration but it works for XMLTransit pipeline only.
https://blog.sandro-pereira.com/2009/10/23/biztalk-training-customize-filename-dynamically-inside-orchestration/
Please let me know if it can be achieved in BizTalk.
In an Orchestration or custom Pipeline Component, set the value of FILE.ReceivedFileName to your desired value: "Smith_02FEB19.txt".
Then you can use the %SourceFileName% Macro on the FILE or FTP Adapter to create the outfile with that name.
Related
I want to load flat file which is ~ delimited but doesn't any header into Snowflake table using informatica cloud integration service.
Just wanted to know how to add header to source file or any turn around in order to map fields in fields mapping option in target .Please find below screenshot. Not able to figure it out which field in source will be mapped in target table as source file does not have headers.
need to run a workflow where the session has source and target variables which will be feeded the value through PMCMD command.is it possible
You cannot directly pass the source and target table names, but you can parameterize those names and put those in parameter file. Then you can pass the parameter file path in pmcmd.
You cannot have source and target names in PMCMD command
Instead create a parameter file and provide the source and target names using the
parameter identifiers like $DBConnection_Src= and $DBConnection_Tgt=
Have below format,
[Folder_Naem.WF:Workflow_Name.ST:SessionName]
$DBConnection_Src=Source_Name
$DBConnection_Tgt=Target_Name
Create this parameter file and provide the path and file name,
In the mapping tab for source and target provide the parameters specified in the parameter file
Parameter file is very helpful for dynamic parameter changes. You can edit the parameter file rather than making changes in the informatica workflow
My file contains data like:
First name: ahmed
Last name: nasser
City: giza
i created a schema to parse this file, but the element store all the line.. such as
<Fname>First name: ahmed</Fname>
<Lname>Last name: nasser</Lname>
i want the element to store only the value without the label
..to be like this:
<Fname>ahmed</Fname>
<Lname>nasser</Lname>
How To do that using Flate File Schema.. BizTalk?
Biztalk Flat File Schema Wizard will help you. You can use this text file you copied into the question as "Instance file" (1. page of the wizard). Tell the wizard that this file is a delimited one (3. page of the wizard) and the delimiter is ":" (4. page of the wizard). On the 5. page of the wizard you can set the labels to be ignored and that's all.
If the records of the input flat file are present in one line, I think the best if you simply remove the labels from the file. You can do this by creating a custom pipeline component, using C# it is super easy. After removing the labels your file will consist of pure data separated by : , which is a good format for a flat file schema.
Good afternoon,
I'm trying to set the output file name in a send port and the available file name macros won't quite work.
I need something of the form "file.YYYYMMDD_HHMMSS". There's a datetime combined macro (with the wrong format), a time only macro, but no date only macro.
I don't have an orchestration for this process.
Is there any way I can set the file name from within a map or a pipeline?
Thanks!
You can achieve filename in this format YYYYMMDD_HHMMSS using following.
Use expression shape in orchestration and create four variables.
varDateTime=System.DateTime.Now; //varDateTime is datetime type
strDate=varDateTime.ToString("yyyyMMdd"); //strDate is string type
strTime=varDateTime.ToString("HHmmss"); //strTime is string type
outboundfilename= ""+strDate + " _ " +strTime +" "; //outboundfilename is the string variable.
Use the following code in Message Assignment Shape
msgOutbound(FILE.ReceivedFileName)=outboundfilename+".xml";
//File extension can be any based on your requirement. I have xml file type.
You don't need custom pipeline to do this.
You can do it with a custom pipeline or an orchestration but not with a map. Info on building a custom pipeline can be found here:
BizTalk MSDN Blogs
This can be set by setting the FILE.ReceivedFileName (instead of BTS.ReceiveFileName).
You can create a custom pipeline component to be placed on the send side (say encode stage), and then set the BTS.ReceiveFileName property to the custom file name value that needs to be set.
After this is done, you can use the %SourceFileName% macro in the Send Port. You can also refer to this MSDN forum link for more details
I am creating an xml file. I need to check first if the file exists or not. If the file does not exist, create it and add the data cmg from a .cs file.
If the file exists, don't create the file just add the data cmg from a .cs file.
My code looks like this:
string filename="c:\\employee.xml";
XmlTextWriter tw=new XmlTextWriter(filename,null);//null represents
the Encoding Type//
tw.Formatting=Formatting.Indented; //for xml tags to be indented//
tw.WriteStartDocument(); //Indicates the starting of document (Required)//
tw.WriteStartElement("Employees");
tw.WriteStartElement("Employee","Genius");
tw.WriteStartElement("EmpID","1");
tw.WriteAttributeString("Name","krishnan");
tw.WriteElementString("Designation","Software Developer");
tw.WriteElementString("FullName","krishnan Lakshmipuram Narayanan");
tw.WriteEndElement();
tw.WriteEndElement();
tw.WriteEndDocument();
tw.Flush();
tw.Close();
so next time we add data to file we need to check if the file exits and add data to xml file
and as we have made empID as a primary key, if user tries to make duplicate entry we need to avoid
Is this possible to do?
if (!File.Exists(filename))
{
// create your file
}
or
if (File.Exists(filename))
{
File.Delete(filename);
}
// then create your file
File class is in System.IO namespace (add using System.IO; to your file)
You can't append records to an XML file, you have to read the file and then rewrite it.
So, just check if the file exists, and read the records from it. Then write the file including all previous records and the new record.
Have a look at the File.Exists method here
Testing for existance of a file before attempting to create it inherently is subject to a "things change after check" race condition. Who can guarantee you that your application isn't preempted and put to sleep for a moment after you checked, someone else creates/deletes that file, your app gets to run again and does exactly the opposite of what you intended ?
Windows (as well as all UN*X variants) supports file open/create modes that allow to perform that create-if-nonexistant/open-if-existant operation as a single call.
As far as .NET goes, this means for your task (create an XML file) you'd first create a System.IO.FileStream with the appropriate modes, see http://msdn.microsoft.com/en-us/library/system.io.filemode.aspx and then pass that stream to the XmlWriter constructor. That's safer than simply performing an "exists" check and hoping for the best.