I have a table like this:
customer ID startdate enddate
11 22 2015-01-01 2015-03-01
11 55 2018-04-03 2018-06-16
22 33 2017-02-01 2017-04-01
And This is the output I want:
customer Id YearMonth
11 22 201501
11 22 201502
11 22 201503
11 55 201804
11 55 201805
11 55 201806
22 33 201702
22 33 201703
22 33 201704
22 33 201505
I've Started writing this function:
datseq<-function(t1,t2) {
seq(as.Data(t1), as.Date(t2), by="month")
}
My Questions are:
a. How can I correct the function to return me YYYYMM format?
b. How can I implemnt this function on the dataframe in order that each customer and id will get the appropriate list of months? The output should be a dataframe.
Thank you
We can do this with data.table, group by the sequence of rows, create a sequence from the 'startdate' to 'enddate', specifying the by as monthly and format the Date class to return the expected format ("%Y%m")
library(data.table)
setDT(df1)[, .(customer = customer[1], Id = ID[1],
YearMonth = format(seq(startdate, enddate, by = '1 month'), "%Y%m")),
by = 1:nrow(df1)]
This can also be done with tidyverse
library(tidyverse)
df1 %>%
mutate(YearMonth = map2(startdate, enddate,
~ seq(.x, .y, by = "1 month") %>%
format(., format = "%Y%m"))) %>%
select(-startdate, enddate) %>%
unnest
If we need a base R, option, then Map can be used
lst <- Map(function(x, y) seq(x, y, by = '1 month'), df1$startdate, df1$enddate)
Replicate the rows of the dataset by the lengths of the list, and create a column 'YearMonth' by concatenating the list elements and then getting the expected format
data.frame(df1[rep(1:nrow(df1), lengths(lst)), 1:2],
YearMonth = format(do.call(c, lst), "%Y%m"))
Related
I have a database containing a list of events. Each event has an associated start date, and a date when the event ended or was completed, eg:
dataset <- tibble(
eventid = sample(1:100, 25, replace=TRUE),
start_date = sample(seq(as.Date('2011/01/01'), as.Date('2012/01/01'), by="day"), 25),
completed_date = sample(seq(as.Date('2012/01/01'), as.Date('2014/01/01'), by="day"), 25)
)
> dataset
# A tibble: 25 x 3
eventid start_date completed_date
<int> <date> <date>
1 57 2011-01-14 2013-01-07
2 97 2011-01-21 2011-03-03
3 58 2011-01-26 2011-02-05
4 25 2011-03-22 2013-07-20
5 8 2011-04-20 2012-07-16
6 81 2011-04-26 2013-03-04
7 42 2011-05-02 2012-01-16
8 77 2011-05-03 2012-08-14
9 78 2011-05-21 2013-09-26
10 49 2011-05-22 2013-01-04
# ... with 15 more rows
>
I am trying to produce a rolling "snapshot" of how many tasks were pending a different points in time, e.g. month by month. Expected result:
# A tibble: 25 x 2
month count
<date> <int>
1 2011-01-01 0
2 2011-02-01 3
3 2011-03-01 2
4 2011-04-01 2
5 2011-05-01 4
6 2011-06-01 8
I have attempted to group my variables using group_by(period=floor_date(start_date,"month")), but I'm a bit stuck and would appreciate a pointer in the right direction!
I would prefer a solution using dplyr if possible.
Thanks!
You can expand rows for each month included in the range of dates with map2 from purrr. map2 will iterate over multiple inputs simultaneously. In this case, it will iterate through the start and end dates at the same time.
In each iteration, if will create a monthly sequence using seq (or seq.Date) from start to end month (determined from floor_date). The result is nested for each row of data (since one row can have multiple months in the sequence). So, unnest is needed afterwards.
The transmute will add a new variable called month_year (and drop the old ones) and use substr to extract the year and month only (no day). This is the first through seventh character of the date.
Then, you can group_by the month-year and count up the number of pending projects for each month_year.
I included set.seed to reproduce from data below.
library(dplyr)
library(tidyr)
library(purrr)
library(lubridate)
dataset %>%
mutate(month = map2(floor_date(start_date, "month"),
floor_date(completed_date, "month"),
seq.Date,
by = "month")) %>%
unnest(month) %>%
transmute(month_year = substr(month, 1, 7)) %>%
group_by(month_year) %>%
summarise(count = n())
Output
month_year count
<chr> <int>
1 2011-01 1
2 2011-02 3
3 2011-03 9
4 2011-04 10
5 2011-05 13
6 2011-06 15
7 2011-07 16
8 2011-08 18
9 2011-09 19
10 2011-10 20
# … with 22 more rows
If you want to exclude the completed month (except when start month and completed month are the same, if that can exist), you can subtract 1 month from the sequence of months created. In this case, you can use pmax so that if both start and end months are the same, it will still count the month).
Here is the modified mutate with map2:
mutate(month = map2(floor_date(start_date, "month"),
pmax(floor_date(completed_date, "month") - 1, floor_date(start_date, "month")),
seq.Date,
by = "month"))
Data
set.seed(123)
dataset <- tibble(
eventid = sample(1:100, 25, replace=TRUE),
start_date = sample(seq(as.Date('2011/01/01'), as.Date('2012/01/01'), by="day"), 25),
completed_date = sample(seq(as.Date('2012/01/01'), as.Date('2014/01/01'), by="day"), 25)
)
I have a csv file that is written like this
Date Data
1/5/1980 25
1/7/1980 30
2/13/1980 44
4/13/1980 50
I'd like R to produce something like this
Date Date
1/1/1980
1/2/1980
1/3/1980
1/4/1980
1/5/1980 25
1/6/1980
1/7/1980 30
Then I would like R to bring the last observation forward like this
Date Date
1/1/1980
1/2/1980
1/3/1980
1/4/1980
1/5/1980 25
1/6/1980 25
1/7/1980 30
I'd like two separate data.tables created one with just the actual data, then another with the last observation brought forward.
Thanks for all the help!
Edit: I also will need any NA's that are populated to changed to 0
You could also use tidyverse:
library(tidyverse)
df %>%
mutate(Date = as.Date(Date, "%m/%d/%Y")) %>%
complete(Date = seq(as.Date(format(min(Date), "%Y-%m-01")), max(Date), by = "day")) %>%
fill(Data) %>%
replace(., is.na(.), 0)
First 10 rows:
# A tibble: 104 x 2
Date Data
<date> <dbl>
1 1980-01-01 0
2 1980-01-02 0
3 1980-01-03 0
4 1980-01-04 0
5 1980-01-05 25
6 1980-01-06 25
7 1980-01-07 30
8 1980-01-08 30
9 1980-01-09 30
10 1980-01-10 30
I've used as a starting point the 1st day of the month and year of minimum date, and maximum the maximum date; this can be of course adjusted as needed.
EDIT: #Sotos has an even better suggestion for a more concise approach (by better usage of format argument):
df %>%
mutate(Date = as.Date(Date, "%m/%d/%Y")) %>%
complete(Date = seq(as.Date(format(min(Date), "%Y-%m-01")), max(Date), by = "day")) %>%
fill(Data)
The solution is:
create a data.frame with successive date
merge it with your original data.frame
use na.locf function from zoo to carry forward your data
Here is the code. I use lubridate to work with date.
library(lubridate)
df$Date <- mdy(df$Date)
successive <-data.frame(Date = seq( as.Date(as.yearmon(df$Date[1])), df$Date[length(df$Date)], by="days"))
successive is the vector of successive dates. Now the merging:
result <- merge(df,successive,all.y = T,on = "Date")
And the forward propagation:
library(zoo)
result$Data <- na.locf(result$Data,na.rm = F)
Date Data
1 1980-01-05 25
2 1980-01-06 25
3 1980-01-07 30
4 1980-01-08 30
5 1980-01-09 30
6 1980-01-10 30
7 1980-01-11 30
8 1980-01-12 30
9 1980-01-13 30
10 1980-01-14 30
11 1980-01-15 30
12 1980-01-16 30
13 1980-01-17 30
14 1980-01-18 30
15 1980-01-19 30
16 1980-01-20 30
17 1980-01-21 30
18 1980-01-22 30
19 1980-01-23 30
20 1980-01-24 30
21 1980-01-25 30
The data:
df <- read.table(text = "Date Data
1/5/1980 25
1/7/1980 30
2/13/1980 44
4/13/1980 50", header = T)
Assuming that the result should start at the first of the month of the first date and end at the last date and that the input data frame is DF shown reproducibly in the Note at the end, convert DF to a zoo object z, create a grid of dates g merge them to give zoo objects z0 (with zero filling) and zz (with na.locf filling) and optionally convert back to data frames or else just leave it as is so you can use zoo for further processing.
library(zoo)
z <- read.zoo(DF, header = TRUE, format = "%m/%d/%Y")
g <- seq(as.Date(as.yearmon(start(z))), end(z), "day")
z0 <- merge(z, zoo(, g), fill = 0) # zero filled
zz <- na.locf0(merge(z, zoo(, g))) # na.locf filled
# optional
DF0 <- fortify.zoo(z0) # zero filled
DF2 <- fortify.zoo(zz) # na.locf filled
data.table
The question mentions data tables and if that refers to the data.table package then add:
library(data.table)
DT0 <- data.table(DF0) # zero filled
DT2 <- data.table(DF2) # na.locf filled
Variations
I wasn't clear on whether the question was asking for a zero filled answer and an na.locf filled answer or just an na.locf filled answer whose remaining NA values are 0 filled but assumed the former case. If you want to fill the NAs that are left in the na.locf filled answer then add:
zz[is.na(zz)] <- 0
If you want to end at the end of the last month rather than at the last date replace end(z) with as.Date(as.yearmon(end(z)), frac = 1) .
If you want to start at the first date rather than the first of the month of the first date replace as.Date(as.yearmon(start(z))) with start(z)
.
As an alternative to (3), to start at the first date and end at the last date we could simply convert to ts and back. Note that we need to restore Date class on the second line below since ts class cannot handle Date class directly.
z2.na <- as.zoo(as.ts(z))
time(z2.na) <- as.Date(time(z2.na))
zz20 <- replace(z2.na, is.na(z2.na), 0) # zero filled
zz2 <- na.locf0(z2.na) # na.locf filled
Note
Lines <- "
Date Data
1/5/1980 25
1/7/1980 30
2/13/1980 44
4/13/1980 50"
DF <- read.table(text = Lines, header = TRUE)
I am using a dataset which is grouped by group_by function of dplyr package.
Each Group has it's own time index which i.e. supposedly consist of 12 months sequences.
This means that it can start from January and end up in December or in other cases it can start from June of the year before and end up in May next year.
Here is the dataset example:
ID DATE
8 2017-01-31
8 2017-02-28
8 2017-03-31
8 2017-04-30
8 2017-05-31
8 2017-06-30
8 2017-07-31
8 2017-08-31
8 2017-09-30
8 2017-10-31
8 2017-11-30
8 2017-12-31
32 2017-01-31
32 2017-02-28
32 2017-03-31
32 2017-04-30
32 2017-05-31
32 2017-06-30
32 2017-07-31
32 2017-08-31
32 2017-09-30
32 2017-10-31
32 2017-11-30
32 2017-12-31
45 2016-09-30
45 2016-10-31
45 2016-11-30
45 2016-12-31
45 2017-01-31
45 2017-02-28
45 2017-03-31
45 2017-04-30
45 2017-05-31
45 2017-06-30
45 2017-07-31
45 2017-08-31
The Problem is that I can't confirm or validate visualy because of dataset dimensions if there are so called "jumps", in other words if dates are consistent. Is there any simple way in r to do that, perhaps some modification/combination of functions from tibbletime package.
Any help will by appreciated.
Thank you in advance.
Here's how I would typically approach this problem using data.table -- the cut.Date() and seq.Date() functions from base are the meat of the logic, so you use the same approach with dplyr if desired.
library(data.table)
## Convert to data.table
setDT(df)
## Convert DATE to a date in case it wasn't already
df[,DATE := as.Date(DATE)]
## Order by ID and Date
setkey(df,ID,DATE)
## Create a column with the month of each date
df[,Month := as.Date(cut.Date(DATE, breaks = "months"))]
## Generate a sequence of Dates by month for the number of observations
## in each group -- .N
df[,ExpectedMonth := seq.Date(from = min(Month),
by = "months",
length.out = .N), by = .(ID)]
## Create a summary table to test whether an ID had 12 observations where
## the actual month was equal to the expected month
Test <- df[Month == ExpectedMonth, .(Valid = ifelse(.N == 12L,TRUE,FALSE)), by = .(ID)]
print(Test)
# ID Valid
# 1: 8 TRUE
# 2: 32 TRUE
# 3: 45 TRUE
## Do a no-copy join of Test to df based on ID
## and create a column in df based on the 'Valid' column in Test
df[Test, Valid := i.Valid, on = "ID"]
## The final output:
head(df)
# ID DATE Month ExpectedMonth Valid
# 1: 8 2017-01-31 2017-01-01 2017-01-01 TRUE
# 2: 8 2017-02-28 2017-02-01 2017-02-01 TRUE
# 3: 8 2017-03-31 2017-03-01 2017-03-01 TRUE
# 4: 8 2017-04-30 2017-04-01 2017-04-01 TRUE
# 5: 8 2017-05-31 2017-05-01 2017-05-01 TRUE
# 6: 8 2017-06-30 2017-06-01 2017-06-01 TRUE
You could also do things a little more compactly if you really wanted to using a self-join and skip creating Test
setDT(df)
df[,DATE := as.Date(DATE)]
setkey(df,ID,DATE)
df[,Month := as.Date(cut.Date(DATE, breaks = "months"))]
df[,ExpectedMonth := seq.Date(from = min(Month), by = "months", length.out = .N), keyby = .(ID)]
df[df[Month == ExpectedMonth,.(Valid = ifelse(.N == 12L,TRUE,FALSE)),keyby = .(ID)], Valid := i.Valid]
You can use the summarise function from dplyr to return a logical value of whether there are any day differences greater than 31 within each ID. You do this by first constructing a temporary date using only the year and month and attaching "-01" as the fake day:
library(dplyr)
library(lubridate)
df %>%
group_by(ID) %>%
mutate(DATE2 = ymd(paste0(sub('\\-\\d+$', '', DATE),'-01')),
DATE_diff = c(0, diff(DATE2))) %>%
summarise(Valid = !any(DATE_diff > 31))
Result:
# A tibble: 3 x 2
ID Valid
<int> <lgl>
1 8 TRUE
2 32 TRUE
3 45 TRUE
You can also visually check if there are any gaps by plotting your dates for each ID:
library(ggplot2)
df %>%
mutate(DATE = ymd(paste0(sub('\\-\\d+$', '', DATE),'-01')),
ID = as.factor(ID)) %>%
ggplot(aes(x = DATE, y = ID, group = ID)) +
geom_point(aes(color = ID)) +
scale_x_date(date_breaks = "1 month",
date_labels = "%b-%Y") +
labs(title = "Time Line by ID")
Given a column of dates, this will count the number of records in each month
library(dplyr)
library(lubridate)
samp <- tbl_df(seq.Date(as.Date("2017-01-01"), as.Date("2017-12-01"), by="day"))
freq <- samp %>%
filter(!is.na(value)) %>%
transmute(month = floor_date(value, "month")) %>%
group_by(month) %>% summarise(adds = n())
freq
# A tibble: 12 x 2
month adds
<date> <int>
1 2017-01-01 31
2 2017-02-01 28
3 2017-03-01 31
4 2017-04-01 30
5 2017-05-01 31
6 2017-06-01 30
7 2017-07-01 31
8 2017-08-01 31
9 2017-09-01 30
10 2017-10-01 31
11 2017-11-01 30
12 2017-12-01 1
>
I would like to convert this to a function, so that I can perform the operation on a number of variables. Have read the vignette on dplyr programming, but continue to have issues.
My attempt;
library(rlang)
count_x_month <- function(df, var, name){
var <- enquo(var)
name <- enquo(name)
df %>%
filter(!is.na(!!var)) %>%
transmute(month := floor_date(!!var, "month")) %>%
group_by(month) %>% summarise(!!name := n())
}
freq2 <- samp %>% count_x_month(value, out)
Error message;
Error: invalid argument type
Making this version of the function work will be a big help. More broadly, other ways to achieve the objective would be welcome.
One way to state the problem; given a dataframe of customers and first purchase dates, count the number of customers purchasing for the first time in each month.
update: The selected answer works in dplyr 0.7.4, but the rstudio environment I have access to has dplyr 0.5.0. What modifications are required to 'backport' this function?
You forgot to quo_name it
library(rlang)
count_x_month <- function(df, var, name){
var <- enquo(var)
name <- enquo(name)
name <- quo_name(name)
df %>%
filter(!is.na(!!var)) %>%
transmute(month := floor_date(!!var, "month")) %>%
group_by(month) %>%
summarise(!!name := n())
}
freq2 <- samp %>% count_x_month(value, out)
# A tibble: 12 x 2
month out
<date> <int>
1 2017-01-01 31
2 2017-02-01 28
3 2017-03-01 31
4 2017-04-01 30
5 2017-05-01 31
6 2017-06-01 30
7 2017-07-01 31
8 2017-08-01 31
9 2017-09-01 30
10 2017-10-01 31
11 2017-11-01 30
12 2017-12-01 1
See "Different input and output variable" section of "Programming with dplyr":
We create the new names by pasting together strings, so we need
quo_name() to convert the input expression to a string.
The error is caused by summarise(df, !!name := n()) and is solved by replacing the second line of the function with
name <- substitute(name)
The reason, as far as I understand it is, that a quosure is not only its name, but it carries with it the environment from where it came. This makes sense when specifying column names in functions. The function must know from which data frame (=environment in this case) the column comes to replace the name with the values.
However, name shall take a new name, specified by the user. There is nothing to replace it with. I suspect if using name <- enquo(name), R wants to replace !!name by values instead of just putting in the new name. Therefore it complains that on the LHS there is no name (because R replaced it by values(?))
Not sure though if substitute is the ideomatic "programming with dplyr" way though. Comments are welcome.
Create a dataframe showing customer IDs and first purchase dates:
dates <- seq.Date(as.Date("2017-01-01"), as.Date("2017-12-01"), by="day")
dates_rep <- c(dates,dates,dates)
cust_ids <- paste('id_', floor(runif(length(dates_rep), min=0, max=100000)))
cust_frame <- data.frame(ID=cust_ids, FP_DATE=dates_rep)
head(cust_frame)
Use the plyr package to aggregate by FP_DATE:
library(plyr)
count(cust_frame, c('FP_DATE'))
Therefore, given a dataframe of customers and first purchase dates, we get a count of the number of customers purchasing for the first time in each month.
You can extend this to aggregate across any number of features in your dataset:
count(cust_frame, c('FP_DATE', 'feature_b', 'feature_c', 'feature_d', 'feature_e'))
I have a "date" vector, that contains dates in mm/dd/yyyy format:
head(Entered_Date,5)
[1] 1/5/1998 1/5/1998 1/5/1998 1/5/1998 1/5/1998
I am trying to plot a frequency variable against the date, but I want to group the dates that it is by month or year. As it is now, there is a frequency per day, but I want to plot the frequency by month or year. So instead of having a frequency of 1 for 1/5/1998, 1 for 1/7/1998, and 3 for 1/8/1998, I would like to display it as 5 for 1/1998. It is a relatively large data set, with dates from 1998 to present, and I would like to find some automated way to accomplish this.
> dput(head(Entered_Date))
structure(c(260L, 260L, 260L, 260L, 260L, 260L), .Label = c("1/1/1998",
"1/1/1999", "1/1/2001", "1/1/2002", "1/10/2000", "1/10/2001",
"1/10/2002", "1/10/2003", "1/10/2005", "1/10/2006", "1/10/2007",
"1/10/2008", "1/10/2011", "1/10/2012", "1/10/2013", "1/11/1999",
"1/11/2000", "1/11/2001", "1/11/2002", "1/11/2005", "1/11/2006",
"1/11/2008", "1/11/2010", "1/11/2011", "1/11/2012", "1/11/2013",
"1/12/1998", "1/12/1999", "1/12/2001", "1/12/2004", "1/12/2005", ...
The floor_date() function from the lubridate package does this nicely.
data %>%
group_by(month = lubridate::floor_date(date, "month")) %>%
summarize(summary_variable = sum(value))
Thanks to Roman Cheplyaka
https://ro-che.info/articles/2017-02-22-group_by_month_r
See more on how to use the function: https://lubridate.tidyverse.org/reference/round_date.html
Here is an example using dplyr. You simply use the corresponding date format string for month %m or year %Y in the format statement.
set.seed(123)
df <- data.frame(date = seq.Date(from =as.Date("01/01/1998", "%d/%m/%Y"),
to=as.Date("01/01/2000", "%d/%m/%Y"), by="day"),
value = sample(seq(5), 731, replace = TRUE))
head(df)
date value
1 1998-01-01 2
2 1998-01-02 4
3 1998-01-03 3
4 1998-01-04 5
5 1998-01-05 5
6 1998-01-06 1
library(dplyr)
df %>%
mutate(month = format(date, "%m"), year = format(date, "%Y")) %>%
group_by(month, year) %>%
summarise(total = sum(value))
Source: local data frame [25 x 3]
Groups: month [?]
month year total
(chr) (chr) (int)
1 01 1998 105
2 01 1999 91
3 01 2000 3
4 02 1998 74
5 02 1999 77
6 03 1998 96
7 03 1999 86
8 04 1998 91
9 04 1999 95
10 05 1998 93
.. ... ... ...
Just to add to #cdeterman answer, you can use lubridate along with dplyr to make this even easier:
df <- data.frame(date = seq.Date(from =as.Date("01/01/1998", "%d/%m/%Y"),
to=as.Date("01/01/2000", "%d/%m/%Y"), by="day"),
value = sample(seq(5), 731, replace = TRUE))
library(dplyr)
library(lubridate)
df %>%
mutate(month = month(date), year = year(date)) %>%
group_by(month, year) %>%
summarise(total = sum(value))
Maybe you just add a column in your data like this:
Year <- format(as.Date(Entered_Date, "%d/%m/%Y"), "%Y")
Dont need dplyr. Look at ?as.POSIXlt
df$date<-as.POSIXlt(df$date)
mon<-df$date$mon
yr<-df$date$year
monyr<-as.factor(paste(mon,yr,sep="/"))
df$date<-monyr
Don't need to use ggplot2 but its nice for this kind of thing.
c <- ggplot(df, aes(factor(date)))
c + geom_bar()
If you want to see the actual numbers
aggregate(. ~ date,data = df,FUN=length )
df2<-aggregate(. ~ date,data = df,FUN=length )
df2
date value
1 0/98 31
2 0/99 31
3 1/98 28
4 1/99 28
5 10/98 30
6 10/99 30
7 11/97 1
8 11/98 31
9 11/99 31
10 2/98 31
11 2/99 31
12 3/98 30
13 3/99 30
14 4/98 31
15 4/99 31
16 5/98 30
17 5/99 30
18 6/98 31
19 6/99 31
20 7/98 31
21 7/99 31
22 8/98 30
23 8/99 30
24 9/98 31
25 9/99 31
There is a super easy way using the cut() function:
list = as.Date(c("1998-5-2", "1993-4-16", "1998-5-10"))
cut(list, breaks = "month")
and you will get this:
[1] 1998-05-01 1993-04-01 1998-05-01
62 Levels: 1993-04-01 1993-05-01 1993-06-01 1993-07-01 1993-08-01 ... 1998-05-01
Another solution is slider::slide_period:
library(slider)
library(dplyr)
monthly_summary <- function(data) summarise(data, date = format(max(date), "%Y-%m"), value = sum(value))
slide_period_dfr(df, df$date, "month", monthly_summary)
date value
1 1998-01 92
2 1998-02 82
3 1998-03 113
4 1998-04 94
5 1998-05 92
6 1998-06 74
7 1998-07 89
8 1998-08 92
9 1998-09 91
10 1998-10 100
...
There is also group_by(month_yr = cut(date, breaks = "1 month") in base R, without needing to use lubridate or other packages.