I made a multicolor border :
https://codepen.io/Niavl/pen/vpmvmL
body {
background: #333;
}
.my-div {
text-align: center;
position: relative;
line-height: 100px;
background: #fff;
height: 100px;
width: 100%;
}
/*border bottom*/
.my-div:after {
background: linear-gradient(to right, transparent 45%, #87c846 45%, #87c846 60%, #e32b2d 60%, #e32b2d 70%, #ffc846 70%, #ffc846 95%, #847c6c 95%);
position: absolute;
content: '';
height: 20px;
right: 0;
left: 0;
bottom: -20px;
}
<div class="my-div">
hello
</div>
I use for that css linear-gradient.
It works but it is not clean especially on chrome: There is blur between 2 colors.
Any idea to make it cleaner ?
Related
In the mockup I have, the stripes have a gradient opacity effect from transparent to semi-transparent.
Currently, I have this:
How do I make it so that the white stripes have the transparency gradient?
Here is my current code.
body {
background: gray;
}
.bar {
height: 50px;
width: 100%;
background-image: linear-gradient(90deg, #FC0252 0%, #01Fdd9 100%);
border-radius: 100rem;
position: relative;
}
/** Stripes. */
.bar::before {
content: "";
position: absolute;
border-radius: 100rem;
height: 100%;
width: 100%;
background-size: 90px 100%;
background-image: linear-gradient(
120deg,
transparent,
transparent 40%,
white 40%,
white 60%,
transparent 60%
);
}
<div class="bar"></div>
You can add a mask layer on the pseudo-element:
body {
background: gray;
}
.bar {
height: 50px;
width: 100%;
background-image: linear-gradient(90deg, #FC0252 0%, #01Fdd9 100%);
border-radius: 100rem;
position: relative;
}
/** Stripes. */
.bar::before {
content: "";
position: absolute;
border-radius: 100rem;
height: 100%;
width: 100%;
background-size: 90px 100%;
background-image: linear-gradient( 120deg, transparent 40%, white 41% 60%, transparent 61%);
-webkit-mask:linear-gradient(white,transparent);
mask:linear-gradient(white,transparent);
}
<div class="bar"></div>
In case you need better browser support than masks provide, I'd do something with an additional container, but overall it's a funny looking progress bar, hope it's for a kids game or something.
body {
background: gray;
padding-top: 5rem;
}
.bar-container {
border-radius: 100rem;
overflow: hidden;
border: darkgray 2px solid;
box-shadow: 0 2px 8px rgba(0,0,0,.5);
background-image: linear-gradient(90deg, #FC0252 0%, #01Fdd9 100%);
}
.bar {
height: 50px;
width: 100%;
position: relative;
background-size: 90px 100%;
background-image: linear-gradient(
120deg,
transparent,
transparent 40%,
white 40%,
white 60%,
transparent 60%
);
}
.bar::before, .bar::after {
content: "";
position: absolute;
top: 0;
bottom: 0;
width: 50%;
}
.bar::before {
left: 0;
background: linear-gradient(45deg, rgba(252,2,82,1) 0%, rgba(0,0,0,0) 50%);
}
.bar::after {
right: 0;
background: linear-gradient(-45deg, rgba(1,253,217,1) 0%, rgba(0,0,0,0) 50%);
}
<div class="bar-container">
<div class="bar"></div>
</div>
How to replicate this image in css to serve as a background for text?
(It's kind of hard to see but they're individual squares, not dots.)
The squares should be transparent as well.
Also it is possible to code it to control the opacity of each horizontal line of squares in css?
1. Here's one way of doing it using pseudo-elements, adjust the values to your liking:
Snippet:
html, body { margin: 0; padding: 0; width: 100%; height: 100%; }
.checkered-bg {
width: 100%;
height: 100%;
color: white;
}
.checkered-bg::before, .checkered-bg::after {
content: "";
width: 100%;
height: 100%;
position: absolute;
top: 0;
left: 0;
pointer-events: none;
z-index: -1;
}
.checkered-bg::before {
background-image:
linear-gradient(black 50%, transparent 50%),
linear-gradient(to right, grey 50%, black 50%);
background-size: 20px 20px;
}
.checkered-bg::after {
background-image: linear-gradient(black, transparent);
}
<div class="checkered-bg">CONTENT</div>
View on JSfiddle.
2. Another way to make the squares and have the area around them transparent. But in order to get the top rows more translucent you will need a solid color:
html, body { margin: 0; padding: 0; width: 100%; height: 100%; }
.checkered-bg {
width: 100%;
height: 100%;
color: black;
}
.checkered-bg::before, .checkered-bg::after {
content: "";
width: 100%;
height: 100%;
position: absolute;
top: 0;
left: 0;
pointer-events: none;
z-index: -1;
}
.checkered-bg::before {
background-image:
linear-gradient(45deg, #808080 25%, transparent 25%),
linear-gradient(45deg, transparent 75%, #808080 75%);
background-size:20px 20px;
background-position:0 0, -10px -10px;
}
.checkered-bg::after {
background-image: linear-gradient(#808080, transparent);
}
<div class="checkered-bg">CONTENT</div>
View on JSfiddle
Option #2 smaller squares - JSfiddle
So I have a div, content of which should always be crossed out diagonally.
I've tried few solutions with few elements that had absolute positions but it wasn't good enough, because content and size of the div that should be crossed out can vary, so crossing out should be adaptive as well.
Basically I need to make something like this: http://www.awesomescreenshot.com/0515d31j22
This should work for you.
.strike {
position: relative;
display: inline-block;
}
.strike:before {
content: "";
position: absolute;
height: 1px;
width: 120%;
background: red;
top: 50%;
left: 50%;
transform: translate(-50%, -50%) rotate(25deg);
}
<div class="strike">$55.55</div>
<br><br>
<div class="strike">$555.55</div>
<br><br>
<div class="strike">$5555.55</div>
A couple of linear gradients can do this and it will auto-size to the dimensions of the element and no degree notation is required.
div {
width: 25%;
height: 250px;
margin: 1em auto;
border:1px solid grey;
position: relative;
}
div:after {
content: '';
position: absolute;
width: 100%;
height: 100%;
top:0;
left: 0;
background:
linear-gradient(to bottom left, transparent 0%, transparent 50%, red 51%, transparent 51%, transparent 100%),
linear-gradient(to bottom right, transparent 0%, transparent 50%, red 51%, transparent 51%, transparent 100%);
}
<div></div>
I am currently using CSS3 to make an div with the left side angled like a trapezium using the following CSS adapted from this jsfiddle:
background:linear-gradient(75deg, transparent 75px, #35753f 76px);
I would like to combine the following CSS background with a radial one, to create the effect shown in the image below. However, when I do this, I lose the angled side. What is the best way to combine these two backgrounds?
Here is the radial background:
background:radial-gradient(circle closest-corner at right center, #337540 0%, #003832 100%);
Here is what it should look like:
Here is a jsfiddle of the below:
.container {
width: 1024px;
margin: 0 auto;
}
.clearfix:after {
content: ".";
display: block;
height: 0;
clear: both;
visibility: hidden;
}
#top-banner {
position: relative;
}
#top-banner .container {
height: 350px;
}
#top-banner #banner-right {
width: 350px;
height: 350px;
background: -moz-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -o-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -webkit-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: linear-gradient(75deg, transparent 75px, #35753f 76px);
position: relative;
float: right;
}
#top-banner #banner-right:after {
content: ".";
display: block;
height: inherit;
width: 5000px;
left: 350px;
top: 0;
position: absolute;
/* IE10 Consumer Preview */
background-image: -ms-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Mozilla Firefox */
background-image: -moz-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Opera */
background-image: -o-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Webkit (Safari/Chrome 10) */
background-image: -webkit-gradient(radial, left center, 0, left center, 140, color-stop(0, #337540), color-stop(1, #003832));
/* Webkit (Chrome 11+) */
background-image: -webkit-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* W3C Markup, IE10 Release Preview */
background-image: ;
z-index: -100;
}
/*#top-banner #banner-right {
width:350px;
height:350px;
background:black;
position:relative;
float: right;
}
#top-banner #banner-right:before {
content:"";
position:absolute;
top:0;
left:0;
width: 0;
height: 0;
border-bottom: 350px solid white;
border-right: 40px solid transparent;
}*/
#top-banner .slider {
float: left;
height: 350px;
width: 100px;
background-color: black;
background-size: cover;
shape-outside: polygon(0 0, 100% 0, 100% 100%, 0 100%);
}
<div id="top-banner">
<div class="container clearfix">
<div id="banner-right">
</div>
<div class="slider">
<img src="http://1.bp.blogspot.com/-9aQmrN3-xpQ/TuYsXHQygrI/AAAAAAAAAtw/cEmz4PgEQdQ/s1600/r-NEW-SPECIES-MEKONG-DELTA-huge.jpg" height="350" alt="banner-1" />
</div>
</div>
</div>
Angled div - 2 methods
The angle is created with transform: rotate and not the linear-gradient.
#1 - Rotated :before with translate 3d
In this example, translate3d(0px,0px,1px) is used to eliminate the jagged edge of the rotated element. More information here. I was reminded about this technique from this answer dealing with a similar rendering problem.
As this is a hack that should be used sparingly, their is an alternative way to mask this edge without it in the second example.
Rotate a pseudo element, :before, of the div. This will create our angled edge
The :before gets an appropriate percentage height, width: 100px and is positioned appropriately
The parent div is given overflow: hidden to cut off the background cleanly
Create a second pseudo element, :after, to extend the background to the edge of the viewport.
The gradient background is applied to :after
The :before pseudo element is given a solid background the same color as the edge of the gradient to blend
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example
The linear-gradient on the body demonstrates that the div can be placed over any background.
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
min-width: 500px;
}
div:before {
content: '';
display: block;
position: absolute;
height: 120%;
width: 90px;
top: -10%;
left: 90px;
background: #003832;
transform: translate3d(0px,0px,1px) rotate(-15deg);
z-index: 1;
}
div:after {
content: '';
display: block;
position: absolute;
height: 120%;
width: 100%;
top: -10%;
left: 135px;
background: radial-gradient(circle closest-corner at 50% 50%, #33753E 0%, #003832 80%);
z-index: 1;
}
p {
color: #FFF;
left: 10px;
position: relative;
z-index: 2;
}
<div>
<p>This is some text</p>
</div>
#2 - Rotated :before and :after without translate 3d
Rotate a pseudo element, :before, of the div
Apply the background to the pseudo element
The pseudo element gets height: 200% and width: 200% and is positioned appropriately
The parent div is given overflow: hidden to cut off the gradient cleanly and the rotated pseudo element becomes the background
A second pseudo element, :after, is used to help mask the jagged edge with a box-shadow (the left edge is jagged at all rotations that are not 45deg increments)
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example 1
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
}
div {
position: relative;
width: 500px;
height: 350px;
overflow: hidden;
padding-left: 100px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 200%;
width: 200%;
top: -220px;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
top: -220px;
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
}
<div>
<p>This is some text</p>
</div>
Example 2 - extended
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
max-width: 1600px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 300%;
width: 300%;
top: -200%;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
left: 80px;
}
<div>
<p>This is some text</p>
</div>
If you want it to be exactly as you shown on a picture - try :before pseudoclass.
#div_with_background{
position: relative;
background: radial-gradient(circle closest-corner at 60% 50%, #33753E 0%, #003832 100%);
width: 567px;
height: 356px;
}
#div_with_background:before{
content: "";
position: absolute;
top: 0px;
left: 0px;
width: 0;
height: 0;
border-style: solid;
border-width: 356px 0 0px 130px;
border-color: transparent transparent transparent #FFFFFF;
z-index: 1;
}
<div id="div_with_background"></div>
I'm trying to figure out if there's a way to do this with CSS: I have a container div with a border-radius of 50% (circular). Inside of that is a rectangular div with a height of 30% positioned at the bottom of the container, and I want to be able to mask that off so that anything outside of the container's rounded border radius doesn't show. How do I accomplish this? Attached is a screenshot of what's currently happening, and this is my code:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
#coupon_container {
position: fixed; right:0; top:0; z-index: 100; color: #fff; width:170px; height: 120px;
#meter_container {
position: absolute; width: 110px; height:110px; .round; background: #greenDk; border:5px solid #fff; left: 60px; overflow: hidden;
.meter_level { width: 100%; height:30%; position: absolute; bottom:0; text-align: center; font-size: 1.6em; background: #limeLt; }
}
}
I really like the gradient solution that bookcasey has posted. However, compatibility may be a drawback as IE9 doesn't support CSS gradients. So another solution would be this one:
demo
The idea is to use a top padding of 70% instead of absolute positioning.
HTML:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
CSS:
#coupon_container {
overflow: hidden;
width: 8em; height: 8em;
border-radius: 50%;
background: green;
}
#meter_container {
margin: 70% 0;
height: 30%;
text-align: center;
background: lime;
}
You can achieve the effect you want using CSS3 gradients:
#coupon_container {
width: 100px;
height: 100px;
border-radius: 100px;
background: -webkit-gradient(linear, 50% 0%, 50% 70, color-stop(100%, #fa8072), color-stop(100%, #ff0000));
background: -webkit-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -moz-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -o-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: linear-gradient(top, #fa8072 70px, #ff0000 70px);
position: relative;
}
#meter_container {
width: 100px;
text-align: center;
position: absolute;
bottom: 10px;
}
Demo
I could be totally missing something, but couldn't you just add "overflow: hidden;" to the round element, #coupon_container?