Normalizing data based on Subset Mean in R - r

I have a table I am trying to normalize by a specific subset of means within the one column based on the variable in another column. Ideally, my code would divide all of the data in the coverage_depth column for a specific strain variable (like 2987) by the mean of a subset of the same column (coverage depth for only the SAG1 in the chr column for only the 2987 in the strain column)
I have found the long way of doing this but I'm really hoping someone has a way to make this a loop so that I don't have to input means by hand after they are calculated.
My table looks like this:
B1 1073 320 2987
B1 1074 324 2987
B1 1075 330 2987
SAG1 955 31 2987
SAG1 956 30 2987
SAG1 957 29 2987
SAG1 958 29 2987
BTub 446 57 2987
BTub 452 59 2987
B1 1707 53 GRE_MIG
B1 1708 56 GRE_MIG
18S 1099 242 GRE_MIG
18S 1100 242 GRE_MIG
SAG1 888 7 GRE_MIG
SAG1 889 7 GRE_MIG
SAG1 890 7 GRE_MIG
First I load in my table:
reads<-read.table("3133_all.CNV.txt", sep = "\t", header = F)
colnames(reads)<-c("chr", "position", "coverage_depth", "strains"
Then I call plyr to calculate the mean of coverage_depth of all the combinations of the chr and strains columns
library(plyr)
coverage_summary<-ddply(reads, c("chr", "strains"), summarise, mean = mean(coverage_depth))
write.csv(format(coverage_summary, scientific=FALSE), file = "CNV_mean_07.27.16.csv", row.names = F)
Which gives me a longer version of this:
chr strains mean
1 18S 2987 2.052802e+03
20 18S GRE_MIG 2.674536e+01
126 B1 GRE_MIG 6.503342e+01
213 SAG1 2987 3.422057e+01
232 SAG1 GRE_MIG 5.863501e+00
I figured out how to normalize all of the coverage_depth of a strain by the mean which I get from that strain at chr SAG1 which I manually put in like so:
NormalizeSAG1<-function(coverage_depth, strains){
if (strains %in% c("2987")) {
coverage_depth<-coverage_depth/3.42
} else if (strains %in% c("GRE_MIG")) {
coverage_depth<-coverage_depth/5.86
} else { coverage.norm<-coverage_depth
}}
reads$SAG1_normalized<-mapply(NormalizeSAG1, reads$coverage_depth, reads$strains)
The problem is that I have 53 different strains that I want to normalize based on the mean at their individual SAG1 in the chr column. It seems like maybe a for loop would do it but I can't figure out how to properly subset my data to normalize without a ton of ifelse statements.

Try the following:
reads <- merge(reads, coverage_summary)
reads <- mutate(reads, normalized = coverage_depth / mean)
Basically, this should join your summary column back into your raw data, after which, creating a normalized column should be trivial. This also avoids having to create a custom function that accounts for 53 different possible values.

Related

Indexing through 'names' in a list and performing actions on contained values in R

I have a data set of counts from standard solutions passed through an instrument that analyses chemical concentrations (an ICPMS for those familiar). The data is over a range of different standards and for each standard I have four repeat measurements that I want to calculate the mean and variance of.
I'm importing the data from an excel spreadsheet and then, following some housekeeping such as getting dates and times in the right format, I split the the dataset up into a list identified by the name of the standard solution using Count11.sp<-split(Count11.raw, Count11.raw$Type). Count11.raw$Type then becomes the list element name and I have the four count results for each chemical element in that list element.
So far so good.
I find I can yield an average (mean, median etc) easily enough by identifying the list element specifically i.e. mean(Count11.sp$'Ca40') , or sapply(Count11$'Ca40', median), but what I'm not able to do is automate that in a loop so that I can calculate the means for each standard and drop that into a numerical matrix for further manipulation. I can extract the list element names with names() and I can even use a loop to make a vector of all the names and reference the specific list element using these in a for loop.
For instance Count11.sp[names(Count11.sp[i])]will extract the full list element no problem:
$`Post Ca45t`
Type Run Date 7Li 9Be 24Mg 43Ca 52Cr 55Mn 59Co 60Ni
77 Post Ca45t 1 2011-02-08 00:13:08 114 26101 4191 453525 2632 520 714 2270
78 Post Ca45t 2 2011-02-08 00:13:24 114 26045 4179 454299 2822 524 704 2444
79 Post Ca45t 3 2011-02-08 00:13:41 96 26372 3961 456293 2898 520 762 2244
80 Post Ca45t 4 2011-02-08 00:13:58 112 26244 3799 454702 2630 510 792 2356
65Cu 66Zn 85Rb 86Sr 111Cd 115In 118Sn 137Ba 140Ce 141Pr 157Gd 185Re 208Pb
77 244 1036 56 3081 44 520625 78 166 724 10 0 388998 613
78 250 982 70 3103 46 526154 76 174 744 16 4 396496 644
79 246 1014 36 3183 56 524195 60 198 744 2 0 396024 612
80 270 932 60 3137 44 523366 70 180 824 2 4 390436 632
238U
77 24
78 20
79 14
80 6
but sapply(Count11.sp[names(count11.sp[i])produces an error message: Error in median.default(X[[i]], ...) : need numeric data
while sapply(Input$Post Ca45t, median) <'Post Ca45t' being name Count11.sp[i] i=4> does exactly what I want and produces the median value (I can clean that vector up later for medians that don't make sense) e.g.
Type Run Date 7Li 9Be 24Mg
NA 2.5 1297109612.5 113.0 26172.5 4070.0
43Ca 52Cr 55Mn 59Co 60Ni 65Cu
454500.5 2727.0 520.0 738.0 2313.0 248.0
66Zn 85Rb 86Sr 111Cd 115In 118Sn
998.0 58.0 3120.0 45.0 523780.5 73.0
137Ba 140Ce 141Pr 157Gd 185Re 208Pb
177.0 744.0 6.0 2.0 393230.0 622.5
238U
17.0
Can anyone give me any insight into how I can automate (i.e. loop through) these names to produce one median vector per list element? I'm sure there's just some simple disconnect in my logic here that may be easily solved.
Update: I've solved the problem. The way to do so is to use tapply on the original dataset with out the need to split it. tapply allows functions to be applied to data based on a user defined grouping criteria. In my case I could group according to the Count11.raw$Type and then take the mean of the data subset. tapply(Count11.raw$Type, Count11.raw[,3:ncol(Count11.raw)], mean), job done.

Stratifying multiple columns for cross-validation

There are many ways I've seen to stratify a sample by a single variable to use for cross-validation. The caret package does this nicely with the createFolds() function. By default it seems that caret will partition such that each fold has roughly the same target event rate.
What I want to do though is stratify by the target rate and by time. I've found a function that can partially do this, it's the splitstackshape package and uses the stratified() function. The issue with that function though is it returns a single sample, it doesn't split the data into k groups under the given conditions.
Here's some dummy data to reproduce.
set.seed(123)
time = rep(seq(1:10),100)
target = rbinom(n=100, size=1, prob=0.3)
data = as.data.frame(cbind(time,target))
table(data$time,data$target)
0 1
1 60 40
2 80 20
3 80 20
4 60 40
5 80 20
6 80 20
7 60 40
8 60 40
9 70 30
10 80 20
As you can see, the target event rate is not the same across time. It's 40% in time 1 and 20% in time 2, etc. I want to preserve this when creating the folds used for cross-validation. If I understand correctly, caret will partition by the overall event rate.
table(data$target)
0 1
710 290
This rate of ~30% will be preserved overall, but target event rate over time will not.
We can get one sample like this:
library(splitstackshape)
train.index <- stratified(data,c("target","time"),size=.2)
I need to repeat this though 4 more times for a 5-fold cross validation and it needs to be done such that once a row is assigned it can't be assigned again. I feel like there should be a function designed for this already. Any ideas?
I know this post is old but I just had the same problem and I couldn't find another solution. In case anyone else needs an answer, here's the solution I'm implementing.
library(data.table)
mystratified <- function(indt, group, NUM_FOLDS) {
indt <- setDT(copy(indt))
if (is.numeric(group))
group <- names(indt)[group]
temp_grp <- temp_ind <- NULL
indt[, `:=`(temp_ind, .I)]
indt[, `:=`(temp_grp, do.call(paste, .SD)), .SDcols = group]
samp_sizes <- indt[, .N, by = group]
samp_sizes[, `:=`(temp_grp, do.call(paste, .SD)), .SDcols = group]
inds <- split(indt$temp_ind, indt$temp_grp)[samp_sizes$temp_grp]
z = unlist(inds,use.names=F)
model_folds <- suppressWarnings(split(z, 1:NUM_FOLDS))
}
Which is basically a rewriting of splitstackshape::stratified. It works like the following, giving as output a list of validation indeces for each fold.
myfolds = mystratified(indt = data, group = colnames(data), NUM_FOLDS = 5)
str(myfolds)
List of 5
$ 1: int [1:200] 1 91 181 261 351 441 501 591 681 761 ...
$ 2: int [1:200] 41 101 191 281 361 451 541 601 691 781 ...
$ 3: int [1:200] 51 141 201 291 381 461 551 641 701 791 ...
$ 4: int [1:200] 61 151 241 301 391 481 561 651 741 801 ...
$ 5: int [1:200] 81 161 251 341 401 491 581 661 751 841 ...
So, for instance the train and validation data for each fold are:
# first fold
train = data[-myfolds[[1]],]
valid = data[myfolds[[1]],]
# second fold
train = data[-myfolds[[2]],]
valid = data[myfolds[[2]],]
# etc...

R One sample test for set of columns for each row

I have a data set where I have the Levels and Trends for say 50 cities for 3 scenarios. Below is the sample data -
City <- paste0("City",1:50)
L1 <- sample(100:500,50,replace = T)
L2 <- sample(100:500,50,replace = T)
L3 <- sample(100:500,50,replace = T)
T1 <- runif(50,0,3)
T2 <- runif(50,0,3)
T3 <- runif(50,0,3)
df <- data.frame(City,L1,L2,L3,T1,T2,T3)
Now, across the 3 scenarios I find the minimum Level and Minimum Trend using the below code -
df$L_min <- apply(df[,2:4],1,min)
df$T_min <- apply(df[,5:7],1,min)
Now I want to check if these minimum values are significantly different between the levels and trends respectively. So check L_min with columns 2-4 and T_min with columns 5-7. This needs to be done for each city (row) and if significant then return which column it is significantly different with.
It would help if some one could guide how this can be done.
Thank you!!
I'll put my idea here, nevertheless I'm looking forward for ideas for others.
> head(df)
City L1 L2 L3 T1 T2 T3 L_min T_min
1 City1 251 176 263 1.162313 0.07196579 2.0925715 176 0.07196579
2 City2 385 406 264 0.353124 0.66089524 2.5613980 264 0.35312402
3 City3 437 333 426 2.625795 1.43547766 1.7667891 333 1.43547766
4 City4 431 405 493 2.042905 0.93041254 1.3872058 405 0.93041254
5 City5 101 429 100 1.731004 2.89794314 0.3535423 100 0.35354230
6 City6 374 394 465 1.854794 0.57909775 2.7485841 374 0.57909775
> df$FC <- rowMeans(df[,2:4])/df[,8]
> df <- df[order(-df$FC), ]
> head(df)
City L1 L2 L3 T1 T2 T3 L_min T_min FC
18 City18 461 425 117 2.7786757 2.6577894 0.75974121 117 0.75974121 2.857550
38 City38 370 117 445 0.1103141 2.6890014 2.26174542 117 0.11031411 2.655271
44 City44 101 473 222 1.2754675 0.8667007 0.04057544 101 0.04057544 2.627063
10 City10 459 361 132 0.1529519 2.4678493 2.23373484 132 0.15295194 2.404040
16 City16 232 393 110 0.8628494 1.3995549 1.01689217 110 0.86284938 2.227273
15 City15 499 475 182 0.3679611 0.2519497 2.82647041 182 0.25194969 2.117216
Now you have the most different rows based on columns 2:4 at the top. Columns 5:7 in analogous way.
And some tips for stastical tests:
Always use t.test(parametrical, based on mean) instead of wilcoxon(u-mann whitney - non-parametrical, based on median), it has more power; HOWEVER:
-Data sets should be big ex. hipotesis: Montreal has taller citizens than Quebec; t.test will work fine when you take a 100 people from each city, so we have height measurment of 200 people 100 vs 100.
-Distribution should be close to normal distribution in all samples; or both samples should have similar distribution far from normal - it may be binominal. Anyway we can't use this test when one sample has normal distribution, and second hasn't.
-Size of both samples should be eqal, so 100 vs 100 is ok, but 87 vs 234 not exactly, p-value will be below 0.05, however it may be misrepresented.
If your data doesn't meet above conditions, I prefer non-parametrical test, less power but more resistant.

Creating data continuously using rnorm until an outlier occurs in R

Sorry for the confusing title, but i wasn't sure how to title what i am trying to do. My objective is to create a dataset of 1000 obs each would be the length of the run. I have created a phase1 dataset, from which a set of control limits are produced. What i am trying to do now is create a phase2 dataset most likely using rnorm. what im trying to do is create a repeat loop that will continuously create values in the phase2 dataset until one of those values is outside of the control limits produced from the phase1 dataset. for example if i had 3.0 and -3.0 as control limits the phase2 dataset would create a bunch of observations until obs 398 when the value here happens to be 3.45, thus stopping the creation of data. my objective is then to record the number 398. Furthermore, I am then trying to loop the code back to the phase1 dataset/ control limits portion and create a new set of control limits and then run another phase2, until i have 1000 run lengths recorded. the code i have for the phase1/ control limits works fine and looks like this:
nphase1=50
nphase2=1000
varcount=1
meanshift= 0
sigmashift= 1
##### phase1 dataset/ control limits #####
phase1 <- matrix(rnorm(nphase1*varcount, 0, 1), nrow = nphase1, ncol=varcount)
mean_var <- apply(phase1, 2, mean)
std_var <- apply(phase1, 2, sd)
df_var <- data.frame(mean_var, std_var)
Upper_SPC_Limit_Method1 <- with(df_var, mean_var + 3 * std_var)
Lower_SPC_Limit_Method1 <- with(df_var, mean_var - 3 * std_var)
df_control_limits<- data.frame(Upper_SPC_Limit_Method1, Lower_SPC_Limit_Method1)
I have previously created this code in SAS and it looks like this. might be a better reference for what i am trying to achieve then me trying to explain it.
%macro phase2_dataset (n=,varcount=, meanshift=, sigmashift=, nphase1=,simID=,);
%do z=1 %to &n;
%phase1_dataset (n=&nphase1, varcount=&varcount);
data phase2; set control_limits n=lastobs;
call streaminit(0);
do until (phase2_var1<Lower_SPC_limit_method1_var1 or
phase2_var1>Upper_SPC_limit_method1_var1);
phase2_var1 = rand("normal", &meanshift, &sigmashift);
output;
end;
run;
ods exclude all;
proc means data=phase2;
var phase2_var1;
ods output summary=x;
run;
ods select all;
data run_length; set x;
keep Phase2_var1_n;
run;
proc append base= QA.Phase2_dataset&simID data=Run_length force; run;
%end;
%mend;
Also been doing research about using a while loop in replace of the repeat loop.
Im new to R so Any ideas you are able to throw my way are greatly appreciated. Thanks!
Using a while loop indeed seems to be the way to go. Here's what I think you're looking for:
set.seed(10) #Making results reproducible
replicate(100, { #100 is easier to display here
phase1 <- matrix(rnorm(nphase1*varcount, 0, 1), nrow = nphase1, ncol=varcount)
mean_var <- colMeans(phase1) #Slightly better than apply
std_var <- apply(phase1, 2, sd)
df_var <- data.frame(mean_var, std_var)
Upper_SPC_Limit_Method1 <- with(df_var, mean_var + 3 * std_var)
Lower_SPC_Limit_Method1 <- with(df_var, mean_var - 3 * std_var)
df_control_limits<- data.frame(Upper_SPC_Limit_Method1, Lower_SPC_Limit_Method1)
#Phase 2
x <- 0
count <- 0
while(x > Lower_SPC_Limit_Method1 && x < Upper_SPC_Limit_Method1) {
x <- rnorm(1)
count <- count + 1
}
count
})
The result is:
[1] 225 91 97 118 304 275 550 58 115 6 218 63 176 100 308 844 90 2758
[19] 161 311 1462 717 2446 74 175 91 331 210 118 1517 420 32 39 201 350 89
[37] 64 385 212 4 72 730 151 7 1159 65 36 333 97 306 531 1502 26 18
[55] 67 329 75 532 64 427 39 352 283 483 19 9 2 1018 137 160 223 98
[73] 15 182 98 41 25 1136 405 474 1025 1331 159 70 84 129 233 2 41 66
[91] 1 23 8 325 10 455 363 351 108 3
If performance becomes a problem, perhaps it would be interesting to explore some improvements, like creating more numbers with rnorm() at a time and then counting how many are necessary to exceed the limits and repeat if necessary.

R: looping through data.frame columns

I got a following my_data:
geneid chr acc_no start end size strand S1 S2 A1 A2
1 gene_010010 1 AC12345.1 3662 4663 1002 - 328 336 757 874
2 gene_010020 1 AC12345.1 5750 7411 1662 - 480 589 793 765
3 gene_010030 2 AC12345.1 9003 11024 2022 - 653 673 875 920
4 gene_010040 2 AC12345.1 12006 12566 561 - 573 623 483 430
5 gene_010050 3 AC12345.1 15035 17032 1998 - 2256 2333 1866 1944
6 gene_010060 3 AC12345.1 18188 18937 750 - 526 642 650 586
I am able to calculate sums for a given column, i.e:
chr.sums <- data.frame(with (my_data, tapply(S1, INDEX=chr, FUN=sum)))
Problem is, I want to get chr.sums with four columns (S1, S2, A1 and A2) and 30 rows corresponding to unique chr numbers. I do not want to switch to Python back and forth, but looping through columns and assigning output to specific columns in data.frame baffles me.
EDIT
Toy data set above.
You can use ddply from plyr. Here is some code:
plyr::ddply(my_data, .(chr), summarize, S1 = sum(S1), S2 = sum(S2),
A1 = sum(A1), A2 = sum(A2))
EDIT. A more compact solution would be:
plyr::ddply(my_data, .(chr), colwise(sum, .(S1, S2, A1, A2)))
Here is how it works. The data is first split into pieces based on chr. Then, the columns S1, S2, A1, A2 are summed up for each piece. Finally, they are assembled back into a single data frame.
Any place you have this kind of a split-apply-combine problem, think plyr as a solution.
tapply won't handle multiple columns but the formula version of aggregate will.
chr.sums <- aggregate(cbind(S1,S2,A1,A2) ~ chr, data = my_data, FUN=sum)))

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