I am new in wordpress, I am currently creating a plugin which is get the message and image and store it in database. I learn wpdb class to store data to database, But i still can't know how to move and upload file and store in also in folder and media library. Please help me i tried codes which i get at wordpress.org but still cant upload image to media library. If you cant tell me please reference to learn admin-ajax.
Get an array containing the current upload directory’s path and url.
wp_upload_dir( string $time = null, bool $create_dir = true, bool $refresh_cache = false )
You can find more on https://developer.wordpress.org/reference/functions/wp_upload_dir/
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I will Try to add Video Embed to drupal-7 programmatically
with thumb.
This is what I've tried:
$url='https://www.youtube.com/watch?v=8Zq3KCBed5Q';
$file_path = drupal_realpath($url);
$file->uid = 1;
$file->filename = 'dsdss';
$file->uri = $url;
$file->filemime = file_get_mimetype($file_path);
$file->type = 'video';
$file->status = 1;
$file_exists = file_save($file);
$node->field_videoyou[$node->language]['0'] = (array) $file_exists;
How I can do this?
As far as I know, drupal_realpath is converting local drupal path to absolute path and you are passing to it absolute path. Also, you didn't show us where you create that $file object. What is that?
If you check file_save() docs:
https://api.drupal.org/api/drupal/includes!file.inc/function/file_save/7
...you'll see that $file should be "a file object returned by file_load()."
So, I think that you are using drupal_realpath wrong, don't see that you are using file_load() for creating $file object and I don't see that you are copy-ing file to your server.
My suggestion is not to mess with files anyway, but just take player embed code and use it. You can have some text field to your content type where admin can insert video embed code and just shoot that value out on front-end.
Moreever...it will probably happen that embed code is pretty similar for different videos and that only difference is just some video id value so you don't even have to store whole embed code, but just that video id and you can keep rest of embed code in some template file, as static, where you will just insert video id.
Im writing a module for drupal, Im trying to create a node from my module, everything is fine , I only have 1 problem with creating an image , The image exist on different server, so I want to grab the page and insert it , I install module http://drupal.org/project/filefield_sources , which has remote option , I search in the module code , I could not find the function that he used for this process, module work very nice from interface , but how i make it do the job from code ? which function should i call and what parameter should i pass .
I'm over Drupal 6.
Hopefully you're using Drupal 7...
The system_retrieve_file() function will download a file from a remote source, copy it from temp to a specified destination and optionally save it to the file_managed table if you want it to be managed.
$managed = TRUE; // Whether or not to create a Drupal file record
$path = system_retrieve_file($url, 'public://my_files/', $managed);
If you want to get the file object immediately after you've done this, the following is the only way I've found so far:
$file = file_load(db_query('SELECT MAX(fid) FROM {file_managed}')->fetchField());
get fid using $path->fid. no need to mysql
I have 2 different project. One is supposed to upload images (admin) and the other is supposed to show them.
I was writing something like "/Contents/images/image path"... But wait! I will I upload the images from the application into that address?
Any help and suggestions please.
If you have two applications that will interact with the same files, it's probably better to have an ImageController with an action that allows you to upload/download the image rather than storing them directly as content. That way both applications can reference the same file location or images stored in a database and manipulate them. Your download action would simply use a FileContentResult to deliver the bytes from the file. You can derive the content type from the file extension.
Example using a database. Note that I assume that the database table contains the content type as determined at upload time. You could also use a hybrid approach that stores the image metadata in a database and loads the actual file from a file store.
public class ImageController : Controller
{
public ActionResult Get( int id )
{
var context = new MyDataContext();
var image = context.Images.SingleOrDefault( i => i.ID == id );
if (image != null)
{
return File( image.Content, image.ContentType );
}
// or you could return a placeholder image here if appropriate.
throw new HttpException( 404, "The image does not exist" );
}
}
An alternative would be to incorporate your administrative interface in an area of the same application rather than in a separate project. This way you could reuse the content/images directory if you wanted. I find that when you have dynamic images the database or a hybrid approach works better from a programming perspective since it's more consistent with the rest of your data model.
you could try like this..
Let's assume that all of your images are in Project A and you want to use the same images in Project B.
Open Project B with Visual Studio. In the Solution Explorer, right click your Project Name and select "Add Existing Item...".
Browse to the physical location on disc where your images in Project A are stored and select the files that you want to import.
You'll then be able to access those images from project A in Project B.
I'm trying to import nodes from my forum to drupal 7. Not in bulk, but one by one so that news posts can be created and referenced back to the forum. The kicker is that I'm wanting to bring image attachments across as well...
So far, using the code example here http://drupal.org/node/889058#comment-3709802 things mostly work: Nodes are created, but the images don't go through any validation or processing.
I'd like the attached images to be validated against the rules defined in the content type. in particular the style associated with my image field which resizes them to 600x600.
So, instead of simply creating the nodes programatically with my own form, i decided to modify a "new" node using hook_node_prepare and using the existing form to create new content (based on passed in url args). This works really well and a create form is presented pre-filled with all my data. including the image! very cute.
I expected that i could then hit preview or save and all the validation and resizing would happen to my image, but instead i get the error:
"The file used in the Image field may not be referenced."
The reason for this is that my file doesn't have an entry in the file_usage table.. *le sigh*
so, how do i get to all the nice validation and processing which happens when i manually choose a file to upload? like resizing, an entry in the file_usage table.
The ajax upload function does it, but i can't find the code which is called to do this anywhere in the api.
What file upload / validation functions does Drupal call which i'm not doing?
Anybody have any experience with the file/image api for Drupal 7 who can help me out?
For getting the usage entry (in essence, checking out a file to a specific module so that it doesn't get deleted while its in use) look up the Drupal function 'file_usage_add()'
For validating incoming images, I got this example from user.module (if you're comfortable with PHP, you can always look at the core to see how something is done the 'Drupal way'):
function user_validate_picture(&$form, &$form_state) {
// If required, validate the uploaded picture.
$validators = array(
'file_validate_is_image' => array(),
'file_validate_image_resolution' => array(variable_get('user_picture_dimensions', '85x85')),
'file_validate_size' => array(variable_get('user_picture_file_size', '30') * 1024),
);
// Save the file as a temporary file.
$file = file_save_upload('picture_upload', $validators);
if ($file === FALSE) {
form_set_error('picture_upload', t("Failed to upload the picture image; the %directory directory doesn't exist or is not writable.", array('%directory' => variable_get('user_picture_path', 'pictures'))));
}
elseif ($file !== NULL) {
$form_state['values']['picture_upload'] = $file;
}
}
That function is added to the $form['#validate'] array like so:
$form['#validate'][] = 'user_validate_picture'
I'm in the progress of creating a bulk upload function for a Drupal site. Using flash I'm able to upload the files to a specific url that then handles the files. What I want to do, is not just to upload the files, but create a node of a specific type with the file saved to a filefield that has been setup with CCK. Since these are audio files, it's important that filefield handles the files, so addition meta data can be provided with the getid3 module.
Now I've looked through some of the code as I wasn't able to find an API documentation, but it's not clear at all how I should handle this. Ideally I could just pass the file to a function and just use the data returned when saving the node, but I haven't been able to find that function.
If any one has experience with this I would apreciate some pointers on how to approach this matter.
I had to do something similar some weeks ago and ended up adapting some functionality from the Remote File module, especially the remote_file_cck_attach_file() function. It uses the field_file_save_file() function from the filefield module, which might be the function you're looking for.
In my case, the files are fetched from several remote locations and stored temporarily using file_save_data(). Attaching them to a CCK filefield happens on hook_nodeapi() presave, using the following:
public static function attachAsCCKField(&$node, $filepath, $fieldname, $index=0) {
// Grab the filefield definition
$field = content_fields($fieldname, $node->type);
$validators = array_merge(filefield_widget_upload_validators($field), imagefield_widget_upload_validators($field));
$fieldFileDirectory = filefield_widget_file_path($field);
// This path does not necessarily exist already, so make sure it is available
self::verifyPath($fieldFileDirectory);
$file = field_file_save_file($filepath, $validators, $fieldFileDirectory);
// Is the CCK field array already available in the node object?
if (!is_array($node->$fieldname)) {
// No, add a stub
$node->$fieldname=array();
}
$node->{$fieldname}[$index] = $file;
}
$filepath is the path to the file that should be attached, $fieldname is the internal name of the filefield instance to use within the node and $index would be the 0 based index of the attached file in case of multiple field entries.
The function ended up within a utility class, hence the class syntax for the verifyPath() call. The call just ensures that the target directory is available:
public static function verifyPath($path) {
if (!file_check_directory($path, FILE_CREATE_DIRECTORY)) {
throw new RuntimeException('The path "' . $path . '" is not valid (not creatable, not writeable?).');
}
}
That did it for me - everything else happens on node saving automatically.
I have not used the getid3 module yet, so I have no idea if it would play along with this way of doing it. Also, I had no need to add additional information/attributes to the filefield, so maybe you'd have to put some more information into the field array than just the file returned by field_file_save_file(). Anyways, hope this helps and good luck.
I have done something whith imagefield which worked, I think the structure has to be right otherwise it won't work. It took a lot of trial and error. This is is what I populated the imagefield with.
$image['data'] =array(
'title' => $media_reference_attributes->getNamedItem("source")->value,
'description' => $description,
'alt' => "",);
$image['width'] = $width;
$image['height'] = $height;
$image['mimetype'] = $mime_type
$image['uid'] = 1;
$image['status'] = 1;
$image['fid'] = $fid;
$image['filesize'] = $file->filesize;
$image['nid'] = $id;
$image['filename'] = $url;
$image['timestamp'] = $file->timestamp;
$image['filepath'] = $file_path;
Hope this is of some help.
You might want to look at Image FUpload if you need a look at integrating the flash upload.
To push the files on to another server while still handling them through Drupal sounds a little like the CDN space, maybe look at the behavior in the CDN or CDN2 projects?
If you find a clear solution please come back and post it!