In Julia, suppose I have a function that returns a dictionary:
function f()
d = [i => 2i for i = 1:10]
return d
end
I would like to return the dictionary as const. That is, keys cannot be added or removed, and existing keys cannot be reassigned. Is it possible to modify f so that the returned dictionary is const?
Julia's standard library does not provide an immutable associative type. You could implement such a type yourself and not define any setindex! method for it. It might be easier to simply not mutate the returned dictionary, however.
Although Julia doesn't have a readonly Dict in its standard library (there is the unexported ImmutableDict, but that only prevents deletions, not sets), nor in the DataStructures.jl package, it could fairly easily be added as a package.
There are a number of advantages of a readonly Dict, for example, a perfect hash function can be generated so that entries are found (or not) with only a single probe. (https://www.gnu.org/software/gperf/manual/gperf.html describes a tool to generate a perfect hash).
Related
Suppose I have hold of the concrete type of a normal, named Julia function, F = typeof(f). Is it possible to get back f from F? I assume this should work in principle, since F is a singleton type.
You can go with Core.Compiler.singleton_type function which returns the instance field for a concrete DataType. I think this function is used for the same objective as yours (not only for this objective) in Core.Compiler during compilation. This is probably considered "more internal" than directly accessing instance field.
julia> Core.Compiler.singleton_type(typeof(sum))
sum (generic function with 13 methods)
I would use F.instance, but maybe there is some better solution (as this one is using the internals).
Does anyone know the reasons why Julia chose a design of functions where the parameters given as inputs cannot be modified? This requires, if we want to use it anyway, to go through a very artificial process, by representing these data in the form of a ridiculous single element table.
Ada, which had the same kind of limitation, abandoned it in its 2012 redesign to the great satisfaction of its users. A small keyword (like out in Ada) could very well indicate that the possibility of keeping the modifications of a parameter at the output is required.
From my experience in Julia it is useful to understand the difference between a value and a binding.
Values
Each value in Julia has a concrete type and location in memory. Value can be mutable or immutable. In particular when you define your own composite type you can decide if objects of this type should be mutable (mutable struct) or immutable (struct).
Of course Julia has in-built types and some of them are mutable (e.g. arrays) and other are immutable (e.g. numbers, strings). Of course there are design trade-offs between them. From my perspective two major benefits of immutable values are:
if a compiler works with immutable values it can perform many optimizations to speed up code;
a user is can be sure that passing an immutable to a function will not change it and such encapsulation can simplify code analysis.
However, in particular, if you want to wrap an immutable value in a mutable wrapper a standard way to do it is to use Ref like this:
julia> x = Ref(1)
Base.RefValue{Int64}(1)
julia> x[]
1
julia> x[] = 10
10
julia> x
Base.RefValue{Int64}(10)
julia> x[]
10
You can pass such values to a function and modify them inside. Of course Ref introduces a different type so method implementation has to be a bit different.
Variables
A variable is a name bound to a value. In general, except for some special cases like:
rebinding a variable from module A in module B;
redefining some constants, e.g. trying to reassign a function name with a non-function value;
rebinding a variable that has a specified type of allowed values with a value that cannot be converted to this type;
you can rebind a variable to point to any value you wish. Rebinding is performed most of the time using = or some special constructs (like in for, let or catch statements).
Now - getting to the point - function is passed a value not a binding. You can modify a binding of a function parameter (in other words: you can rebind a value that a parameter is pointing to), but this parameter is a fresh variable whose scope lies inside a function.
If, for instance, we wanted a call like:
x = 10
f(x)
change a binding of variable x it is impossible because f does not even know of existence of x. It only gets passed its value. In particular - as I have noted above - adding such a functionality would break the rule that module A cannot rebind variables form module B, as f might be defined in a module different than where x is defined.
What to do
Actually it is easy enough to work without this feature from my experience:
What I typically do is simply return a value from a function that I assign to a variable. In Julia it is very easy because of tuple unpacking syntax like e.g. x,y,z = f(x,y,z), where f can be defined e.g. as f(x,y,z) = 2x,3y,4z;
You can use macros which get expanded before code execution and thus can have an effect modifying a binding of a variable, e.g. macro plusone(x) return esc(:($x = $x+1)) end and now writing y=100; #plusone(y) will change the binding of y;
Finally you can use Ref as discussed above (or any other mutable wrapper - as you have noted in your question).
"Does anyone know the reasons why Julia chose a design of functions where the parameters given as inputs cannot be modified?" asked by Schemer
Your question is wrong because you assume the wrong things.
Parameters are variables
When you pass things to a function, often those things are values and not variables.
for example:
function double(x::Int64)
2 * x
end
Now what happens when you call it using
double(4)
What is the point of the function modifying it's parameter x , it's pointless. Furthermore the function has no idea how it is called.
Furthermore, Julia is built for speed.
A function that modifies its parameter will be hard to optimise because it causes side effects. A side effect is when a procedure/function changes objects/things outside of it's scope.
If a function does not modifies a variable that is part of its calling parameter then you can be safe knowing.
the variable will not have its value changed
the result of the function can be optimised to a constant
not calling the function will not break the program's behaviour
Those above three factors are what makes FUNCTIONAL language fast and NON FUNCTIONAL language slow.
Furthermore when you move into Parallel programming or Multi Threaded programming, you absolutely DO NOT WANT a variable having it's value changed without you (The programmer) knowing about it.
"How would you implement with your proposed macro, the function F(x) which returns a boolean value and modifies c by c:= c + 1. F can be used in the following piece of Ada code : c:= 0; While F(c) Loop ... End Loop;" asked by Schemer
I would write
function F(x)
boolean_result = perform_some_logic()
return (boolean_result,x+1)
end
flag = true
c = 0
(flag,c) = F(c)
while flag
do_stuff()
(flag,c) = F(c)
end
"Unfortunately no, because, and I should have said that, c has to take again the value 0 when F return the value False (c increases as long the Loop lives and return to 0 when it dies). " said Schemer
Then I would write
function F(x)
boolean_result = perform_some_logic()
if boolean_result == true
return (true,x+1)
else
return (false,0)
end
end
flag = true
c = 0
(flag,c) = F(c)
while flag
do_stuff()
(flag,c) = F(c)
end
I am puzzled by the following results of typeof in the Julia 1.0.0 REPL:
# This makes sense.
julia> typeof(10)
Int64
# This surprised me.
julia> typeof(function)
ERROR: syntax: unexpected ")"
# No answer at all for return example and no error either.
julia> typeof(return)
# In the next two examples the REPL returns the input code.
julia> typeof(in)
typeof(in)
julia> typeof(typeof)
typeof(typeof)
# The "for" word returns an error like the "function" word.
julia> typeof(for)
ERROR: syntax: unexpected ")"
The Julia 1.0.0 documentation says for typeof
"Get the concrete type of x."
The typeof(function) example is the one that really surprised me. I expected a function to be a first-class object in Julia and have a type. I guess I need to understand types in Julia.
Any suggestions?
Edit
Per some comment questions below, here is an example based on a small function:
julia> function test() return "test"; end
test (generic function with 1 method)
julia> test()
"test"
julia> typeof(test)
typeof(test)
Based on this example, I would have expected typeof(test) to return generic function, not typeof(test).
To be clear, I am not a hardcore user of the Julia internals. What follows is an answer designed to be (hopefully) an intuitive explanation of what functions are in Julia for the non-hardcore user. I do think this (very good) question could also benefit from a more technical answer provided by one of the more core developers of the language. Also, this answer is longer than I'd like, but I've used multiple examples to try and make things as intuitive as possible.
As has been pointed out in the comments, function itself is a reserved keyword, and is not an actual function istself per se, and so is orthogonal to the actual question. This answer is intended to address your edit to the question.
Since Julia v0.6+, Function is an abstract supertype, much in the same way that Number is an abstract supertype. All functions, e.g. mean, user-defined functions, and anonymous functions, are subtypes of Function, in the same way that Float64 and Int are subtypes of Number.
This structure is deliberate and has several advantages.
Firstly, for reasons I don't fully understand, structuring functions in this way was the key to allowing anonymous functions in Julia to run just as fast as in-built functions from Base. See here and here as starting points if you want to learn more about this.
Secondly, because each function is its own subtype, you can now dispatch on specific functions. For example:
f1(f::T, x) where {T<:typeof(mean)} = f(x)
and:
f1(f::T, x) where {T<:typeof(sum)} = f(x) + 1
are different dispatch methods for the function f1
So, given all this, why does, e.g. typeof(sum) return typeof(sum), especially given that typeof(Float64) returns DataType? The issue here is that, roughly speaking, from a syntactical perspective, sum needs to serves two purposes simultaneously. It needs to be both a value, like e.g. 1.0, albeit one that is used to call the sum function on some input. But, it is also needs to be a type name, like Float64.
Obviously, it can't do both at the same time. So sum on its own behaves like a value. You can write f = sum ; f(randn(5)) to see how it behaves like a value. But we also need some way of representing the type of sum that will work not just for sum, but for any user-defined function, and any anonymous function. The developers decided to go with the (arguably) simplest option and have the type of sum print literally as typeof(sum), hence the behaviour you observe. Similarly if I write f1(x) = x ; typeof(f1), that will also return typeof(f1).
Anonymous functions are a bit more tricky, since they are not named as such. What should we do for typeof(x -> x^2)? What actually happens is that when you build an anonymous function, it is stored as a temporary global variable in the module Main, and given a number that serves as its type for lookup purposes. So if you write f = (x -> x^2), you'll get something back like #3 (generic function with 1 method), and typeof(f) will return something like getfield(Main, Symbol("##3#4")), where you can see that Symbol("##3#4") is the temporary type of this anonymous function stored in Main. (a side effect of this is that if you write code that keeps arbitrarily generating the same anonymous function over and over you will eventually overflow memory, since they are all actually being stored as separate global variables of their own type - however, this does not prevent you from doing something like this for n = 1:largenumber ; findall(y -> y > 1.0, x) ; end inside a function, since in this case the anonymous function is only compiled once at compile-time).
Relating all of this back to the Function supertype, you'll note that typeof(sum) <: Function returns true, showing that the type of sum, aka typeof(sum) is indeed a subtype of Function. And note also that typeof(typeof(sum)) returns DataType, in much the same way that typeof(typeof(1.0)) returns DataType, which shows how sum actually behaves like a value.
Now, given everything I've said, all the examples in your question now make sense. typeof(function) and typeof(for) return errors as they should, since function and for are reserved syntax. typeof(typeof) and typeof(in) correctly return (respectively) typeof(typeof), and typeof(in), since typeof and in are both functions. Note of course that typeof(typeof(typeof)) returns DataType.
The Julia documentation says:
A primitive type is a concrete type whose data consists of plain old
bits. Classic examples of primitive types are integers and
floating-point values. Unlike most languages, Julia lets you declare
your own primitive types, rather than providing only a fixed set of
built-in ones. In fact, the standard primitive types are all defined
in the language itself:
I'm unable to find an example of how to do this, though, either in the docs or in the source code or anywhere else. What I'm looking for is an example of how to declare a primitive type, and how to subsequently implement a function or method on that type that works by manipulating those bits.
Is anyone able to point me towards an example? Thanks.
Edit: It's clear how to declare a primitive type, as there are examples immediately below the above quote in the doc. I'm hoping for information about how to subsequently manipulate them. For example, say I wanted to (pointlessly) implement my own primitive type MyInt8. I could declare that with primitive type MyInt8 <: Signed 8 end. But how would I subsequently implement a function myplus that manipulated the bits within Myint8?
PS in case it helps, the reason I'm asking is not because I need to do anything specific in Julia; I'm designing my own language for fun, and am researching how other languages implement various things.
# Declare the new type.
primitive type MyInt8 <: Signed 8 end
# A constructor to create values of the type MyInt8.
MyInt8(x :: Int8) = reinterpret(MyInt8, x)
# A constructor to convert back.
Int8(x :: MyInt8) = reinterpret(Int8, x)
# This allows the REPL to show values of type MyInt8.
Base.show(io :: IO, x :: MyInt8) = print(io, Int8(x))
# Declare an operator for the new type.
import Base: +
+ (a :: MyInt8, b :: MyInt8) = MyInt8(Int8(a) + Int8(b))
The key function here is reinterpret. It allows the bit representation of an Int8 to be treated as the new type.
To store a value with a custom bit layout, inside the MyInt8 constructor, you could perform any of the standard bit manipulation functions on the Int8 before 'reinterpreting' them as a MyInt8.
I've got a symbol that represents the name of a function to be called:
julia> func_sym = :tanh
I can use that symbol to get the tanh function and call it using:
julia> eval(func_sym)(2)
0.9640275800758169
But I'd rather avoid the 'eval' there as it will be called many times and it's expensive (and func_sym can have several different values depending on context).
IIRC in Ruby you can say something like:
obj.send(func_sym, args)
Is there something similar in Julia?
EDIT: some more details on why I have functions represented by symbols:
I have a type (from a neural network) that includes the activation function, originally I included it as a funcion:
type NeuralLayer
weights::Matrix{Float32}
biases::Vector{Float32}
a_func::Function
end
However, I needed to serialize these things to files using JLD, but it's not possible to serialize a Function, so I went with a symbol:
type NeuralLayer
weights::Matrix{Float32}
biases::Vector{Float32}
a_func::Symbol
end
And currently I use the eval approach above to call the activation function. There are collections of NeuralLayers and each can have it's own activation function.
#Isaiah's answer is spot-on; perhaps even more-so after the edit to the original question. To elaborate and make this more specific to your case: I'd change your NeuralLayer type to be parametric:
type NeuralLayer{func_type}
weights::Matrix{Float32}
biases::Vector{Float32}
end
Since func_type doesn't appear in the types of the fields, the constructor will require you to explicitly specify it: layer = NeuralLayer{:excitatory}(w, b). One restriction here is that you cannot modify a type parameter.
Now, func_type could be a symbol (like you're doing now) or it could be a more functionally relevant parameter (or parameters) that tunes your activation function. Then you define your activation functions like this:
# If you define your NeuralLayer with just one parameter:
activation(layer::NeuralLayer{:inhibitory}) = …
activation(layer::NeuralLayer{:excitatory}) = …
# Or if you want to use several physiological parameters instead:
activation{g_K,g_Na,g_l}(layer::NeuralLayer{g_K,g_Na,g_l} = f(g_K, g_Na, g_l)
The key point is that functions and behavior are external to the data. Use type definitions and abstract type hierarchies to define behavior, as is coded in the external functions… but only store data itself in the types. This is dramatically different from Python or other strongly object-oriented paradigms, and it takes some getting used to.
But I'd rather avoid the 'eval' there as it will be called many times and it's expensive (and func_sym can have several different values depending on context).
This sort of dynamic dispatch is possible in Julia, but not recommended. Changing the value of 'func_sym' based on context defeats type inference as well as method specialization and inlining. Instead, the recommended approach is to use multiple dispatch, as detailed in the Methods section of the manual.