Sqlite - Calculation of time period - sqlite

I need to calculate the time between a 'fixed' time (usually a few days ago) and now.
Therefore I have googled me to this sql (http://www.sqlite.org/lang_datefunc.html):
SELECT strftime ('%s', '1423143532') - strftime ('%s', 'now') as timediff;
It gives a weird result (122747310831610), and I have no idea why !? :-/
Should I use a different method of calculation, is that where the problem is? If yes, which one would give me the correct result? :)

A bare number is interpreted as a Julian day number:
> SELECT datetime('1423143532');
3891722-46318118-31 12:00:00
> SELECT datetime(2457064);
2015-02-10 12:00:00
To interpret a number as the number of seconds since 1970, you must use the unixepoch modifier:
> SELECT datetime(1423143532, 'unixepoch');
2015-02-05 13:38:52
> SELECT strftime ('%s', 1423143532, 'unixepoch');
1423143532
As you can see, passing this number through strftime is pointless. Just use it directly:
> SELECT 1423143532 - strftime('%s', 'now') as timediff;
-436916

Related

How do i subtract time from datetime in snowflake?

pdt.startTime is datetime
s_first.FromTimeOfDay is a time
I want to subtract the time drom the datetime. When i run the code below, Snowflake gives me this error invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
select (pdt.StartTime - (SELECT s_first.FromTimeOfDay::datetime FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
When i try this:
select (pdt.StartTime::TIMESTAMP_NTZ(9) - (SELECT s_first.FromTimeOfDay::TIMESTAMP_NTZ(9) FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
I get more or less the same error: invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
How do I convert the time into a datetime format so that I can subtract the two. It doesnt seem to me that there is a clear way to convert time into datetime in snowflake.
Is this what you're after?
select current_timestamp() as sample_timestamp
, time(sample_timestamp) as sample_time
, date(sample_timestamp) as sample_date;
A user pointed me in the right direction. i didnt realize i could use "dateadd" to also subtract time.
dateadd(HOUR, - (HOUR(current_timestamp())), temp.DateTime)

Sqlite SELECT * for Last 30 days

I have a SQLite DB with the following columns:
File, Date_created, Owner
How do I get the list of files created in the last 30 days?
I tried the following, but it didn't limit the result. The list came back with files created 2 years ago!
SELECT * FROM Table1 WHERE Date_created > (SELECT DATETIME('now', '-30 day'))
Also, not sure if it matters, but my Created_date column is in the following date format: dd/mm/yyyy hh:mm:ss
SQLite doesn't have a native datetime data type, so that comparison's going to be on text. If your records are in DD/MM/YYYY format, you'll end up with comparisons like "07/03/2020" > "2020-06-07" which make little sense.
If you opt to store your datetimes as text, you must use a format that's lexicographically orderable. A great standard format that exhibits this property (if every piece of data has the same timezone, anyway) is ISO 8601, e.g. 2020-07-07 15:04:14+0300 at the time of writing in my timezone. As an aside, even xkcd recommends ISO 8601.
If you opt to store your datetimes as numbers, you can store them as either UNIX time, or maybe, if you're feeling adventurous, as e.g. the number 20200707150414. Do remember neither of these numeric options store timezone information, if that's important to your application.
As an aside,
SELECT * FROM Table1 WHERE Date_created > DATETIME('now', '-30 day')
is enough :)
Something like this might be what you are looking for, it's something that's come up in my head, haven't tested it.
Basically you're going 30 days backwards by Date_created.
SELECT * FROM Table1
WHERE DATEDIFF(DAY, DATEADD(DAY, -30, GETDATE()), Date_created) > 0

how to do sec_to_time in SQLite?

I have a field with seconds after midnight, and I have to convert it to HH:MM:SS. MySQL has sec_to_time(), which would be perfect, but SQLite does not.
How to convert?
I feel like it's some combination of strftime or date, and some dividing by 3600, but I can't get it.
For example, I need to convert 3601 to 1:01. Or, 32405 -> 9:05.
Use time()
select time(3601, 'unixepoch');
will give:
01:00:01

Query between dates in SQLITE

I'm trying to query what happened between today and yesterday. To example on the 17th of June 2016 it would look like:
SELECT * FROM Inspection_Log WHERE date_time BETWEEN '2016-6-16' AND '2016-6-17'
But these days are relative, and this won't work say tomorrow, or really every again. So I've encountered this page where tells me now to use DATE as it's just a polite wrapper around strftime.
But here is my current issue:
This query works:
>SELECT COUNT(*) FROM Inspection_Log WHERE date_time BETWEEN '2016-6-16' AND '2016-6-17'
535
But when I use date('yada', '+1 day')
>SELECT COUNT(*) FROM Inspection_LOG WHERE date_time BETWEEN '2016-6-16' AND DATE('2016-6-16','+1 day')
0
So I try with strftime
>SELECT COUNT(*) FROM Inspection_LOG WHERE date_time BETWEEN '2016-6-16' AND strftime('%Y-%M-%D','2016-6-16','+1 day')
0
So I try with datetime
>SELECT COUNT(*) FROM Inspection_LOG WHERE date_time BETWEEN '2016-6-16' AND datetime('2016-6-16','+1 day')
0
Digging into this here is what i see
SELECT time('now')
'2016-06-24'
SELECT date('now')
'2016-06-24'
SELECT date('now','-1 day')
'2016-06-23'
SELECT date('2016-6-24','-1 day')
NONE
What am I doing wrong?
You need to change: AND strftime('%Y-%M-%D','2016-6-16','+1 day') for AND strftime('%Y-%m-%d','2016-06-16','+1 day').
1 - You should use '%Y-%m-%d' for the first parameter 'YYYY-MM-DD'.
The format string supports the most common substitutions found in the strftime() function from the standard C library plus two new substitutions, %f and %J. The complete list link
2 - A time string must be follow the format: YYYY-MM-DD, then you need to use '2016-06-16'.
There is a question and answer : SQL Select between dates
Okay so I was totally and completely wrong.
My scheme looks like this:
CREATE TABLE InspectionLog(
date_time DATE,
station_name TEXT,
inspection TEXT,
barcode_part_number TEXT,
bus_part_number TEXT,
barcode_serial_number TEXT,
bus_serial_number TEXT,
rework_operation TEXT,
status TEXT,
ng_description TEXT
)
DATE is not a valid data type. It is actually a high level wrapper around INTEGER and TEXT depending on the data placed into it. Sqlite3 defaults to TEXT.
What this means is when I perform an insert/update which does something similar to:
date_time = '2016-6-16'
This is valid as date_time is really TEXT not DATE. And when I preform a search that uses the DATE data type, it will skip any row which isn't a DATE.
The long version is. I inserted ~250MB incorrectly formatted into this table. After fixing my tests and functions so my inserts always have 2 day/month digits the majority of the OP's time queries work correctly.

Storing my dates as long (milliseconds) in SQLite: Can I use strftime(...)?

I'm storing my dates in SQLite in a column of data type INTEGER. I'm storing the milliseconds since 1970.
Eg:
date (long) other columns ...
-----------------------------------------
1407297600000 ...
1407211200000 ...
1407124800000 ...
My question is: how can I use strftime() under this circumstances?
If not, I should use TEXT as the column type??
Running this:
select strftime('%Y-%m', date) from my_table;
Is throwing nonesense stuff:
strftime('%Y-%m', date)
-----------------------------------------
1968-19
1968-19
1968-19
Unless you tell it otherwise, strftime() thinks those numbers are Julian day values - very different from Unix epoch milliseconds.
You'll want to convert to seconds, and tell strftime() these are Unix epoch numbers:
select strftime('%Y-%m', date / 1000, 'unixepoch');
See the Modifiers section in the SQLite Date and Time Functions docs.

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