Perhaps a little basic question, but is it possible to style elements of a table by classname in JavaFX. So for example like this:
MyClassname .table-view .column-header .label {
-fx-text-fill:#F00;
}
I want this to style multiple tables within 1 stylesheet.
thanks in advance
Yes, styling based upon class name selectors is supported - it's based on Node.getTypeSelector(), which comes from the Styleable interface.
The type of this Styleable that is to be used in selector matching. This is analogous to an "element" in HTML. (CSS Type Selector).
Returns: getClass().getName() without the package name
So you could style all Labels to have a green text fill using the CSS rule:
Label { -fx-text-fill: forestgreen; }
Most nodes also have style classes which are set on them by the application or, if it is a standard control, by the JavaFX framework. The standard way most people code is not to use the type selectors but to use style class selectors instead:
.label { -fx-text-fill: forestgreen; }
The type selector information is documented in the JavaFX CSS reference guide:
Node's getTypeSelector method returns a String which is analogous to a CSS Type Selector. By default, this method returns the simple name of the class. Note that the simple name of an inner class or of an anonymous class may not be usable as a type selector. In such a case, this method should be overridden to return a meaningful value.
Specify the full path to your class from root.
.root MyClassname .table-view .column-header .label {
-fx-text-fill:#F00;
}
Related
To select all elements that start with the class name foo. I can use:
[class^="foo"] { }
What can I use to select a custom element that starts with foo.
Example:
<foo-bar>Hola</foo-bar>
<foo-bazz>Hola</foo-bazz>
I want to have a single selector for both elements.
You can't. The [...] selectors only work on attributes, not element types themselves.
What you can do though, as I'm sure you're already aware, is chain them all into one selectors group, but this will mean that you'll need to know the exact element names:
foo-bar,
foo-bazz {
...
}
Failing that, you can always just give them all a shared class or data-* attribute:
<foo-bar class="foo"></foo-bar>
<foo-bazz class="foo"></foo-bazz>
.foo {
...
}
I use the following CSS to change the font of some components which are placed on a custom JavaFX AnchorPane, defined as fx:root. But the font-size remains default.
* {
-fx-font-family : Arial;
}
.label, .textField, .textfield, .checkBox, .text{
-fx-font-size: 18;
}
I got that I should change them using the ids of all inner components but it's not a good idea, because it results in redundant code.
Then I got that applying it on the main style class, it will work. But the sad story is that * can't be overriden. (I have defined * selector in a global css class for my whole application.
Try .root instead of *.
For the font size, some of your class names are wrong. Try
.label, .text-field, .check-box, .text {
-fx-font-size: 18pt ;
}
Style classes are documents in the CSS Reference Guide
Note that Text nodes have empty style class, so you need to explicitly set the style class for your text nodes.
Is there a way you can have a CSS file with one class let say p.one{color:red;}
and apply it to different tags? is there a way i can get an example if this is possible?
with one class
That isn't a class. It is a rule-set with a selector consisting of a type selector and a class selector.
and apply it to different tags?
Don't specify the element type. Use a class selector by itself.
.one { color: red; }
Create a class with color name that will be easy to use.
.redText { color: red; }
I'm creating a span in my web page with dojo.create, and need to apply CSS to it. I can see how to apply a style to it in the dojo reference, but I'd rather apply it via the external stylesheet (there's quite a few attributes I need to set and I'd rather not do it inline).
So given the example code below, how would I apply the CSS for the printSpan class?
var node = dojo.create("span", {innerHTML:_text, id:"printSpan", class:"printSpan"}, map);
You can write this in your external stylesheet:
.printSpan { color: red; }
This is called the class selector.
By the way, your code should be:
{ innerHTML : _text, id : "printSpan", "class" : "printSpan" }
Notice the colon was inside the "class" string, though it should be outside and printSpan is a different string.
I have a window with two buttons.
I'd like to decorate each one with a different stylesheet. They both have different object names, of course, but it seems that only the generic QPushButton stylesheet selector works.
I tried:
QPushButton#myBtnObjectName1 {
/* style definitions */
}
QPushButton#myBtnObjectName2 {
/* style definitions */
}
Tried the same with replacing the # with a ., or having the #myBtnObjetNameX only. Nothing works. Just:
QPushButton {
/* style definitions */
}
Am I using a wrong syntax? Or is this simply impossible without deriving from QPushButton in code and using a separate class name for each?
To match instances using the objectName, you can also use the selector ^=. According to the standard:
[att^=val] Represents an element with the att attribute whose value
begins with the prefix "val".
Example in Qt:
QPushButton[objectName^="push"] { background-color: red; }
A QPushButton called pushButton would be matched, but not an object called pbt.
You can use "accessibleName" in Qt Designer for this.
And in qss stylesheet:
more universal:
[accessibleName="alert-error"] {
color: red;
}
or be more specific:
QPushButton[accessibleName="bigred"] {
background-color: red;
}
Ah yes, the "AccessibleName" in Qt Designer needs to be set too, not just "ObjectName"