I need to simple current week list from sale_detail and I am using
Sqlite ,but problem is that condition not work but I check that similer sqlite macth date if 2015-1-9 not equal to 2015-01-09 so may program generate this that sqlite is not compare what is the solution second Condition operator not working Please Help me !
SELECT sale.sale_id, sale_date, sale_type, sale_detail.Quantity, sale_status p_cate_name, p_cate_size, p_cate_price
FROM sale
JOIN sale_detail ON sale.sale_id = sale_detail.sale_id
JOIN p_category ON p_category.p_cate_id = sale_detail.category_id
WHERE sale.sale_date >= date('now', 'weekday 0','-7 days')
AND sale.sale_date <= date('now', 'weekday 0')
Related
I have two time stamps #starttimestamp and #endtimestamp. How to calculate number of working hours between these two
Working hours is defined below:
Mon- Thursday (9:00-17:00)
Friday (9:00-13:00)
Have to work in impala
think i found a better solution.
we will create a series of numbers using a large table. You can get a time dimension type table too. Make it doenst get truncated. I am using a large table from my db.
Use this series to generate a date range between start and end date.
date_add (t.start_date,rs.uniqueid) -- create range of dates
join (select row_number() over ( order by mycol) as uniqueid -- create range of unique ids
from largetab) rs
where end_date >=date_add (t.start_date,rs.uniqueid)
Then we will calculate total hour difference between the timestamp using unix timestamp considering date and time.
unix_timestamp(endtimestamp - starttimestamp )
Exclude non working hours like 16hours on M-T, 20hours on F, 24hours on S-S.
case when dayofweek ( dday) in (1,7) then 24
when dayofweek ( dday) =5 then 20
else 16 end as non work hours
Here is complete SQL.
select
end_date, start_date,
diff_in_hr - sum(case when dayofweek ( dday) in (1,7) then 24
when dayofweek ( dday) =5 then 20
else 16 end ) total_workhrs
from (
select (unix_timestamp(end_date)- unix_timestamp(start_date))/3600 as diff_in_hr , end_date, start_date,date_add (t.start_date,rs.uniqueid) as dDay
from tdate t
join (select row_number() over ( order by mycol) as uniqueid from largetab) rs
where end_date >=date_add (t.start_date,rs.uniqueid)
)rs2
group by 1,2,diff_in_hr
Thanks again for the help everyone. I went with the script below...
SELECT beginning, end,
(SELECT SUM(sale) FROM sales_log WHERE date BETWEEN beginning AND `end` ) AS sales
FROM performance
and I added a salesperson column to both the performance table and sales_log but it winds up crashing DB Browser. What is the issue here? New code below:
SELECT beginning, end, salesperson
(SELECT SUM(sale) FROM sales_log WHERE (date BETWEEN beginning AND end) AND sales_log.salesperson = performance.salesperson ) AS sales
FROM performance
I believe that the following may do what you wish or be the basis for what you wish.
WITH sales_log_cte AS
(
SELECT substr(date,(length(date) -3),4)||'-'||
CASE WHEN length(replace(substr(date,instr(date,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(date,instr(date,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(date,1,instr(date,'/') -1)) < 2 THEN '0' ELSE '' END||substr(date,1,instr(date,'/') -1) AS date,
CAST(sale AS REAL) AS sale
FROM sales_log
),
performance_cte AS
(
SELECT substr(beginning,(length(beginning) -3),4)||'-'||
CASE WHEN length(replace(substr(beginning,instr(beginning,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(beginning,instr(beginning,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(beginning,1,instr(beginning,'/') -1)) < 2 THEN '0' ELSE '' END||substr(beginning,1,instr(beginning,'/') -1)
AS beginning,
substr(`end`,(length(`end`) -3),4)||'-'||
CASE WHEN length(replace(substr(`end`,instr(`end`,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(`end`,instr(`end`,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(`end`,1,instr(`end`,'/') -1)) < 2 THEN '0' ELSE '' END||substr(`end`,1,instr(`end`,'/') -1)
AS `end`
FROM performance
)
SELECT beginning, `end` , (SELECT SUM(sale) FROM sales_log_cte WHERE date BETWEEN beginning AND `end` ) AS sales
FROM performance_cte
;
From your data this results in :-
As can be seen the bulk of the code is converting the dates into a format (i.e. YYYY-MM-DD) that is usable/recognisable by SQLite for the BETWEEN clause.
Date And Time Functions
I don't believe that you want a join between performance (preformance_cte after reformatting the dates) and sales_log (sales_log_cte) as this will be a cartesian product and then sum will sum all the results within the range.
The use of end as a column name is also awkward as it is a KEYWORD requiring it to be enclosed (` grave accents used in the above).
The above works by using 2 CTE's (Common Table Expresssions), which are temporary tables who'd life time is for the query in which they are used.
The first sales_log_cte is simply the sales_log table but with the date reformatted. The second, likewise, is simply the performace table with the dates reformatted.
If the tables already has suitable date formatting then all of the above could simply be :-
SELECT beginning, `end` , (SELECT SUM(sale) FROM sales_log WHERE date BETWEEN beginning AND `end` ) AS sales FROM performance;
I am trying to get the equivalent of this query in SQL in SQLite
SELECT DATE_ADD(now(),INTERVAL (DAYOFWEEK(S.start_date)+1) DAY) AS pymtdate FROM subscriptions
The purpose of this is that I have a start date and a weekly payment. I want to calculate the weekly payments for the next N days (in the example above this is for one week) for a number of start dates. In SQLite the nearest I can get to is
SELECT date('now', 'weekday stftime('%w', S.start_date)') AS pymtdate FROM subscriptions
but this isn't working as it blows out when I try to combine the weekday with a calculated value.
Any suggestions?
I did find the answer using this post: sqlite return as day of week
SELECT S.subscription_id AS subid,
case cast (strftime('%w',S.start_date) as integer)
when 0 then date('now' , 'weekday 0')
when 1 then date('now' , 'weekday 1')
when 2 then date('now' , 'weekday 2')
when 3 then date('now' , 'weekday 3')
when 4 then date('now' , 'weekday 4')
when 5 then date('now' , 'weekday 5')
else date('now' , 'weekday 6') end as pymtdate
FROM subscriptions AS S
In SQL, anything 'between quotes' is a string.
You do not want the string strftime(...), you want to execute this function, so you must write it outside the quotes (and append its return value to the other string):
SELECT date('now', 'weekday ' || strftime('%w', S.start_date)) ...
I can't get the following query to work:
UPDATE ISSUE
SET DUE_DATE = DATE(ISSUE.DATE_ADDED,'+90 day')
JOIN CVE on CVE.CVE_ID = ISSUE.CVE_ID
WHERE CVE.CVSS >= 4 AND CVE.CVSS < 9
This is because in sqlite3 you can't join in an UPDATE. What I'm trying to do is set the due date of an issue to be 90 days after the date added if the CVE associated with the issue is: greater than or equal to four and less than 9. Is there an alternative option that I'm missing here?
You can join the rows in a sub-query.
UPDATE ISSUE
SET DUE_DATE = DATE(ISSUE.DATE_ADDED,'+90 day')
WHERE ISSUE.CVE_ID IN (
SELECT ISSUE.CVE_ID
FROM ISSUE JOIN CVE on CVE.CVE_ID = ISSUE.CVE_ID
WHERE CVE.CVSS >= 4 AND CVE.CVSS < 9
)
I have to implement a solution where two date ranges can overlap each other. within the overlapped dates, I have to count how many days overlap each other. Once I know the overlapped days I can calculate a total figure based on the price that's attached per day.
A scenario would be that
A customer is booking a hotel
Customer booking dates - 17/02/2011 to 26/02/2011
Normal price (All year) - 01/01/2011 - 31/12/2011 (price per day :$30.00)
Special Offer 1 dates - 01/01/2011 to 19/02/2011 (price per day :$20.00)
Special Offer 2 dates - 17/02/2011 to 24/02/2011 (price per day :$10.00)
In the above scenario, the proposed algorithm should work out the cheapest offer that the date ranges overlap and work out the price for the booking. If there is no special offer available it uses the normal price.
So for the first two days the system should get the price from "special offer 1" as it's the cheapest available price. Next 5 days should be "Special offer 2 price" and for the next 2 days it'll be normal price.
I'd be grateful to see both SQL(using MS-SQL Server) or Code base answers to get the diffrenet views.
I hope the question is clear and looking foward to see the answers.
Many thanks in advance
Using the standard trick of using an auxiliary calendar table, it is simply a case of joins and grouping to get the best price each day:
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
The same query as above, including sample data using CTEs:
WITH Prices (price_start_date, price_end_date, narrative, price)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date), narrative, price
FROM (
VALUES ('2011-01-01T00:00:00', '2011-12-31T00:00:00', 'Normal price', 30),
('2011-01-01T00:00:00', '2011-02-21T00:00:00', 'Special Offer 1', 20),
('2011-02-19T00:00:00', '2011-02-24T00:00:00', 'Special Offer 2', 10)
) AS T (start_date, end_date, narrative, price)
),
CustomerBooking (booking_start_date, booking_end_date)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date)
FROM (
VALUES ('2011-02-17T00:00:00', '2011-02-26T00:00:00')
) AS T (start_date, end_date)
)
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
Let's supose that for each day you should apply lowest price.
create function price ( #fromDate date, #toDate date) returns money
as
begin
declare #iterator_day date
declare #total money
set #total = 0
set #iterator_day = #fromDate
WHILE #iterator_day < = #toDate
begin
select #total = #total + min( price )
from offers
where #iterator_day between offers.fromFay and offers.toDay
set #iterator_day = DATEADD (day , 1 , #iterator_day )
end
return #total
end
then you can call function in your query:
select
b.fromDay, b.toDay, dbo.price( b.fromDay, b.toDay )
from
booking b
I've only used ASP.net 4.0, but I can offer some SQL will give you the price for a given date:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11')
From your application you could build the query to be something like this:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '17/2/11') AND (EndDate >= '17/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '19/2/11') AND (EndDate >= '19/2/11');
This would return a dataset of tables containing a single value for the minimum price for that date (in the same order as your query)
Sounds like a good job for a Stored Procedure...
Your problem here is that you're got multiple overlapping time periods. You either need to constrain the problem slightly, or remodel the data slightly. (To get desirable performance.)
Option 1 - Constraints
A data set of 'normal' prices - that never overlap with each other
A data set of 'special' prices - that also never overlap with each other
Every bookable date has a 'normal' price
Every bookable date has a 'special' price (EVEN if it's NULL to mean 'no special price')
The last constraint is the strangest one. But it's needed to make the simple join work. When comparing date ranges, it's alot easier to form the query if the two sets of ranges are gapless and have no overlaps inside them.
This means that you should now be able to work it out with just a few joins...
SELECT
CASE WHEN [sp].started > [np].started THEN [sp].started ELSE [np].started END AS [started]
CASE WHEN [sp].expired < [np].expired THEN [sp].expired ELSE [np].expired END AS [expired]
CASE WHEN [sp].price < [np].price THEN [sp].price ELSE [np].price END AS [price]
FROM
normal_prices AS [np]
LEFT JOIN
special_prices AS [sp]
ON [sp].started < [np].expired
AND [sp].expired > [np].started
AND [sp].started >= (SELECT ISNULL(MAX(started),0) FROM special_prices WHERE started <= [np].started)
-- The third condition is an optimisation for large data-sets.
WHERE
[np].started < #expired
AND [np].expired > #started
-- Note: Inclusive StartDates, Exlusive EndDate
-- For example, "all of Jan" would be "2011-01-01" to "2011-02-01"
Option 2 - Re-Model
This one is often the fastest in my experience; you increase the amount of space being used, and gain a simpler faster query...
Table Of Prices, stored by DAY rather than period...
- calendar_date
- price_code
- price
SELECT
calendar_date,
MIN(price)
FROM
prices
WHERE
calendar_date >= #started
AND calendar_date < #expired
Or, if you needed the price_code as well...
WITH
ordered_prices AS
(
SELECT
ROW_NUMBER() OVER (PARTITION BY calendar_date ORDER BY price ASC, price_code) AS price_rank,
*
FROM
prices
)
SELECT
calendar_date,
price_code,
price
FROM
ordered_prices
WHERE
calendar_date >= #started
AND calendar_date < #expired