I have two tables
table1- ---
file_id ,est_edit_id,cal_head_code,cal_spec_code,cal_item_head_code
table 2--
file_id ,est_edit_id,cal_head_code,cal_spec_code,cal_item_head_code,cal_item_code
i want to delete rows from table 2 that does not match values( file_id ,est_edit_id,cal_head_code,cal_spec_code,cal_item_head_code) in table 1
any help on the same
eg
table A contains
-----------
file_id |est_edit_id,| cal_head_code| cal_spec_code| cal_item_head_code
1 | 2 | 3 | 4 | 5
--
table B contains
file_id |est_edit_id ,| cal_head_code | cal_spec_code | cal_item_head_code |cal_item_code
1 | 2 | 3 | 4 | 5 | 20
1 | 2 | 3 | 4 | 5 | 50
7 | 8 | 9 | 10 | 11 |21
i want to delete row containg value 7 | 8 | 9 | 10 | 11 from table B because 7 | 8 | 9 | 10 | 11 is not present in table A
This should do it:
delete from table2 t2
where not exists (select 1
from table1 t1
where t1.file_id = t2.file_id
and t1.est_edit_id = t2.est_edit_id
and t1.cal_head_code = t2.cal_head_code
and t1.cal_spec_code = t2.cal_spec_code);
This assumes that none of the columns contain null values.
SQLFiddle example: http://sqlfiddle.com/#!15/e9e9b/1
Related
I have a database that I don't control the source of directly and results in errant '0' entries which mess up generated graphs with these drops to zero. I am able to manipulate the data after the fact and update that database.
It is acceptable that the last known good value can be used instead and so I am trying to make a general query that will remove all the zeros and populate it with the last known value.
Luckily, every entry includes the ID of the last entry and so it is a matter of simply looking back and grabbing it.
I have got very close to a final answer, but instead of updating with the last good value, it just uses the first value over and over again.
dummy data
CREATE TABLE tbl(id INT,r INT,oid INT);
INSERT INTO tbl VALUES(1,10,0);
INSERT INTO tbl VALUES(2,20,1);
INSERT INTO tbl VALUES(3,0,2);
INSERT INTO tbl VALUES(4,40,3);
INSERT INTO tbl VALUES(5,50,4);
INSERT INTO tbl VALUES(6,0,5);
INSERT INTO tbl VALUES(7,70,6);
INSERT INTO tbl VALUES(8,80,7);
SELECT * FROM tbl;
OUTPUT:
| id| r |oid|
|---|----|---|
| 1 | 10 | 0 |
| 2 | 20 | 1 |
| 3 | 0 | 2 | ** NEEDS FIXING
| 4 | 40 | 3 |
| 5 | 50 | 4 |
| 6 | 0 | 5 | ** NEEDS UPDATE
| 7 | 70 | 6 |
| 8 | 80 | 7 |
I have worked several queries to get results around what I am after:
All zero entries:
SELECT * FROM tbl WHERE r = 0;
OUTPUT:
| id | r | oid |
|----|----|-----|
| 3 | 0 | 2 |
| 6 | 0 | 5 |
Output only the those rows with the preceding good row
SELECT * FROM tbl WHERE A in (
SELECT id FROM tbl WHERE r = 0
UNION
SELECT oid FROM tbl WHERE r = 0
)
OUTPUT:
| id| r |oid|
|---|----|---|
| 2 | 20 | 1 |
| 3 | 0 | 2 |
| 5 | 50 | 4 |
| 6 | 0 | 5 |
Almost works
This is as close as I have got, it does change all the zero's, but it changes them all to the value of the first lookup
UPDATE tbl
SET r = (SELECT r
FROM tbl
WHERE id in (SELECT oid
FROM tbl
WHERE r = 0)
) WHERE r = 0 ;
OUTPUT:
| id| r |oid|
|---|----|---|
| 1 | 10 | 0 |
| 2 | 20 | 1 |
| 3 | 20 | 2 | ** GOOD
| 4 | 40 | 3 |
| 5 | 50 | 4 |
| 6 | 20 | 5 | ** BAD, should be 50
| 7 | 70 | 6 |
| 8 | 80 | 7 |
If it helps, I created this fiddle here that I've been playing with:
http://sqlfiddle.com/#!5/8afff/1
For this sample data all you have to do is use the correct correlated subquery that returns the value of r from the row with id equal to the current oid in the WHERE clause:
UPDATE tbl AS t
SET r = (SELECT tt.r FROM tbl tt WHERE tt.id = t.oid)
WHERE t.r = 0;
See the demo.
I have a SQLite table just like this:
the table name is 'surat'
But i want to make id_ayat to be split into different rows using SQLite query, and expected result just like this:
_id|id_surat|id_ayat
---+--------+-------
3 | 2 | 112
3 | 2 | 213
3 | 3 | 19
3 | 3 | 83
3 | 3 | 85
3 | 3 | 102
is that possible? what query that i can use in SQLite format?
With a recursive CTE:
with recursive cte as (
select _id, id_surat, id_ayat,
id_ayat + 0 col
from tablename
union all
select _id, id_surat, trim(substr(id_ayat, length(col) + 2)),
trim(substr(id_ayat, length(col) + 2)) + 0
from cte
where instr(id_ayat, ',')
)
select _id, id_surat, col id_ayat
from cte
order by _id, id_surat
See the demo.
Results:
| _id | id_surat | id_ayat |
| --- | -------- | ------- |
| 3 | 2 | 112 |
| 3 | 2 | 213 |
| 3 | 3 | 19 |
| 3 | 3 | 83 |
| 3 | 3 | 85 |
| 3 | 3 | 102 |
I have the following table in an sqlite database
+----+-------------+-------+
| ID | Week Number | Count |
+----+-------------+-------+
| 1 | 1 | 31 |
| 2 | 2 | 16 |
| 3 | 3 | 73 |
| 4 | 4 | 59 |
| 5 | 5 | 44 |
| 6 | 6 | 73 |
+----+-------------+-------+
I want to get the following table out. Where I get this weeks sales as one column and then the next column will be last weeks sales.
+-------------+-----------+-----------+
| Week Number | This_Week | Last_Week |
+-------------+-----------+-----------+
| 1 | 31 | null |
| 2 | 16 | 31 |
| 3 | 73 | 16 |
| 4 | 59 | 73 |
| 5 | 44 | 59 |
| 6 | 73 | 44 |
+-------------+-----------+-----------+
This is the select statement i was going to use:
select
id, week_number, count,
(select count from tempTable
where week_number = (week_number-1))
from
tempTable;
You are comparing values in two different rows. When you are just writing week_number, the database does not know which one you mean.
To refer to a column in a specific table, you have to prefix it with the table name: tempTable.week_number.
And if both tables have the same name, you have to rename at least one of them:
SELECT id,
week_number,
count AS This_Week,
(SELECT count
FROM tempTable AS T2
WHERE T2.week_number = tempTable.week_number - 1
) AS Last_Week
FROM tempTable;
In case of you want to take a query upon a same table twice, you have to put aliases on the original one and its replicated one to differentiate them
select a.week_number,a.count this_week,
(select b.count from tempTable b
where b.week_number=(a.week_number-1)) last_week
from tempTable a;
i have a dataset in sqlite db which has ids and image urls. It is as follows:
ID | URL
1 | http://img.url1.com
2 |
3 | http://img.url2.com
4 | http://img.url3.com
5 | http://img.url4.com
6 |
7 | http://img.url5.com
8 |
9 | http://img.url6.com
10 |
11 | http://img.url7.com
12 | http://img.url8.com
13 |
I want to sort this accordingly in such a way that the ids with blank values appears at the bottom and the ids with nearest with img urls get appeared at the top with nearest values in the sorted order of ids as follows:
ID | URL
1 | http://img.url1.com
3 | http://img.url2.com
4 | http://img.url3.com
5 | http://img.url4.com
7 | http://img.url5.com
9 | http://img.url6.com
11 | http://img.url7.com
12 | http://img.url8.com
2 |
6 |
8 |
10 |
13 |
Can you suggest me what kind of query I need to put ?
SELECT * FROM T
ORDER BY (URL IS NULL),id
SQLFiddle demo
I have one table 'positions' with columns:
id | session_id | keyword_id | position
and some rows in it:
10 rows with session_id = 1
and 10 with session_id = 2.
As a result of the query I need a table like this:
id | keyword_id | position1 | position2
where 'position1' is a column with values that had session_id = 1 and 'position2' is a column with values that had session_id = 2.
The result set should contain 10 records.
Sorry for my bad English.
Data examle:
id | session_id | keyword_id | position
1 | 1 | 1 | 2
2 | 1 | 2 | 3
3 | 1 | 3 | 0
4 | 1 | 4 | 18
5 | 2 | 5 | 9
6 | 2 | 1 | 0
7 | 2 | 2 | 14
8 | 2 | 3 | 2
9 | 2 | 4 | 8
10 | 2 | 5 | 19
Assuming that you wish to combine positions with the same id, from the two sessions, then the following query should to the trick:
SELECT T1.keyword_id
, T1.position as Position1
, T2.position as Position2
FROM positions T1
INNER JOIN positions T2
ON T1.keyword_id = T2.keyword_id -- this will match positions by [keyword_id]
AND T1.session_id = 1
AND T2.session_id = 2