I'm trying to make a container that has an upward arrow attached to it. I am familiar with the border drawing trick and think that's a likely solution, but it only works for known sizes I think, since you have to specify border in em or px.
The shape I would like to make is this:
.
/ \
/ \
/ \
| flex |
| |
Where the content area can flex to different sizes as a percentage of a parent container.
Here is the CSS, with the problem area flagged:
.metric {
display: inline-block;
position: relative;
height: 150px;
width: 50%;
background: lawngreen;
}
.metric:after {
position: absolute;
top: -25px;
left: 0;
content: '';
background: white;
width: 100%;
height: 0;
border: 75px solid white; /* this fixed width is the problem */
border-top: none;
border-bottom: 25px solid lawngreen;
box-sizing: border-box;
}
Here is the jsfiddle: http://jsfiddle.net/C8XJW/2/
Do you guys know any way to pull this off?
Here is another posibility.
This one does the trick with gradient backgrounds. You need 2 of them, so that the diagonal is easily achieved:
Relevant CSS:
.metric:before, .metric:after {
position: absolute;
top: -25px;
content: '';
width: 50%;
height: 25px;
}
.metric:before {
left: 0px;
background: linear-gradient(to right bottom, transparent 50%, lawngreen 50%);
}
.metric:after {
right: 0px;
background: linear-gradient(to left bottom, transparent 50%, lawngreen 50%);
}
Updated Fiddle
The differences with Simple As Could Be solution:
Pro Transparent corners (relevant if you have a background)
Con Worse browser support
Here's one great solution. Bascially, you make the arrow always centered, and bigger than you'd ever need it, but lop off the overflow.
Here's the JSFiddle:
http://jsfiddle.net/nBAK9/4/
And here's the interesting code:
.metric:after {
position: absolute;
top: 0;
left: 50%;
margin-left: -250px; /* max expected width /2 */
content: '';
background: white;
width: 500px; /* max expected width */
height: 0;
border: 250px solid white; /* max expected width /2 */
border-top: none;
border-bottom: 50px solid #cf6; /* This size adjusts the slope of the triangle */
box-sizing: border-box;
}
Not sure you can, I played with it found that since em inherits from parents you can play a bit with it.
body{
font-size: 3em;
}
div {
width: 0;
height: 0;
border-style: solid;
border-width: 0 3em 4em 7em;
border-color: transparent transparent #007bff transparent;
-webkit-transform:rotate(360deg)
}
Fiddle
.top-arrow:before, .top-arrow:after {
position: absolute;
top: -25px;
content: '';
width: 50%;
height: 25px;
}
.top-arrow:before {
left: 0px;
background: linear-gradient(to right bottom, transparent 50%, black 50%);
}
.top-arrow:after {
right: 0px;
background: linear-gradient(to left bottom, transparent 50%, black 50%);
}
<div class="top-arrow"></div>
Related
I am trying to produce a rectangle connected to a heavy-arrow (right facing) like the following:
(Link to image for those using SO dark theme)
I have attempted this by splitting the shape into parts. I have attempted drawing the rectangle first (and placing it in the same class as the arrow holder) then drawing the base of the arrow. Finally, the head by using rotation and transparency. In my current version of the CSS code can't seem to move the arrow head outside the rectangle to resemble the one shown in the image above. I have been trying to achieve this by tweaking the parameters and trying different CSS properties. Please suggest solutions and approaches.
body {
height: 100%;
width: 100%;
background-color: black;
overflow: hidden;
}
/* Arrow holder */
.arrowed {
position: relative;
height: 200px;
width: 200px;
margin: 0 20px 20px 0;
border: 1px solid rgba(0, 0, 0, 0.25);
}
.arrowed div {
float: right;
top: 0;
bottom: 0;
left: 18;
right: 0;
margin: auto;
}
.arrow-5 {
/* more triangle */
position: relative;
height: 22px;
width: 35px;
border: 30px solid;
border-color: white white transparent transparent;
transform: rotate(45deg);
}
.arrow-5:before {
content: '';
position: absolute;
top: 0px;
right: 0px;
display: block;
height: 54px;
width: 58px;
background-color: white;
transform: rotate(-45deg) translate(10px, 1px);
}
.rectangle {
width: 200px;
height: 100px;
background: blue;
}
<div class="arrowed rectangle">
<div class="arrow-5"></div>
</div>
You can draw block with arrow on the right by using pseudo elements.
In this example I'm using CSS variables to easelly control sizes and gaps. If it's impossible to use for some reason, you can replace it manually and use this Code Snippet like an generator.
This approach also support shadows, if needed.
/* root variables */
:root {
--space: 1rem;
--bg-color: #47baffb3;
}
/* main block bg color and part between of block and arrow */
.arrow-block,
.arrow-block:before {
background-color: var(--bg-color);
}
/* arrow block (text container) */
.arrow-block {
position: relative;
padding: var(--space);
margin-right: calc(var(--space) * 3);
filter: drop-shadow(0 0 .5rem rgba(0, 0, 0, .6));
}
/* arrow parts */
.arrow-block:before,
.arrow-block:after {
content: '';
position: absolute;
top: 50%;
transform: translate3d(0, -50%, 0);
}
/* part between block and arrow */
.arrow-block:before {
height: calc(var(--space) * 2);
width: var(--space);
right: calc(var(--space) * -1);
}
/* arrow itself */
.arrow-block:after {
--arrow-side-size: calc(var(--space) * 2);
border-bottom: var(--arrow-side-size) solid transparent;
border-top: var(--arrow-side-size) solid transparent;
border-left: var(--arrow-side-size) solid var(--bg-color);
right: calc(var(--space) * -3);
}
<div class="arrow-block">
<p>Block with arrow</p>
<p>Block with arrow second line</p>
</div>
Sometimes images just explain things better than 1000 words
assumed the black border is my image I want to cut off the top left/right edge - like marked by the red lines.
Would it be possible (if yes: how) to cut an image this way with CSS?
Just in case its not clear what I mean by cut: I want
By cut I mean, that the image will look like this
Without using a wrapper element, you can use clip-path, though the support isn't great.
img.cut {
-webkit-clip-path: polygon(50px 0, calc(100% - 50px) 0, 100% 50px, 100% 100%, 0 100%, 0 50px);
clip-path: polygon(50px 0, calc(100% - 50px) 0, 100% 50px, 100% 100%, 0 100%, 0 50px);
}
<img class="cut" src="http://lorempixel.com/200/300/">
This uses calc (widely supported), so you can specify exact pixel values to clip by.
CSS Pseudo
If you know you're background is going to remain a solid colour, you can achieve this using pseudo elements in a number of ways.
1st option
A very simple solution is to use the pseudo elements with borders to which should get you the effect you want.
div {
height: 300px;
background: red;
position: relative;
}
div:before {
content: '';
position: absolute;
top: 0;
left: 0;
border-top: 80px solid white;
border-right: 80px solid red;
width: 0;
}
div:after {
content: '';
position: absolute;
top: 0;
right: 0;
border-top: 80px solid white;
border-left: 80px solid red;
width: 0;
}
<div></div>
2nd Option
Using a single pseudo element which is larger than the parent and rotating it to get the desired effect.
This is a much cleaner effect and also means the use of background images is supported and easier to implement.
div {
height: 200px;
width: 200px;
background: transparent;
position: relative;
z-index: 9;
overflow: hidden;
}
div:before {
content: '';
width: 200%;
height: 200%;
position: absolute;
transform: rotate(45deg);
background: red;
left: -50%;
top: 20px;
<div></div>
So I know how to do a basic box shadow with CSS3. You can see that in the top of the graphic below.
The effect I'm trying to achieve is a 3D box shadow, as shown in the bottom of the graphic below.
Any ideas on how to do this with CSS3 box shadows?
Unfortunately box shadows are effectively just flat layers. However you can apply multiple box shadows to create this effect.
.box-shadow-3d{
box-shadow: 1px 1px 0px #999,
2px 2px 0px #999,
3px 3px 0px #999,
4px 4px 0px #999,
5px 5px 0px #999,
6px 6px 0px #999;
}
you can use pseudo element for as shadow
div {
background: black;
height: 100px;
width: 100px;
position: relative;
}
div:after,
div:before {
content: '';
background: grey;
position: absolute;
}
div:after {
width: 100%;
height: 20px;
left: 10px;
bottom: 0;
transform: translatey(100%) skewx(45deg);
}
div:before {
width: 20px;
height: 100%;
right: 0;
transform: translatex(100%) skewy(45deg);
top: 10px;
}
<div></div>
Here is a real 3D shadow using perspective and pseudo-element :before.
body {
background: lightblue;
}
.foo {
position: relative;
display: inline-block;
-webkit-perspective: 1000px;
-moz-perspective: 1000px;
persepctive: 1000px;
margin: 20px;
margin-top: 50px;
}
.foo .box {
transform: rotateY(-40deg);
height: 350px;
width: 250px;
background-color: black;
}
.foo:before {
content: "";
top: -15px;
position: absolute;
width: 50px;
height: 375px;
background-color: grey;
transform: translateX(215px) translateY(2.7px) rotateY(55deg)
}
<div class="foo">
<div class="box"></div>
</div>
You can stack the horizontal/vertical offsets of several box-shadows, each slightly bigger than the previous one. The more shadows you add, the more pronounced the effect. Here is a fiddle example.
div {
background: black;
height: 100px;
width: 100px;
box-shadow: 0 01px gray,
01px 0 gray,
01px 02px gray,
02px 01px gray,
02px 03px gray,
03px 02px gray,
03px 04px gray,
04px 03px gray,
04px 05px gray,
05px 04px gray,
05px 06px gray,
06px 05px gray;
}
I had some problems with these two options, so I adapted some diagonal gradients from Lea Verou's excellent book CSS Secrets. I thought about creating a gradient inside a right and bottom border via border-image, but that property does not allow edge targeting, à la border-right-image, etc.
So, I settled on using a pseudo element with two truncated corners, which seems to work pretty well. You have to be careful to adjust the width of the gradient to be 1.414 the size of half the padding, since this would be the diagonal of a square (square root of two). Also, since that's a pseudo element, be careful of the right placement. Interested to hear what you folks think.
div {
background: #bbb;
padding: 1em 1.2em;
width: 50%;
margin: 0 auto;
color: #111;
font: 150%/1.2 Georgia, Palatino, Times, serif;
position: relative;
}
div:after {
content:" ";
position:absolute;
top:0;
left: 0;
width:100%;
height:100%;
padding: 1.42em; /* (square root of gradient position) */
background: #000; /* Fallback if not supported */
background: linear-gradient(-135deg, transparent 2em, #000 0) top right,
linear-gradient(#000, #000) padding-box bottom right,
linear-gradient(45deg, transparent 2em, #000 0) bottom left;
/*I have avoided adding -webkit-, -moz and -0 prefixs for linear-gradient. You may put them in later to be extra safe*/
background-size: 50% 50%; /* There is no reason to paint the upper left quadrant, so I didn't. */
background-repeat: no-repeat;
-webkit-box-sizing: content-box; -moz-box-sizing: content-box; box-sizing: content-box;
/* Many people use border-box as default these days. Unfortunately, the box cannot be sized using border-box settings with the combination of padding in ems and percentages. So this is reset to content-box, just in case. */
z-index: -1; /* To keep the shadow behind the div*/
<div>This is a short sentence to demonstrate that our little div is responsive.</div>
Here's a little implementation, inspired by #Vitorino fernandes, in stylus...
offset = 10
border = 3
.offsetbox
margin offset
padding offset
text-align center
box-shadow inset 0 0 0 unit(border,px) black
background white
display inline-block
position relative
&:after,
&:before
content ''
background black
position absolute
&:after
width 100%
height offset
transform translatey(100%) skewx(-45deg)
right (offset/2)
bottom 0
&:before
height 100%
width offset
transform: translatex(-100%) skewy(-45deg)
left 0
top (offset/2)
I added some clip paths to #Vittorino fernandes code, to avoid white space between pseudos and make it sharper.
I added some 1px adjustments to avoid bad svg rendering problems.
You can use the variable called shadow-dimension to set the shadow width and height.
I Put it on a codePen:
https://codepen.io/silviamalavasi/pen/XWqeWEq
:root {
--shadow-dimension: 20px;
--blue: #0039a6;
}
.box-container {
position: relative;
}
.box-container>div {
border: 2px solid var(--blue);
}
.box-container>div:after, .box-container>div:before {
content: '';
background-color: var(--blue);
position: absolute;
}
.box-container>div:before {
width: calc(var(--shadow-dimension) + 1px);
height: calc(100% + 100px + 1px);
left: calc(var(--shadow-dimension) * -1);
transform: skewy(-45deg);
top: calc(0.5*var(--shadow-dimension));
clip-path: polygon(0% 0%, 100% 0%, 100% calc(100% - 100px - 2px + var(--shadow-dimension)), 0% calc(100% - 100px - 2px));
}
.box-container>div:after {
width: calc(100% + 100px);
height: calc(var(--shadow-dimension) + 1px);
left: calc(-0.5*var(--shadow-dimension) - 100px);
bottom: 1px;
transform: translateY(100%) skewx(-45deg);
clip-path: polygon(100px 0%, 100% 0%, 100% 100%, calc(100px + 2px) 100%);
}
I'm not sure what is specific name for this shape but can I just called it "half Parallelogram" ? I want make this shape purely using CSS/CSS3. Any help? or tutorial?
You can do it using pseudo-elements like below. The approach is to cut out a triangle shape from the left-bottom and top-right of the box. This method can be used with either a solid color an image inside the shape as long as the body background is a solid color. When the body background is a non-solid color this approach will not work because the border hack needs a solid color background.
The advantage of this method is that it can support cuts of different angles at each side (like in the question where the hypotenuse of the triangular cut on either side are not parallel to each other).
div {
background: red;
width: 200px;
height: 100px;
position: relative;
}
div:before {
position: absolute;
height: 0;
width: 0;
content: ' ';
border: 20px solid white;
border-color: transparent transparent white white;
border-width: 20px 0px 0px 15px;
left: 0;
top: 80px;
}
div:after {
position: absolute;
height: 0;
width: 0;
content: ' ';
border: 20px solid white;
border-color: white white transparent transparent;
left: 170px;
top: 0px;
}
.with-img {
background: url(http://lorempixel.com/100/100);
}
<div></div>
<br>
<div class="with-img"></div>
Sample 2: You can also achieve a similar effect using gradients. Just 1 gradient is enough to produce a cut of similar angle on both sides. If different angles are required then two gradients should be used. However the multiple gradient approach mentioned here will not work when the body background is a non-solid color.
div {
width: 200px;
height: 100px;
position: relative;
}
.with-single-gradient {
background: linear-gradient(45deg, transparent 5%, yellowgreen 5%, yellowgreen 90%, transparent 90.5%);
}
.with-single-gradient.image {
background: linear-gradient(45deg, white 5%, transparent 5%, transparent 90%, white 90.5%), url(http://lorempixel.com/100/100);
}
.with-multiple-gradient.image {
background: linear-gradient(45deg, transparent 0%, transparent 90%, white 90%), linear-gradient(60deg, white 10%, transparent 5%, transparent 100%), url(http://lorempixel.com/100/100);
}
<div class='with-single-gradient'></div>
<br>
<div class='with-single-gradient image'></div>
<br>
<div class='with-multiple-gradient image'></div>
Sample 3: This can also be created using SVG and is the best method yet. All that it requires is just a single path element which creates the required shape.
<svg viewBox='0 0 100 60' width='200px' height='120px'>
<path d='M0,0 80,0 100,16 100,60 10,60 0,54z' fill='yellowgreen' />
</svg>
Tested on Chrome v24, Firefox v19, Safari v5.1.7 (on Windows) and IE v10. They are older versions but should work in the latest versions also.
Note: IE versions less than 10 do not support gradients as mentioned in this SO thread.
there's no thing as straight radius, but here you have some tutorials. For weird shapes, you need to use a combination of shape and negative space, basically using figures with the same color of the background . The good news is you could use "transparent" as color, so you can "fake" this figures in an easy way. See tutorials Shapes of CSS or yuo can use a generator like CSS Shape Generator or CSS Shape Generator 2 but they will highly depend on your needs. Personally, I'd use a BG image and be a happy camper
to make this shape you have to use pseudo class.
and i hope it will help you
div { display: inline-block; margin: 20px; float: left; }
shape {
width: 208px;
height: 130px;
background: red;
position: relative; }
shape:before {
content: "";
position: absolute;
top: 0;
left: 0;
border-bottom: 29px solid red;
border-right: 29px solid #fff;
width: 179px;
height: 0; }
shape:after {
content: "";
position: absolute;
bottom: 0;
left: 0;
border-top: 29px solid red;
border-left: 29px solid #fff;
width: 42px;
height: 0; }
demo
2 gradients and background-size can be used too :
div {
width: 1440px;
height: 590px;
background:
linear-gradient(45deg, transparent 80px, #FF0000 80px) left no-repeat,
linear-gradient(-135deg, transparent 160px, #FF0000 160px) top right no-repeat;
background-size: 50% 100%;
}
<div>
</div>
1 gradients and calc() can be used too :
div {
width: 1440px;
height: 590px;
background:
linear-gradient(45deg, transparent 80px, #FF0000 80px, #FF0000 calc( 100% - 160px), transparent calc( 100% - 160px) );
}
<div>
</div>
Related to duplicate question https://stackoverflow.com/questions/36932294/how-can-i-create-the-object-in-picture-below-using-css-border-radius :
div {
width:980px;
height:460px;
background:linear-gradient(140deg,transparent 200px, #FFCB05 200px) left no-repeat,
linear-gradient(-40deg,transparent 80px, #FFCB05 80px) top right no-repeat;
background-size:50% 100% ;
}
<div>
div shape
</div>
image
<img src="http://i.stack.imgur.com/M48zP.png" />
For the second shape use this:
border-bottom-left-radius:50px;
border-top-right-radius:50px;
Check JSFiddle Demo
Edit:
Question is edited and second shape has been removed.
You can add an element with overflow: hidden;
skew transform the parent by desired angle. Unskew the pseudoelement by the negative of that angle.
Using this approach, you can also add images to background.
div {
height: 100px;
width: 220px;
overflow: hidden;
position: relative;
-webkit-transform: skewX(45deg);
-moz-transform: skewX(45deg);
transform: skewX(45deg);
}
div:before {
content: '';
position: absolute;
left: 10px;
height: 100px;
width: 200px;
background: red;
-webkit-transform: skewX(-45deg);
-moz-transform: skewX(-45deg);
transform: skewX(-45deg);
}
<div></div>
FIDDLE
FIDDLE (with image)
Through help on stackoverflow I've been able to generate and position a CSS triangle in the correct position on my website, I've also learnt how to color a triangle in 2 equal halves.
But I am stuck on merging the two examples together, what I've tried I don't think is worth pasting here due to the mess I've made of it.
I am trying to get a triangle that has the proportions and sits at the bottom of the div like this fiddle example and then is split in 2 colors like this fiddle example.
Where I believe I am going wrong is that in the different fiddles there are different uses of:
:before
Well..., Here is my attempt to achieve this effect (proportions + split in 2 colors):
JSFiddle Demo.
In this demo, I added the triangle to the .bottom div and positioned that to stay at the top (with a negative value).
Then added margin-top: 1%; property to move the triangle when resizing the window:
HTML
<div class="top"></div>
<div class="bottom">
<div class="triangle"></div>
</div>
CSS:
.top {
/* other styles... */
position: relative;
z-index: 2;
}
.bottom {
background: lightGreen;
height: 100px;
position: relative;
z-index: 1; /* A lower z-index value than .top */
/* Or use overflow: hidden; instead */
}
.triangle {
width: 40px;
height: 20px;
position: absolute;
left: 0;
right: 0;
top: -20px;
margin: auto;
margin-top: 1%; /* Move the triangle when resizing the window */
z-index: 1;
}
.triangle:before {
content: " ";
position: absolute;
width: 0;
height: 0;
border-style: solid;
border-width: 0 20px 20px 0;
border-color: transparent blue transparent transparent;
}
.triangle:after {
content: " ";
position: absolute;
left: 20px;
width: 0;
height: 0;
border-style: solid;
border-width: 20px 20px 0 0;
border-color: red transparent transparent transparent;
}