I am working on a site that uses three small images as links to twitter, facebook, etc. I have a callout image that I would like to appear when I mouse over the image.
The key here is that the callout image not interfere with the other images and text on the page.
Is there a handy solution that would meet this need?
not positive but it sounds like u can just assign the background image and use the background-position property to show the appropriate image during hover and non-hover state
a.twitter { display: block; width: 16px; height: 16px;
background: url(/images/twitter-hover.png) no-repeat 0 0; }
a.twitter:hover { background-position: 0 16px }
that's assuming a 16x32 sprite comprised of two 16x16 buttons (non-hover and hover) stacked vertically.
this is a rudimentary example http://www.dynamicsitesolutions.com/css/background-image-switching/
Old skool:
Combine the images into one and then use a client side imagemap with onmouseover events which make the appropriate divs visible.
New skool:
Use CSS hover psuedo class. Good example here: http://www.dynamicdrive.com/style/csslibrary/item/css-popup-image-viewer/ (won't work in all browsers)
Have you tried MooTools? They have a lot of Javascript utilities that might meet your requirements.
Related
I have noticed that Facebook and Instagram uses the same way of displaying icons found on the site, which is to add into a single PNG file all the icons and make the styling based on their position?
Please have a look on the Instagram way of doing it.
I understand that in this way, the client will receive only a single image which will be cached and the user performance will increase. But how do they do it?
Thank you for your time!
They do it by making a div or span or whatever, with a background of that image and then change the background position.
Example
.icons {
height:20px;
width: 20px;
background-image: url("path/to/image");
}
.icon1{
background-position: 0 0
}
.icon2{
background-position: 30px 0
}
JSFiddle: https://jsfiddle.net/qxjyycv2/
What you're looking for is Image Sprites.
The div you are displaying the image in (always as a background image) is set to overflow: hidden; while the background position changes to display the correct part of the sprite.
https://www.w3schools.com/css/css_image_sprites.asp
You can use this tool to generate CSS Sprites(one single png image) from your multiple images along with their css:
CSS SPRITE GENERATOR
I'm working with the Shape5.com Corporate Response Joomla template and been asked to make a change to the color of the four icons for social media in the upper right-hand corner. The demo of this template can be found here:
http://www.shape5.com/demo/corporate_response/
Their CSS for each icon looks like this from the template.css file. I'm just including the first icon to keep this brief, which is for RSS:
#s5_rss {
height:23px;
width:22px;
background:url(../images/rss.png) no-repeat top left;
cursor:pointer;
margin-left:8px;
float:right;
}
#s5_rss:hover {
background:url(../images/rss.png) no-repeat bottom left;
}
The rss.png is here:
http://www.shape5.com/demo/corporate_response/templates/corporate_response/images/rss.png
I've been asked to use CSS to change the active/hover color from what it is now to red. I'm not sure if this can be done with CSS or not. Can it? Or does this require a new .png file created with the image by the designer to be the desired red color?
I'd also like to understand why this rss.png file has two images of the icon inside of it at different shades and how does the CSS toggle between them to know which to use for hover? Is this a special .png file that allows this, perhaps in a different format than most .png files? Thanks!
The image is known as a sprite image: a single image file consisting of multiple sprites which you apply as a single background image, and position according to the constraints set by the width and height properties on an element. It's just a regular PNG image and is not intrinsically different from other PNG images.
As for actually changing the color of the image to red, that is not something you can do with CSS alone depending on what you mean by "changing the color" — the safest bet is to modify the image to add a new sprite with the desired color. Since it's just a regular PNG image it's a simple matter of extending the canvas another 23 pixels down, rendering the new sprite in the extra space that's created, and modifying your CSS so it looks like this:
#s5_rss:hover {
background:url(../images/rss.png) no-repeat center left;
}
#s5_rss:active {
background:url(../images/rss.png) no-repeat bottom left;
}
You can also replace the background:url(../images/rss.png) no-repeat portion with background-position: in your :hover and :active rules as you're really only modifying the background position when using a sprite in CSS:
#s5_rss:hover {
background-position:center left;
}
#s5_rss:active {
background-position:bottom left;
}
Experimental CSS filters are up around the horizon, but without good cross-browser support, you're basically out of luck on that front. If you can handle reduced browser support, go take a look at this overview of CSS filters.
Your current code shows only half the rss.png which conveniently is the exact height of just one of the sub-images within it. When you declare the background: you're telling it to stick the image from the top and hide the bottom half.
On hover, you're instructing it to draw just the bottom half of the image (the hovered state part). To make it a different color, you pretty much need to edit the file (short of having the background image partially transparent and showing a red background through it).
Overall, there's nothing magical going on, just well-documented magic that we all share and use every day.
Currently there is no way to change the colours within an image using css and likely there will either never be or a long way off. There is the potential to do a color overlay but this would not help unless the image you were dealing with was a block colour.
In order to change the color you will need a separate image to reference on the hover styling rule for that element.
The alternative way to do this is to use a sprite, where all the images are loaded as one image and css just focuses on a portion of it depending on the state ie hover, active etc. This is what you mentioned earlier. Have a look at the following links for information on using a sprite, but put simply if you have a 40*40px social icon. You would create a 40*80 image and then in css say use the top half for normal and the bottom for hover. This actually saves time when loading your page and you should always try and use sprites where ever possible, remember the faster the page the better for the user.
http://css-tricks.com/css-sprites/ (good guide on sprites)
http://spriteme.org/ (very handy and will do the work for you - recommended)
I'm having a big issue with something so "small" I can't figure it out and I'm reaching out to everyone here. The issue I'm having is this:
I have photos which are roughly 512px or 800px wide I want to fit, CENTERED, in a circle display area and keep my hover effects. I also need to size them the photos so the centered part shows a decent amount of the photo.
The current code I'm working with will make them perfect circles IF the photos are perfect squares. The problem is when the photo is a rectangle, it turns into an oval.
I had created a div like below using overflow:hidden and the css but it conflicted with the current CSS. Any help would be appreciated immensely!
.thumby {
width:200px;
margin: 0 auto;
overflow:hidden;
position: relative;
height: 200px;
border-radius: 100% 100% 100% 100%;
}
img.absolutely {
left: 50%;
margin-left: -256px;
top: 50%;
margin-top: -200px;
position:absolute;
width:512px;
}
Here's the link to my dev pages.
http://www.lmcodebox.com/b-test/index5.html
http://www.lmcodebox.com/b-test/portfolio.html
have you thought about setting the image as the background of the div? This way you keep all the effects you already use and there are ways to manipulate the background position without affecting the outside div. Other possible solution to have perfect round divs, is to use the ::after pseudo-class, like in this gallery tutorial:
http://webdesignerwall.com/tutorials/decorative-css-gallery-part-2
Sorry if I misunderstood you, hope it helps.
PS.: Beautiful test page by the way.
Well first, you'd only need to set the border radius to 50% to make something a circle, and if each corner is the same value, then you can just enter it once like so:
border-radius:50%;
As far as these images being rectangles goes, you could set your images as the background of a span, give it a height and a width that forms as square and use display block. This would keep the photos proportional, but allow you to make them square.
This however, could create a bit of a markup mess if you have a lot of images to display. Another solution, which means more work, but I would personaly do it, is to just crop your images into squares for their thumbnail with photoshop or some other image editing tool.
Above all of that, I don't see a width or height actually declared on the pages you linked. Are you sure you've placed them on the correct class? I see the border radius declared, but I'm only seeing a max-width: 100%; not width: 200px or height:200px
I re-thought the problem with the suggestion of using the images as backgrounds of an element as madaaah did above.
What I ended up doing was wrapping a DIV around my A tag like this:
then, I set the background of the A like this: style="background:url(PHOTO URL HERE) no-repeat;background-position:center;">
lastly, I made a square image (800 x 800) to go inside the A tag so it would keep the round shape and made it completely transparent so the background image is visible, while growing and shrinking in a "responsive" manner.
When using the like or send widget on a Fan Page (no mater if you use iframe tag or fbml for it) the overlay for commenting is positioned always to the right. see
http://twitpic.com/4q7ggi for example.
I cant find a way to get the widget to respect the 520px boundary of the facebook tab.
see http://www.facebook.com/pages/Ludwig-Test/127771653944246?sk=app_101150316644842 for an example.
Anyone an idea how to solve this ?
TIA
Rufinus
Try adding this to your css:
.fb_edge_comment_widget {
margin-left: -350px;
}
This will move comment box to the left, but the little arrow pointing to the button will move too (which you could try to cover with another element). It will only work if you're using XFBML, not an iframe.
Here's an example.
I had to move the little arrow to the bottom, and that's how i did it.
1) Move your popup window to the desired position. Use the !important statement to overwrite default styles.
.fb_edge_comment_widget {
top: -224px !important; left: -246px !important; height: 191px;
background: url(../img/arrow-down.gif) 0 100% no-repeat
}
This style also contains a new arrow image which replaces the bottom line of the popup window. It contains my own new bottom arrow, which is blue (#283E6C) by default and grey inside (#F2F2F2). We can use height to adjust the vertical position and move the background image to the bottom.
The image will look like this:
.
2) Apply overflow: hidden to the span that wraps the iframe, We'll be able to cut off parts of the iframe by applying margin-top in step 3, and replace them with our own.
.fb_edge_comment_widget > span {
height: 184px !important; overflow: hidden; border-top: 1px solid #000;
}
I'm using border-top to create my own upper border, since in step 3 we are cutting of the default border and arrow.
3) Move the iframe up a bit to cut off its upper border and arrow.
.fb_edge_comment_widget > span > iframe {
margin-top: -7px;
}
The result looks like this in my case:
If you're using the XFBML implementation of the Facebook Like button, you can use CSS to re-position the "flyout" menu relative to its original position near the Send button:
The above example using jsFiddle and this CSS:
.fb_edge_comment_widget {
margin-left: -343px;
}
Since the contents of the "flyout" are inside an iframe you won't be able to apply any CSS to it — meaning, moving the triangle indicator to the right side of the "flyout" isn't possible.
Web browsers have tightened security on cross-frame scripting due to spoofing and other hacks, so iframes are treated like separate HTML pages with their own CSS and JavaScript.
For any advanced CSS styling, you would have to inject the Facebook Widget's iframe using DOM Scripting ... and even then it may not work across browsers.
Not a great answer but the only option I have found is to wrap the widget in an absolutely positioned Div to keep it on the left side of the window
To fix it I strongly recommend to put the Facebook widget on the left side of your page. Any other solution could work for a certain period of time, but in the future will fail.
The reason is that Facebook updates its widget frequently.
I've used the div:hover CSS rule to achieve the desired affect - an image "swap" when the mouse hovers over a navigation image: www.scottmccarthydesign.com/dev.index.html
My setup here, however, is not actually a "swap." The main navigation image is a flattened jpeg of the entire desk (for faster loading), and there are empty divs over each item on the desk to map the image with links. When these empty divs are moused over, the div:hover rule fills the div with a .png that is meant to be placed precisely over the main desk image to give the effect of an image swap.
It works nicely in Firefox, but I do not understand why Safari is positioning the :hover image over the desk differently than Firefox is - each :hover image is about 1 pixel off, making it look like the seperate images on the desk are actually shifting a bit when moused over. Any suggestions??
I've had trouble using the :hover pseudo-class on elements other than <a></a>. You could use (jquery/javascript) to alter the class of the said <div> using onmouseover and onmouseout events.
With onmouseover, add a class that defines a certain background image. With onmouseout remove that class.
Even easier, use jquery .hover()
reposition your links after adding this to your css:
a div {
line-height: 0;
}
I've come across this issue before and found that it had to do with the size of the image. When the image is an odd-number pixel size on one of its dimensions, the calculations done by Firefox and Chrome/Safari (particularly when using center) are slightly different. Essentially, it has to do with sub-pixel rounding.
Simply add or subtract a pixel to your images on the axis that has an odd number length, to make them an even number (ie - instead of 100x123, make it 100x124) and you should be golden.
No need to use Javascript, this can certainly be achieved using just CSS. In my opinion, your best bet is to use the technique discussed in this article on CSS Sprites: http://www.alistapart.com/articles/sprites.
Essentially, for each item on your desk, place the hovered and non-hovered image in same image, one on top of each other, so that the top area has the non-hover state, and the bottom area has the hover state. Your code will probably look like this modified:
div#keyboard2 {
position: absolute;
left: 89px;
top: 256px;
width: 67px;
height: 160px;
background: url(../images/keyboard.png) 0 0 no-repeat;
}
#keyboard2:hover { background-position: 0 100%; }
Your desk image will then be empty, and of your items will just be on top of it.