I've used the div:hover CSS rule to achieve the desired affect - an image "swap" when the mouse hovers over a navigation image: www.scottmccarthydesign.com/dev.index.html
My setup here, however, is not actually a "swap." The main navigation image is a flattened jpeg of the entire desk (for faster loading), and there are empty divs over each item on the desk to map the image with links. When these empty divs are moused over, the div:hover rule fills the div with a .png that is meant to be placed precisely over the main desk image to give the effect of an image swap.
It works nicely in Firefox, but I do not understand why Safari is positioning the :hover image over the desk differently than Firefox is - each :hover image is about 1 pixel off, making it look like the seperate images on the desk are actually shifting a bit when moused over. Any suggestions??
I've had trouble using the :hover pseudo-class on elements other than <a></a>. You could use (jquery/javascript) to alter the class of the said <div> using onmouseover and onmouseout events.
With onmouseover, add a class that defines a certain background image. With onmouseout remove that class.
Even easier, use jquery .hover()
reposition your links after adding this to your css:
a div {
line-height: 0;
}
I've come across this issue before and found that it had to do with the size of the image. When the image is an odd-number pixel size on one of its dimensions, the calculations done by Firefox and Chrome/Safari (particularly when using center) are slightly different. Essentially, it has to do with sub-pixel rounding.
Simply add or subtract a pixel to your images on the axis that has an odd number length, to make them an even number (ie - instead of 100x123, make it 100x124) and you should be golden.
No need to use Javascript, this can certainly be achieved using just CSS. In my opinion, your best bet is to use the technique discussed in this article on CSS Sprites: http://www.alistapart.com/articles/sprites.
Essentially, for each item on your desk, place the hovered and non-hovered image in same image, one on top of each other, so that the top area has the non-hover state, and the bottom area has the hover state. Your code will probably look like this modified:
div#keyboard2 {
position: absolute;
left: 89px;
top: 256px;
width: 67px;
height: 160px;
background: url(../images/keyboard.png) 0 0 no-repeat;
}
#keyboard2:hover { background-position: 0 100%; }
Your desk image will then be empty, and of your items will just be on top of it.
Related
I'm having a big issue with something so "small" I can't figure it out and I'm reaching out to everyone here. The issue I'm having is this:
I have photos which are roughly 512px or 800px wide I want to fit, CENTERED, in a circle display area and keep my hover effects. I also need to size them the photos so the centered part shows a decent amount of the photo.
The current code I'm working with will make them perfect circles IF the photos are perfect squares. The problem is when the photo is a rectangle, it turns into an oval.
I had created a div like below using overflow:hidden and the css but it conflicted with the current CSS. Any help would be appreciated immensely!
.thumby {
width:200px;
margin: 0 auto;
overflow:hidden;
position: relative;
height: 200px;
border-radius: 100% 100% 100% 100%;
}
img.absolutely {
left: 50%;
margin-left: -256px;
top: 50%;
margin-top: -200px;
position:absolute;
width:512px;
}
Here's the link to my dev pages.
http://www.lmcodebox.com/b-test/index5.html
http://www.lmcodebox.com/b-test/portfolio.html
have you thought about setting the image as the background of the div? This way you keep all the effects you already use and there are ways to manipulate the background position without affecting the outside div. Other possible solution to have perfect round divs, is to use the ::after pseudo-class, like in this gallery tutorial:
http://webdesignerwall.com/tutorials/decorative-css-gallery-part-2
Sorry if I misunderstood you, hope it helps.
PS.: Beautiful test page by the way.
Well first, you'd only need to set the border radius to 50% to make something a circle, and if each corner is the same value, then you can just enter it once like so:
border-radius:50%;
As far as these images being rectangles goes, you could set your images as the background of a span, give it a height and a width that forms as square and use display block. This would keep the photos proportional, but allow you to make them square.
This however, could create a bit of a markup mess if you have a lot of images to display. Another solution, which means more work, but I would personaly do it, is to just crop your images into squares for their thumbnail with photoshop or some other image editing tool.
Above all of that, I don't see a width or height actually declared on the pages you linked. Are you sure you've placed them on the correct class? I see the border radius declared, but I'm only seeing a max-width: 100%; not width: 200px or height:200px
I re-thought the problem with the suggestion of using the images as backgrounds of an element as madaaah did above.
What I ended up doing was wrapping a DIV around my A tag like this:
then, I set the background of the A like this: style="background:url(PHOTO URL HERE) no-repeat;background-position:center;">
lastly, I made a square image (800 x 800) to go inside the A tag so it would keep the round shape and made it completely transparent so the background image is visible, while growing and shrinking in a "responsive" manner.
Consider a translucid background-image blocking the pointer-events of css links underneath it. I would like to make the links work even beneath this image.
Is it possible?
If one element overlaps another you can't click it, simple.
You can put the links on top of the overlay, but you will lose the effect on those links. It's not classy, but I guess it would work.
a {
position: relative; /* set them relative, keeping their position */
z-index: 1000; /* set z-index to move it in front */
}
Don't think so!
generally one of the oldest image theft methods was putting image behind a transparent image.
but if it is very important to you you can make hot spots on that image with some usual methods such as html image map or using some of the svg capabilities.
and if there is effects like shadow or something like this you can use css3 to make them with code
When using the like or send widget on a Fan Page (no mater if you use iframe tag or fbml for it) the overlay for commenting is positioned always to the right. see
http://twitpic.com/4q7ggi for example.
I cant find a way to get the widget to respect the 520px boundary of the facebook tab.
see http://www.facebook.com/pages/Ludwig-Test/127771653944246?sk=app_101150316644842 for an example.
Anyone an idea how to solve this ?
TIA
Rufinus
Try adding this to your css:
.fb_edge_comment_widget {
margin-left: -350px;
}
This will move comment box to the left, but the little arrow pointing to the button will move too (which you could try to cover with another element). It will only work if you're using XFBML, not an iframe.
Here's an example.
I had to move the little arrow to the bottom, and that's how i did it.
1) Move your popup window to the desired position. Use the !important statement to overwrite default styles.
.fb_edge_comment_widget {
top: -224px !important; left: -246px !important; height: 191px;
background: url(../img/arrow-down.gif) 0 100% no-repeat
}
This style also contains a new arrow image which replaces the bottom line of the popup window. It contains my own new bottom arrow, which is blue (#283E6C) by default and grey inside (#F2F2F2). We can use height to adjust the vertical position and move the background image to the bottom.
The image will look like this:
.
2) Apply overflow: hidden to the span that wraps the iframe, We'll be able to cut off parts of the iframe by applying margin-top in step 3, and replace them with our own.
.fb_edge_comment_widget > span {
height: 184px !important; overflow: hidden; border-top: 1px solid #000;
}
I'm using border-top to create my own upper border, since in step 3 we are cutting of the default border and arrow.
3) Move the iframe up a bit to cut off its upper border and arrow.
.fb_edge_comment_widget > span > iframe {
margin-top: -7px;
}
The result looks like this in my case:
If you're using the XFBML implementation of the Facebook Like button, you can use CSS to re-position the "flyout" menu relative to its original position near the Send button:
The above example using jsFiddle and this CSS:
.fb_edge_comment_widget {
margin-left: -343px;
}
Since the contents of the "flyout" are inside an iframe you won't be able to apply any CSS to it — meaning, moving the triangle indicator to the right side of the "flyout" isn't possible.
Web browsers have tightened security on cross-frame scripting due to spoofing and other hacks, so iframes are treated like separate HTML pages with their own CSS and JavaScript.
For any advanced CSS styling, you would have to inject the Facebook Widget's iframe using DOM Scripting ... and even then it may not work across browsers.
Not a great answer but the only option I have found is to wrap the widget in an absolutely positioned Div to keep it on the left side of the window
To fix it I strongly recommend to put the Facebook widget on the left side of your page. Any other solution could work for a certain period of time, but in the future will fail.
The reason is that Facebook updates its widget frequently.
when we define hover state of anything CSS... & on hover state we change the background:url('image path'); will this image be preloaded of will be download on the first hover of the element.. if that is so then how to preload it... i know the javascript to preload images.. is that going to work...
If you're trying to avoid having your hover state images only load they they're being hovered on, instead of preloading them, why not create sprites that hold both the normal and hover images ? That way you can be sure that all your hover state images will already be loaded, and at the same time drop the overhead for all the requests. The only thing that you would then need to do, is to set the value of the background-position attribute.
As for your first question, I suppose the best way of finding the answer is to use two large images (a couple of wallpapers would work) and test it yourself, although I suspect that the images will only be loaded when the mouse is over the original image, because that's when the code is being executed.
Hope this helps !
If you have a div of height 20px, say, and want a background image to change on hover, use an image with both the no-hover and hover graphics in it, with the no-hover at the top, and the hover image at the bottom. Both parts should be the hight of your div, in this case, 20px. Then, set your CSS background-position first to 0px 0px (top left). This is default (no hover).
When the user hovers over the div, set the background-position to 0px -20px (20px up). This will move the background image up by 20px, showing the bottom half of the sprite, which is the hover graphic. When the mouse is removed from the div, the sprite will fall back to it's original position.
CSS:
.hoverDiv /* Normal state */
{
background: url('images/img.png');
background-position: 0px 0px;
}
.hoverDiv:hover /* Hover state */
{
background-position: 0px -20px; /* Move background up by 20px, hiding the top image */
}
If you have a div of different height, just change the 20px bits with the height of the div.
If your sprites are side by side as opposed to on top of each other, move the X axis by using background-position: -20px 0px; instead of 0px -20px;. Of course, you can move the background positively too.
Hope this helps,
James
you could use css sprites
The best thing to do is use CSS Sprites. A sprite sheet is a large image with lots of images inside it, which will be used on your site. What's the benefit? Well, it means that only one http request is sent to download all of your images. Therefore, making the site load slightly faster.
It will really work well with a hover effect!
It's much easier to use plus simple code. Not like JavaScript, with messy horrible code. It's very easy to learn. Based around the position of the image in the sprite. Here's a useful tutorial, on Flowdev. Here's an example on W3Schools
I am working on a site that uses three small images as links to twitter, facebook, etc. I have a callout image that I would like to appear when I mouse over the image.
The key here is that the callout image not interfere with the other images and text on the page.
Is there a handy solution that would meet this need?
not positive but it sounds like u can just assign the background image and use the background-position property to show the appropriate image during hover and non-hover state
a.twitter { display: block; width: 16px; height: 16px;
background: url(/images/twitter-hover.png) no-repeat 0 0; }
a.twitter:hover { background-position: 0 16px }
that's assuming a 16x32 sprite comprised of two 16x16 buttons (non-hover and hover) stacked vertically.
this is a rudimentary example http://www.dynamicsitesolutions.com/css/background-image-switching/
Old skool:
Combine the images into one and then use a client side imagemap with onmouseover events which make the appropriate divs visible.
New skool:
Use CSS hover psuedo class. Good example here: http://www.dynamicdrive.com/style/csslibrary/item/css-popup-image-viewer/ (won't work in all browsers)
Have you tried MooTools? They have a lot of Javascript utilities that might meet your requirements.